Call specific variable based on what another variable is set to.(PHP) - php

I am not exactly sure how to word this in the form of a short question...the above called up many different answers that were not related, but I apologize if this has been asked before.
I am trying to make a variable name itself based the value of another.
I could simply create if statements for each one, but if I were able to declare the variable the way I want, it would save me about 20-30 lines of code, and make future additions much easier.
Here is a better description.
This is the code that I am using at the moment. It is within a shortcode function for wordpress, to create a button based on user-given parameters.
extract(shortcode_atts(array(
'size' => 'medium',
'link' => '#',
'text' => ''
), $atts));
$large_button_img = of_get_option('large_button_arrow_upload');
$button_pos = of_get_option('button_image_position');
if($button_pos == 'right' && !empty($button_img)){
$the_button = "<a href='" . $link . "' class='" . $size . "_button custom_button" . $button_pos ."'>" . $text . "<img src='" . $large_button_img . "' id='button_img' alt='button image' /></a>";
}elseif($button_pos == 'left' && !empty($button_img)){
$the_button = "<a href='" . $link . "' class='" . $size . "_button custom_button" . $button_pos ."'><img src='" . $large_button_img . "' id='button_img' alt='button image' />" . $text . "</a>";
}else
{
$the_button = "<a href='" . $link . "' class='" . $size . "_button custom_button'>" . $text . "</a>";
}
return $the_button;
In the above:
The function pulls the value of "size", "link" and "text" from the user given shortcode and generates a button. It sets the class based on the size...
At the moment I have it to where the user can set different images for a large, medium and small button.
Question:
IS IT POSSIBLE
to return the name of the image source based on what size is set to.
soooo basically the equivalent of?
img src = '" . $($size)_button_img . "'
Where it places value of $size in the name of the variable that it pulls to tell it which image source to pull afterwards? (so the proper equivalent of the above would produce something like
img src= '" . $large_button_img ."'
or, if the user has medium selected
img src= '" . $medium_button_img . "'
If possible this save myself having to write if-statements for every possible option (basically copy the set of if-ifelse-else from above, everytime I have a new size setting available)...which eventually may become more of an efficiency issue.
Thanks in advance for any help that can be given :)
ALSO
Please ignore any syntax errors in the above set of code...I am working on this as you read this, so more than likely, if you see something wrong, it has already been fixed.

You can simple use function for your logic:
function somethingWithImage($img, $pos) {
if ($pos == 'right' && !empty($button_img)) {
$the_button = "<a href='" . $link . "' class='" . $size . "_button custom_button" . $pos ."'>" . $text . "<img src='" . $img . "' id='button_img' alt='button image' /></a>";
} elseif ($pos == 'left' && !empty($button_img)) {
$the_button = "<a href='" . $link . "' class='" . $size . "_button custom_button" . $pos ."'><img src='" . $img . "' id='button_img' alt='button image' />" . $text . "</a>";
} else {
$the_button = "<a href='" . $link . "' class='" . $size . "_button custom_button'>" . $text . "</a>";
}
return $the_button;
}
And just call it whenever you want with any arguments.

What you are looking for, are variable variable names.
Short example:
$hello_text = 'Hello World!';
$bye_text = 'Goodbye World!';
$varname = 'hello';
echo ${$varname}_text; // Hello World!
// Is the same as:
echo $hello_text; // Hello World!

As I mentioned, you can use interpolation to create variable variables:
$src = ${"{$size}_button_img"};
But may I suggest using arrays instead? You get cleaner and understandable code:
$sizes = array(
'large' => ...,
'medium' => ...,
);
if(isset($sizes[$size]))
$src = $sizes[$size];

