i have a folder with some folder names, for example 3 folders:
2012-2013, 2013-2014 ,2014-2015
is any way with some php code, to show the names folders in my php like this:
<option value="2012-2013">2012-2013</option>
<option value="2013-2014">2013-2014</option>
<option value="2014-2015">2014-2015</option>
untill I use to show the stuff with php-foreach using a html-template inside the folders.
but i want to show direct the stuff without using the template in the data-folder, is any way? thx.
I suppose you want to recursive the folder in a directory. Below please find the code.
<?php
$folder_name = "c:\\your_folder\\";
$folders = scandir($folder_name);
echo '<select>';
foreach($folders as $folder){
if (is_dir($folder_name . $folder)){
if ($folder != '.' && $folder != '..')
echo '<option value="' . $folder . '">' . $folder . '</option>';
}
}
echo '</select>';
?>
You need to read the directory and print an option tag for each time you find a file that is a folder.
first thing you need to open file handler to your directory by giving the main folder path, than itterate over the directory by using the read method on the folder handler.
By using the "is_dir" function you can determine if the file is a folder, and if so print the file.
I added my solution which is recursive.
function printFolders($path = "", $c = 0) {
if ( empty($path) || !is_dir($path) )
{
return false;
}
//Folder handler
$handler = dir($path);
//Read each file name inside the directory
while(($file = $handler->read()) !== false)
{
// "." is the current folder and ".." is the parent folder
// We skip those folders
if ( $file == "." || $file == ".." )
{
continue;
}
// The current file path
$filePath = $path . "/" . $file;
if ( is_dir($filePath) )
{
//Just to make things more pretty
for($i=0; $i<=$c; $i++) {echo "-";}
//Printing the folder name
echo $file . "<br>";
//Calling the function again with the folder we found
printFolders($filePath, $c+1);
}
}
}
printFolders("path/to/folder");
Related
I want to be able to list all the directories, subdirectories and files in the "./" folder ie the project folder called fileSystem which contains this php file scanDir.php.
You can view the directory system I've got here:
At the minute it will only return the subdirectory folders/files in the root of the mkdir directory but not any folders inside that subdirectory.
How do I modify the code so that it demonstrates all the files, directories, subdirectories and their files and subdirectories within the fileSystem folder given that the php file being run is called scanDir.php and the code for that is provided below.
Here is the php code:
$path = "./";
if(is_dir($path))
{
$dir_handle = opendir($path);
//extra check to see if it's a directory handle.
//loop round one directory and read all it's content.
//readdir takes optional parameter of directory handle.
//if you only scan one single directory then no need to passs in argument.
//if you are then going to scan into sub-directories the argument needs
//to be passed into readdir.
while (($dir = readdir($dir_handle))!== false)
{
if(is_dir($dir))
{
echo "is dir: " . $dir . "<br>";
if($dir == "mkdir")
{
$sub_dir_handle = opendir($dir);
while(($sub_dir = readdir($sub_dir_handle))!== false)
{
echo "--> --> contents=$sub_dir <br>";
}
}
}
elseif(is_file($dir))
{
echo "is file: " . $dir . "<br>" ;
}
}
closedir($dir_handle); //will close the automatically open dir.
}
else {
echo "is not a directory";
}
Use scandir to see all stuff in the directory and is_file to check if the item is file or next directory, if it is directory, repeat the same thing over and over.
So, this is completely new code.
function listIt($path) {
$items = scandir($path);
foreach($items as $item) {
// Ignore the . and .. folders
if($item != "." AND $item != "..") {
if (is_file($path . $item)) {
// this is the file
echo "-> " . $item . "<br>";
} else {
// this is the directory
// do the list it again!
echo "---> " . $item;
echo "<div style='padding-left: 10px'>";
listIt($path . $item . "/");
echo "</div>";
}
}
}
}
echo "<div style='padding-left: 10px'>";
listIt("/");
echo "</div>";
You can see the live demo here in my webserver, btw, I will keep this link just for a second
When you see the "->" it's an file and "-->" is a directory
The pure code with no HTML:
function listIt($path) {
$items = scandir($path);
foreach($items as $item) {
// Ignore the . and .. folders
if($item != "." AND $item != "..") {
if (is_file($path . $item)) {
// this is the file
// Code for file
} else {
// this is the directory
// do the list it again!
// Code for directory
listIt($path . $item . "/");
}
}
}
}
listIt("/");
the demo can take a while to load, it's a lot of items.
There are some powerful builtin functions for PHP to find files and folders, personally I like the recursiveIterator family of classes.
$startfolder=$_SERVER['DOCUMENT_ROOT'];
$files=array();
foreach( new RecursiveIteratorIterator( new RecursiveDirectoryIterator( $startfolder, RecursiveDirectoryIterator::KEY_AS_PATHNAME ), RecursiveIteratorIterator::CHILD_FIRST ) as $file => $info ) {
if( $info->isFile() && $info->isReadable() ){
$files[]=array('filename'=>$info->getFilename(),'path'=>realpath( $info->getPathname() ) );
}
}
echo '<pre>',print_r($files,true),'</pre>';
I´m building a php programm which uploads a zip file, extracts it and generates a link for a specific file in the extracted folder. Uploading and extracting the folder works fine. Now I´m a bit stuck what to do next. I have to adress the just extracted folder and find the (only) html file that is in it. Then a link to that file has to be generated.
