Add and edit in one form php - php

Question

I have two files .. addclient.php & Editclient.php.
I want to combine in one php form. can u please help me to do this
<?php
if(isset($_GET['id'])) {
$id = $_GET['id'];
echo "add";
} else if(isset($_GET['id'])) {
$id = $_GET['id'];
echo "edit"
}
?>
if $id already exist in the table than the row is updated otherwise it's an INSERT.
If you only have an $id : show the form with existing data in it.
If it's not a $id isn't populated : show an empty form.

Answer 1

<?php
if(isset($_GET['id'])) {
$id = intval($_GET['id']);
$stmt = $mysqli->prepare("SELECT id FROM table WHERE id = ?");
$stmt->bind_param('i', $id);
$stmt->execute();
if($stmt->num_rows > 0) {
// UPDATE
// Text field with the id
echo '<input type="text" name="id" value="'. $id. '"/>';
} else {
// INSERT
// Text field with no id
echo '<input type="text" name="id"/>';
}
}
?>
This validates the integer and makes sure it's one, queries the table for that specific id, if there is more than one row with that id then you need to update, else you need to insert.

Answer 2

<?php
if(isset($_GET['ID'])) {
$ID= $_GET['ID'];
// Use MySQL with $ID to check if the user is existing, and this string will either be 0 or 1
$existing = 0; // 0 = New 1 = Existing
//Add
if($existing== 0) {
}
//Edit
if($existing == 1) {
}
}
?>

Answer 3

Try this
<?php
if(isset($_GET['id'])) {
$id = $_GET['id'];
echo "update";
}else{
$id = $_GET['id'];
echo "add"
}
?>

Answer 4

Can you try this,
<?php
if(isset($_GET['id'])) {
$id = $_GET['id'];
echo "Edit";
} else {
echo "Add"
}
?>

Answer 5

try this
if(isset($id) && !empty($id)){
echo "Update";
}else{
echo "Add";
}