Related

Listing number of rows by group

I have a database with members joining and I am trying to display the number of members from each country.
Here is the code I'm using to show the country flags:
<?
foreach( $sorters as $sortvalue )
if( $sortvalue == '' )
echo '<li> <a href="' . $list_url . $connector . $sortfield .
'=none">None given</a> </li>';
else
echo '<a href="' . $list_url . $connector . $sortfield .
'=' . $sortvalue . '"><img src="' . $flags . str_replace(' ', '_', $sortvalue) . '.gif" title="' . $sortvalue . '" alt="' . $sortvalue . '"></a> ' . $countrynum . ' fans<br>';
}
?>
I have really looked for the answer, and keep seeing the same type of code, but I haven't been able to get it to work for me.
I've tried this:
$countrynum = SELECT COUNT(name) FROM $table WHERE country = $sortvalue;
which I inserted after the foreach statement. This (and every other iteration of this I've tried gives me Parse error: syntax error, unexpected 'COUNT' (T_STRING) in...
The closest I've come to solving this is by using this code (though, I shouldn't have to reconnect to the db should i?):
<?
foreach( $sorters as $sortvalue )
if( $sortvalue == '' )
echo '<li> <a href="' . $list_url . $connector . $sortfield .
'=none">None given</a> </li>';
else
$dbh = new PDO("mysql:host=$hostname;dbname=$db", $username, $password);
foreach($dbh->query('SELECT country, COUNT(*) FROM $table GROUP BY country') as $row) {
echo '<a href="' . $list_url . $connector . $sortfield .
'=' . $sortvalue . '"><img src="' . $flags . str_replace(' ', '_', $sortvalue) . '.gif" title="' . $sortvalue . '" alt="' . $sortvalue . '"></a> ' . $row['COUNT(*)'] . ' fans<br>';
}
?>
This gave me the correct row (member) count, but the same single flag was displayed beside each number instead of the corresponding flag with number of members.
I'm sure this is probably super simple for lots of you, but I'm a newbie who's really trying to learn coding and so far that mostly means cutting, pasting and LOTS of trial and error.
Any assistance (and learning resource suggestions) would be very much appreciated. :)
Since the flag image source is depending on$sorters and $sortvalue, it will be same for all country. Look at the loops. For each $sorters as $sortvalue, the link will be multiple countries but the img source will be same for all.

How would I add another column and populate it?

I know this is way out of left field, but i was wanting to see if anyone could help.
I am wanting to add a column, populating the data from a certain variable (the variable i have yet to discover the name of). This is a plugin for wordpress and the developer wont really help.
Last ditch effort i guess. Here is the code:
}$output.='><tr><th>' . __('Request For', 'wpsc-support-tickets') . '</th><th>'
. __('Status', 'wpsc-support-tickets') . '</th><th>'
. __('Last Reply', 'wpsc-support-tickets')
. '</th><th>' . __('Department', 'wpsc-support-tickets') . '</th></tr>';
I added the last column, "Department".
Now, looking at the following code, i cant figure out how to populate that data (assuming i knew the variable even)
$output .= '<tr><td>
<a href="" onclick="loadTicket(' . $result['primkey'] . ',\'' . $canReopen . '\');
return false;" ';
if ($result['resolution'] == strtolower('open') ) {
$resresolution = __('Open', 'wpsc-support-tickets');
} elseif ($result['resolution'] == strtolower('closed') ) {
$resresolution = __('Closed', 'wpsc-support-tickets');
} else {
$resresolution = $result['resolution'];
}
if ($devOptions['disable_inline_styles'] == 'false') {
$output.='style="border:none;text-decoration:none;"';
}$output.='><img';
if ($devOptions['disable_inline_styles'] == 'false') {
$output.=' style="float:left;border:none;margin-right:5px;"';
}$output.=' src="' . plugins_url('/images/page_edit.png', __FILE__) . '"
alt="' . __('View', 'wpsc-support-tickets') . '" /> ' . base64_decode($result['title']) .
'</a></td><td>' . $resresolution . '</td><td>'
. date_i18n( get_option( 'date_format' ),
$result['last_updated']) . ' ' . __('by', 'wpsc-support-tickets') . '
' . $last_staff_reply . '</td>
</tr>';
again - where might i add the variable for the column "department" if the variable were $department_var?
You can add it to the very end of that large chunk of mess before the closing </tr>...
change
...$last_staff_reply . '</td></tr>';
to
...$last_staff_reply . '</td><td>' . $department_var . '</td></tr>';

