How can I select my sql database only from yesterday? Here is my code:
SELECT *, COUNT(visitors.usr_id) as usr_count FROM user, visitors WHERE visitors.usr_id = $usr_id GROUP BY $usr_id ORDER BY usr_count LIMIT 1
My database name is timein and the way it inputs the date and time that the INSERT was done. Here is the code:
Database column : timein
Database insert looks like : 2012-9-6 9:11:35
Basically I want to be able to SELECT and COUNT only from yesterday. How can I SELECT COUNT from my sql database from yesterday only?
Your query does not make sense. You are doing a cross join between user and visitors and then filtering only on visitors. I suspect you want something like:
SELECT *, COUNT(visitors.usr_id) as usr_count
FROM user join
visitors
on visitors.usr_id = user.usr_id
WHERE user.usr_id = $usr_id
GROUP BY $usr_id
ORDER BY usr_count
LIMIT 1;
The where clause to get yesterday's data would be:
WHERE date(timein) = date(NOW() - INTERVAL 1 DAY)
Or, if you have an index on timein:
WHERE timein >= date(NOW() - INTERVAL 1 DAY) and timein < date(NOW())
Try this one add a condition for yesterday like timein <= NOW() - INTERVAL 1 DAY , timein >= NOW() - INTERVAL 2 DAY;
SELECT *, COUNT(visitors.usr_id) as usr_count
FROM user, visitors
WHERE visitors.usr_id = $usr_id
AND timein <= NOW() - INTERVAL 1 DAY
AND timein >= NOW() - INTERVAL 2 DAY
GROUP BY $usr_id
ORDER BY usr_count
LIMIT 1
Or you can use BETWEEN
SELECT *, COUNT(visitors.usr_id) as usr_count
FROM user, visitors
WHERE visitors.usr_id = $usr_id
AND timein BETWEEN NOW() - INTERVAL 1 DAY AND NOW() - INTERVAL 2 DAY;
GROUP BY $usr_id
ORDER BY usr_count
LIMIT 1
Related
I want to get the today count of users and yesterday's users count for that i want to write only one query how can i do that..?
these are my queries I want only one query:
SELECT COUNT(*) FROM visitors group by visited_date ORDER by visited_date DESC limit 1,1 as todayCount
SELECT COUNT(*) FROM visitors group by visited_date ORDER by visited_date DESC limit 1,0 as yesterdayCount
My expected results or only 2 columns
todayCount yesterdayCount
2 4
This should do the trick:
SELECT COUNT(CASE
WHEN visited_date = CURDATE() THEN 1
END) AS todayCount ,
COUNT(CASE
WHEN visited_date = CURDATE() - INTERVAL 1 DAY THEN 1
END) AS yesterdayCount
FROM visitors
WHERE visited_date IN (CURDATE(), CURDATE() - INTERVAL 1 DAY)
GROUP BY visited_date
ORDER by visited_date
If you know the current and previous date, then you can do:
SELECT SUM(visited_date = CURDATE()) as today,
SUM(visited_date = CURDATE() - interval 1 day) as yesterday
FROM visitors
WHERE visited_date >= CURDATE() - interval 1 day;
If you don't know the two days, then you can do something similar, getting the latest date in the data:
SELECT SUM(v.visited_date = m.max_vd) as today,
SUM(v.visited_date < m.max_vd) as yesterday
FROM visitors v CROSS JOIN
(SELECT MAX(v2.visited_date) as max_vd FROM visitors v2) as m
WHERE v.visited_date >= m.max_vd - interval 1 day
Just try this simple query
select visited_date as date, COUNT(*) as count from `visitors`
group by `visited_date` order by `visited_date` asc
It will produce output as
It will work for you.
Try this:
$sqlToday = "Select COUNT(*) FROM menjava WHERE DATE(date_submitted)=CURRENT_DATE()";
$sqlYesterday = "Select COUNT(*) FROM menjava WHERE DATE(dc_created) = CURDATE() - INTERVAL 1 DAY";
I have 2 tables:
profile userid, fname,lname
schedule: userid, date, start_time, end_time
Here is my query .
select *, group_CONCAT(distinct(date),'_',start_time,'_',end_time)
as dateformat FROM profile, schedule WHERE profile.userid =
schedule.pid
This returns all dates from the table. But what I am trying to do is return only certain days like:
date >= DATE(NOW()) and date <= date(now() + 2 day)
So today tomorrow and the day after.
