MySQL Database Access [closed] - php

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Closed 9 years ago.
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NOTE: Question Closed. I managed to figure out what was wrong.
My current code is this:
<?php
$con=mysqli_connect("HOST","USERNAME","PASSWORD");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
mysqli_select_db($con, "rbxdataa_Data");
$Amount=$_GET["Amount"];
$GetType=$_GET["Type"];
$sql = "SELECT * FROM EventRecord WHERE EventType='$GetType' ORDER BY EventId DESC";
$sql_run = mysqli_query($con, $sql);
while($sql_row = mysqli_fetch_assoc($sql_run)){
echo $sql_row['EventId'].'<br>';
}
mysqli_close($con);
?>
As I am currently very new to PHP and MySQL, I have no idea why this code will not work. I am also confused as to how I would make it echo only the top ($Amount) as determined by how large the "EventId" value is.
My intent is to gather the [$Amount] highest rows in the table with the EventType $GetType.
I am aware of SQL Injection vulnerability, however for my purposes this does not affect me.
Error:
"Parse error: syntax error, unexpected T_STRING on line 4"
This isn't the main error, however. I just can't read the main error yet.

Answer 1

In your line 4, mysqli_connect_error() doesn't exist. Please check mysqli documentation http://www.php.net/manual/en/book.mysqli.php
Edit: You may try: printf("Connect failed: %s\n", mysqli_error($con));

Answer 2

Please use this code:
<?php
$con=mysqli_connect("HOST","USERNAME","PASSWORD");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
mysqli_select_db($con, "rbxdataa_Data");
$Amount=$_GET["Amount"];
$GetType=$_GET["Type"];
$sql = "SELECT * FROM EventRecord WHERE EventType='$GetType' ORDER BY EventId DESC";
$sql_run = mysqli_query($con, $sql);
while($sql_row = mysqli_fetch_assoc($sql_run)){
echo $sql_row['EventId'].'<br>';
}
mysqli_close($con);
?>

Answer 3

Try this.
$con=mysqli_connect("HOST","USERNAME","PASSWORD","rbxdataa_Data");
$sql_query = "SELECT * FROM EventRecord WHERE EventType='$GetType' ORDER BY EventId DESC";
$sql_result = mysqli_query($con,$sql_query)
or exit("Query fail message");
Otherwise looks like what I'm used to.
I just realized that no one has even asked about the $_GET variable you're using you're using. You set $GetType from $_GET['Type']. It could be that.