Database driven PHP menu with check for current page

I have a page with a persisted left nav that is populated based on a database. I need to visually mark the menu entry that corresponds with the content currently presented on the right side of the page. I am having problems getting the check of current page to work. (I am learning PHP and attempting to edit someone else's code, person long gone.)
Here is the code for the menu:
while( ( $row = mysql_fetch_array( $result ) ) && ( $count < $limit ) ) {
$count++;
echo "\t\t\t<li><a href=\"" . NEWS_URL . "?show=news&action=show&id=" . $row['id'] . "\" >" . stripslashes( $row['title'] ) . "</a></li>\n";
..etc. Works fine to generate menu list.
Then I think what I want to do is to compare the URI this code produces with the currently loaded page, to determine if I should add a CSS style for current page or not.
So I attempted this:
echo "\t\t\t<li><a href=\"" . NEWS_URL . "?show=news&action=show&id=" . $row['id'] . "\" <?php if( $_SERVER['REQUEST_URI'] == "$this" ) echo " class=\"selected\""; ?>>" . stripslashes( $row['title'] ) . "</a></li>\n";
Got syntax errors. So tried this:
echo "\t\t\t<li><a href=\"" . NEWS_URL . "?show=news&action=show&id=" . $row['id'] . "\" <?php if( $_SERVER['REQUEST_URI'] == $this ) echo " class=\"selected\""; ?>>" . stripslashes( $row['title'] ) . "</a></li>\n";
Still syntax errors. So tried this:
echo "\t\t\t<li><a href=\"" . NEWS_URL . "?show=news&action=show&id=" . $row['id'] . "\" <?php if( $_SERVER['REQUEST_URI'] == $row['id'] ) echo " class=\"selected\""; ?>>" . stripslashes( $row['title'] ) . "</a></li>\n";
Suggestions?
Success at last. I found a way to get this to work, though the code may be less than elegant.
I could not get the comparison of the URI and the $row['id'] to work within the echo statement. So I created a separate function to do the comparison and returned the result to the echo statement as follows:
echo "\t\t\t<li>" . stripslashes( $row['title'] ) . "</li>\n";
function checkRow($myID)
{
if( strstr( $_SERVER['REQUEST_URI'], $myID ) )
{
return " class=\"selected\"";
}
}
You have php tags in your echo statement in your first example
echo "\t\t\t<li><a href=\"" . NEWS_URL . "?show=news&action=show&id=" . $row['id'] . "\" <?php if( $_SERVER['REQUEST_URI'] == "$this" ) echo " class=\"selected\""; ?>>" . stripslashes( $row['title'] ) . "</a></li>\n";
try this
echo "\t\t\t<li><a href=\"".NEWS_URL."?show=news&action=show&id=".$row['id']."\". ($_SERVER['REQUEST_URI'] == $this ?"class=\"selected\"" :"").stripslashes( $row['title'] )."</a></li>\n";

Inside of a ternary php script how do i concatenate a second variable into my string?

Before style="style="color: ' . $rx_event_colors . '" I want to add the $ima variable. it's just a variable with an image inside of the string. Additionally, if you think i would benefit from just adding the
if(!empty($ins_event))
{
echo "<tr><td> <a href='". matry::here(array('event_id'=>$ins_event['id'])) . "'" .
( $ins_event['status'] == 2 ? ' style="color: ' . $rx_event_colors . '">Completed Insurance Event' : '>Active Insurance Event') . "</a></td></tr>";
}
I've tried:
? ' $ima, style="style="color: ' . $rx_event_colors . '"
style="style="color: ' . $ima, $rx_event_colors . '"
style="style="color: ' . ($ima), $rx_event_colors . '"
style="style="color: ' . ($ima), ($rx_event_colors) . '"
with no avail.
I'm assuming $ima is a string. To concatenate strings, use the "."
So in the first part of your ternary, if you'd like to add $ima, simply do this:
' style="color: ' . $ima . $rx_event_colors . '">Completed Insurance Event'
However, I'm confused when you say "[$ima] just a variable with an image inside of the string". Does $ima contain the path to the image itself? If so, it belongs in the SRC attribute of the img tag, not inside the STYLE attribute.
UPDATE:
Because $ima contained the entire img tag, it doesn't belong in the style atrribute. See:
' style="color: ' . $rx_event_colors . '">' . $ima . 'Completed Insurance Event'

How do I display the function the_content in this loop?

I have this loop in my wordpress site which displays the latest posts with their titles, I want to display the post content after the title. I normally retrieve it with the function get_the_content but I jkeep breaking the whole page in all kind of ways, I'm very new to php and have little idea of how to add anything to the loop. This is the loop:
while ( $q_query->have_posts() )
{
$q_query->next_post();
$question = get_post($q_query->post);
$loophtml = $loophtml . "<li><span class='list-question-title'>" . "<a class='list-answer-link' href='" . get_permalink($question->ID) ."'>" . $question->post_title . "</a></span>";
$loophtml = $loophtml . "<span class='list-number-answers'>" . get_comments_number($question->ID) . " comentarios</span> ยท&nbsp<a href='" . get_permalink($question->ID) ."'>Comentar</a>";
$loophtml = $loophtml . "</li>";
}
Anyone knows how I add the content somewhere? Thanks
All the post data are stored in the $question object, to retrieve the content
echo $question->post_content;
Here is some more information on get_post().
It has nothing to do with your question but please note: next_post() is deprecated.

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