No matter what I try it just returns all dates in the schedule database. I need this to return 2 rows userid 5 has 1 row in profile but 5 rows in schedule and userid 6 has 1 row in profile and 2 rows in schedule the query works fine its just returning all dates and not the dates within the
"date >= DATE(NOW()) and date <= date(now() + 2 day)"
did you try GROUP BY?
like WHERE profile.userid = schedule.pid GROUP BY date
select profile.userid,schedule.userid, group_CONCAT(distinct(date),'_',start_time,'_',end_time) as dateformat FROM profile, schedule WHERE profile.userid = schedule.userid and date >= DATE(NOW()) and date <= date(now() + interval 2 day);
That did it for now!! Now I can use the dateformat variable in php to parse out my results.
kanishka panamaldeniya - thanks for your suggestion!
I am trying to call data from SQL table that is only 3 days old
My table has a lbs-date column in it and is date format. I have tried the following but get no result from the query at all
$result = mysql_query("SELECT *, DATE_FORMAT(datetime, '%y,%m,%d') FROM lbs_trace_etrack
WHERE lbs_date(datetime) = CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC")
Is there any other way I can call only the last 3 days of information from the SQL my date format is Y/M/D
SELECT *, DATE_FORMAT(lbs_date, '%y,%m,%d')
FROM lbs_trace_etrack
WHERE lbs_date >= CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC
check DATE_FORMAT. Its syntax is DATE_FORMAT(<date>,format) . Use like this :
SELECT *, DATE_FORMAT(lbs_date , '%y,%m,%d') FROM lbs_trace_etrack
WHERE lbs_date = CURDATE() - INTERVAL 3 DAY
ORDER BY lbs_date DESC
SELECT
doctors. fullname,
dutyroster.date,
dutyroster.time
FROM
dutyroster
INNER JOIN doctors ON doctors.docid = dutyroster.docid
WHERE doctors.docid = $doc_id AND
dutyroster.date = DATE(NOW()) AND DATE(NOW())+ INTERVAL 1 DAY
ORDER BY dutyroster.`date` ASC";
this query is used to find specific doctors information from a table called dutyroster. i want to get the docs shedule information for current day and tommrow only.. but this doesnt work.
and i made a second one which is also not working since it returns current one and all the next dates also
SELECT
doctors. fullname,
dutyroster.date,
dutyroster.time
FROM
dutyroster
INNER JOIN doctors ON doctors.docid = dutyroster.docid
WHERE doctors.docid = $doc_id AND
DATE_SUB(CURDATE(),INTERVAL 2 DAY) <= dutyroster.date
ORDER BY dutyroster.`date` ASC"
Instead of
... AND dutyroster.date = DATE(NOW()) AND DATE(NOW())+ INTERVAL 1 DAY
try
... AND (dutyroster.date = CURDATE() OR
dutyroster.date = CURDATE() + INTERVAL 1 DAY))
or in more concise way, as #MarcM suggested
... AND dutyroster.date IN (CURDATE(), CURDATE() + INTERVAL 1 day)
From your first attempt it almost looks like you are trying to program COBOL!
Also, for future reference "this doesn't work" is not a helpful comment. You should say what actually happens.
Anyway, try changing your where clause to either:
WHERE doctors.docid = $doc_id AND
(dutyroster.date = CURRENT_DATE OR dutyroster.date = CURRENT_DATE + INTERVAL 1 DAY)
or:
WHERE doctors.docid = $doc_id AND
dutyroster.date IN (CURRENT_DATE, CURRENT_DATE + INTERVAL 1 DAY))
I have Db which has data of an year...so I need a query to select data from based on a date(particularly yesterday's) and count how many are in this.....
Help please!
It has a column with name "created" where all the date & time are present.
code used:
//$thirty_reg = mysql_query("SELECT column FROM user WHERE user.date BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND NOW()");
//$num_thirty=mysql_num_rows($thirty_reg);
//echo $num_thirty;
select *
from YourTable
where date_sub(curdate(), interval 1 day) < DateColumn
and DateColumn < curdate()
To fetch result set:
SELECT * FROM table WHERE data_date = DATE_SUB(NOW(), INTERVAL 1 DAY)
To fetch count of rows:
SELECT COUNT(*) FROM table WHERE data_date = DATE_SUB(NOW(), INTERVAL 1 DAY)