Rating on Radio button is not stored - php

Question

I have a comment BOX, which has 5 fields, one is name, email, RATE, comment, articleid.
Rate field is a radio type, which has 5 radio buttons with value 1,2,3,4,5. IF someone click on rate my product and it should save the rated value in databse. I'm using RATE as INT in database, It stores 0 in it, If i use RATE as TEXT in database, it stores "on" in database. It is not storing rating values like 1,2,3,4,5.
My form Code
<form action="manage_comments.php" method="post">
<span class="rating">
<input type="radio" class="rating-input" id="rate" name="rate" value="1">
<label for="rating-input-1-5" class="rating-star"></label>
<input type="radio" class="rating-input" id="rate" name="rate" value="2">
<label for="rating-input-1-4" class="rating-star"></label>
<input type="radio" class="rating-input" id="rate" name="rate" value="3">
<label for="rating-input-1-3" class="rating-star"></label>
<input type="radio" class="rating-input" id="rate" name="rate" value="4">
<label for="rating-input-1-2" class="rating-star"></label>
<input type="radio" class="rating-input" id="rate" name="rate" value="5">
<label for="rating-input-1-1" class="rating-star"></label>
</span>
<input type='hidden' name='articleid' id='articleid' value='<?php echo $_GET["id"]; ?>' />
<input type="submit" name="submit" value="Publish Now"></p>
</form>
My php Code
<?php
if( $_POST )
{
$con = mysql_connect("localhost","asfi","asfi");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("aw-tech", $con);
$post_rate = (isset($_POST['rate'])) ? $_POST['rate'] : '';
$articleid = (int)isset($_GET['id']);
if(!is_numeric($articleid))
die('invalid article id');
$sql="INSERT INTO `aw-tech`.`comment` (cid, name, email, website, comment, timestamp, rate, articleid) VALUES (NULL, '$_POST[name]', '$_POST[email]', '$_POST[website]', '$_POST[comment]', CURRENT_TIMESTAMP, '$post_rate', ".$articleid.")";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "Comment Saved";
mysql_close($con);
}
?>
Secondly My articleid saves always 0.. my page id is .php?id=49 , it is 49 but if i made comment on that page, It saves my article ID always 0.
articleid & rate Both are INT in database, I have used them as TEXT too in database but didn't work

Answer 1

I think I found your problem. Change form declaration to:
<form action="manage_comments.php" method="post">
Remove row:
<input type='hidden' name='articleid' id='articleid' value='<?php echo $_GET["id"]; ?>' />
the Then PHP code from:
$post_rate = (isset($_POST['rate'])) ? $_POST['rate'] : '';
$articleid = (int)isset($_GET['id']);
to:
$post_rate = (isset($_POST['rate'])) ? $_POST['rate'] : 0;
$articleid = (int)isset($_GET['id']) ? $_GET['id'] : 0;
And for debug add this after the $sql variable and insert into a comment here:
print_r($_GET);
print_r($_POST);
echo $sql;
Hope it works.

Answer 2

when you post the form in action you put : manage_comments.php
so the "id" be lost!
in action you can put : manage_comments.php?id=<?php=$_GET[id]?>
or
after submit form
use $_POST[articleid] not $_GET['id']

Answer 3

i think it supposes to be
$post_rate = (isset($_POST['rate'])) ? $_POST['rate'] : '';
$articleid = (int)isset($_POST['articleid']);