PHP articles and images issue - php

Question

This is still not working, so I'm posting whole code here now...
<form id="contact-form" action="fileovi/dodaj_novost.php" method="post">
<fieldset>
<div class="coll-1">
<div class="txt-form">Naslov[hr]</div>
<label class="name">
<input type="text" name="naslov_hr">
<br>
</div>
<div class="clear"></div>
<div class="coll-1">
<div class="txt-form">Naslov[en]</div>
<label class="name">
<input type="text" name="naslov_en">
<br>
</div>
<div class="clear"></div>
<div class="clear"></div>
<div class="coll-1">
<div class="txt-form">Naslov[de]</div>
<label class="name">
<input type="text" name="naslov_de">
<br>
</div>
<div class="clear"></div>
<div class="clear"></div>
<div class="coll-1">
<div class="txt-form">Link slike</div>
<label class="name">
<input type="file" name="image[]" enctype="multipart/form-data"/><br />
<input type="file" name="image[]" enctype="multipart/form-data"/><br />
<br>
</div>
<div class="clear"></div>
<div class="clear"></div>
<div class="coll-big">
<div class="txt-form"><center>Tekst[hr]</center></div>
<label class="name">
<textarea id="tekst" name="tekst_hr"></textarea>
<br>
</div>
<div class="clear"></div>
<div class="coll-big">
<div class="txt-form"><center>Tekst[en]</center></div>
<label class="name">
<textarea id="tekst1" name="tekst_en"></textarea>
<br>
</div>
<div class="clear"></div>
<div class="coll-big">
<div class="txt-form"><center>Tekst[de]</center></div>
<label class="name">
<textarea id="tekst2" name="tekst_de"></textarea>
<br>
</div>
<div class="clear"></div>
Dodaj!
</form>
And here's my php function that I've created...
function dodaj_novost()
{
global $mysqli;
$mysqli->query("SET NAMES utf8");
$mysqli->query("SET CHARACTER SET utf8");
$mysqli->query("SET COLLATION_CONNECTION='utf8_general_ci'");
//sanitize variables
$naslovhr = $_POST['naslov_hr'];
$naslovhr = $mysqli->real_escape_string($naslovhr);
$nasloven = $_POST['naslov_en'];
$nasloven = $mysqli->real_escape_string($nasloven);
$naslovde = $_POST['naslov_de'];
$naslovde = $mysqli->real_escape_string($naslovde);
$teksthr = $_POST['tekst_hr'];
$teksthr = $mysqli->real_escape_string($teksthr);
$teksten = $_POST['tekst_en'];
$teksten = $mysqli->real_escape_string($teksten);
$tekstde = $_POST['tekst_de'];
$tekstde = $mysqli->real_escape_string($tekstde);
//sanitize variables END
$dan = date('d');
$mjesec = date('M');
$godina = date('Y');
$sql="INSERT INTO novosti (naslovhr, nasloven, naslovde, teksthr, teksten, tekstde, dan, mjesec, godina) VALUES ($naslovhr,$nasloven, $naslovde,$teksthr,$teksten,$tekstde,$dan,$mjesec,$godina)";
$query = $mysqli->query("$sql");
//Add picture!
$valid_exts = array('jpeg', 'jpg', 'png', 'gif'); // valid extensions
$max_size = 2048 * 1024; // max file size (200kb)
$path = 'uploads/'; // upload directory
if(isset($_FILES['image'])){
for($i=0; $i<count($_FILES['image']['name']); $i++){
if( #is_uploaded_file($_FILES['image']['tmp_name'][$i]) )
{
// get uploaded file extension
$ext = strtolower(pathinfo($_FILES['image']['name'][$i], PATHINFO_EXTENSION));
// looking for format and size validity
if (in_array($ext, $valid_exts) AND $_FILES['image']['size'][$i] < $max_size)
{
// unique file path
$filename = uniqid(). '.' .$ext;
// move uploaded file from temp to uploads directory
if (move_uploaded_file($_FILES['image']['tmp_name'][$i], $path.$filename))
{
$status = $path.$filename;
$link = 'http://'.$domena.'/'.$path.'/'.$filename;
$upit = "INSERT INTO slike_novosti (link, id_posta) VALUES ($link, $id_posta)";
$upit = $mysqli->query("$upit");
if ($upit == 'true'){
echo 'Successfull!';
} else {
echo 'Not sucessfull!';
}
}
else {
$status = 'Upload Fail: Unknown error occurred!';
}
}
else {
$status = 'Upload Fail: Unsupported file format or It is too large to upload!';
}
}
else{
//image is not uploaded!
$status = ' ';
}
echo '<br>'.$status.'<br>';
}
} else {
echo 'Nema slike!';
}
//Add picture END!!
}
And for some reason this code is still not working, If someone can point me in right direction on how to solve this problem.. I would be soo happy! :) Cheers.

Answer 1

At first:
$sql1 = "INSERT INTO slike_novosti (slika, link_slike) VALUES ('$link_slike','$slika')";
check order of your variables? I think, it must be:
$sql1 = "INSERT INTO slike_novosti (slika, link_slike) VALUES ('$slika','$link_slike')";
at second: Use PDO component, you have a very bad code and SQL Injection.

Answer 2

Remove the single qoutes from your $variables. For PHP '$var' is a variable with the value of $var. If you want them qouted, use "$var". See variables
So this wil work
$sql="INSERT INTO novosti (naslovhr, nasloven, naslovde, teksthr, teksten, tekstde,
link_slike, dan, mjesec, godina) VALUES
$naslovhr,$nasloven,$naslovde,$teksthr,
$teksten,$tekstde,$link_slike,$dan,$mjesec,$godina)";