Here is the code I´m using currently:
$zip = new ZipArchive();
if ($zip->open($_FILES['zip_to_upload']['name']) === TRUE)
{
$folderName = trim($zip->getNameIndex(0), '/');
$zip->extractTo(getcwd());
$zip->close();
}
else
{
echo 'Es gab einen Fehler beim Extrahieren der Datei';
}
$dir = getcwd();
$scandir = scandir($dir);
foreach ($scandir as $key => $value)
{
if (!in_array($value,array(".",".."))) //filter . and .. directory on linux-systems
{
if (is_dir($dir . DIRECTORY_SEPARATOR . $value) && $value == $folderName)
{
foreach (glob($value . "/*.html") as $filename) {
$htmlFiles[] = $filename; //this is for later use
echo "<a href='". SK_PICS_SRV . DIRECTORY_SEPARATOR . $filename . "'>" . SK_PICS_SRV . DIRECTORY_SEPARATOR . $filename . "</a>";
}
}
}
}
So this code seems to be working. I just noticed a rather strange problem. The $zip->getNameIndex[0] function behaves differently depending on the program that created the zip file. When I make a zip file with 7zip all seems to work without a problem. $folderName contains the right name of the main folder which I just extracted. For example "folder 01". But when I zip it with the normal windows zip programm the excat same folder (same structure and same containing files) the $zip->getNameIndex[0] contains the wrong value. For example something like "folder 01/images/" or "folder 01/example.html". So it seems to read the zip file differently/ in a wrong way. Do you guys know where that error comes from or how I can avoid it? This really seems strange to me.
Because you specify the extract-path by yourself you can try finding your file with php's function "glob"
have a look at the manual:
Glob
This function will return the name of the file matching the search pattern.
With your extract-path you now have your link to the file.
$dir = "../../suedkurier/werbung/"
$scandir = scandir($dir);
foreach ($scandir as $key => $value)
{
if (!in_array($value,array(".",".."))) //filter . and .. directory on linux-systems
{
if (is_dir($dir . DIRECTORY_SEPARATOR . $value))
{
foreach (glob($dir . DIRECTORY_SEPARATOR . $value . "/*.html") as $filename) {
$files[] = $value . DIRECTORY_SEPARATOR $filename;
}
}
}
}
The matched files will now be saved in the array $files (with the subfolder)
So you get your path like
foreach($files as $file){
echo $dir . DIRECTORY_SEPARATOR . $file;
}
$dir = "the/Directory/You/Extracted/To";
$files1 = scandir($dir);
foreach($files1 as $str)
{
if(strcmp(pathinfo($str, PATHINFO_EXTENSION),"html")===0||strcmp(pathinfo($str, PATHINFO_EXTENSION),"htm")===0)
{
echo $str;
}
}
Get an array of each file in the directory, check the extension of each one for htm/html, then echo the name if true.
I have one main directory "Images" and many subdirectories - inside them are files (in main folder too). Example tree:
+Images
-first.jpg
-second.jpg
++FOLDER1
--image1.jpg
++FOLDER2
--image2.jpg
I found a script there:
function ListFiles($dir) {
if($dh = opendir($dir)) {
$files = Array();
$inner_files = Array();
while($file = readdir($dh)) {
if($file != "." && $file != ".." && $file[0] != '.') {
if(is_dir($dir . "/" . $file)) {
$inner_files = ListFiles($dir . "/" . $file);
if(is_array($inner_files)) $files = array_merge($files, $inner_files);
} else {
array_push($files, $dir . "/" . $file);
}
}
}
closedir($dh);
return $files;
}
}
$list = ListFiles('../upload/_thumbs/Images');
sort($list);
foreach ($list as $key=>$file){
echo '<option value="">'.$file.'</option>';
}
This script works fine but I can sort my results by folders (first main content, then rest)... I get i my select:
../upload/_thumbs/Images/first.jpg
../upload/_thumbs/Images/FOLDER1/image1.jpg
../upload/_thumbs/Images/FOLDER2/image2.jpg
../upload/_thumbs/Images/second.jpg
Expection:
../upload/_thumbs/Images/first.jpg
../upload/_thumbs/Images/second.jpg
../upload/_thumbs/Images/FOLDER1/image1.jpg
../upload/_thumbs/Images/FOLDER2/image2.jpg
I would be glad if you will help me! Thanks!
Well it probably has something to do with the sort function you call somewhere in the last lines
sort($list);
It's causing the array to sort alphabetical. You could try to leave it out, or you could try to use natsort.
natsort($list);
This is happening because you are sorting with the full path. Instead of sort, I would use uasort which is similar to sort, except you use a callback function to define which goes first.
alternatively, you could get by prepending the file name to the path and using the key on insert. In other words:
array_push($files, $dir . "/" . $file);
becomes:
$files[$file . $dir] = $dir . "/" . $file;
then you sort using ksort
The code below is able list down nicely all the folders, sub folder and their files.
But I need create this in as a directory.html which will hyperlink to the file. it will be open at a computer so the linking how do I do it, as of now I only can display the content but no hyperlink.
Thanks for helping. !
<?php
$base_dir = 'C:\Users\baoky\Dropbox\SS133A\FINAL PHASE\Documents To Submit';
if (is_dir($base_dir))
scan_directory($base_dir);
else
echo 'Invalid base directory. Please check your setting.';
// recursive function to check all dir
function scan_directory($path) {
if (is_dir($path)) {
if ($dir_handle = opendir($path)) {
echo '<ul>';
while (($file = readdir($dir_handle)) !== false) {
if ($file != '.' && $file != '..') {
if (is_dir($path . '/' . $file)) {
echo '<li>';
echo ''.$file.'';
scan_directory($path . '/' . $file);
echo '</li>';
}
else
echo "<li>{$file}</li>";
}
}
echo '</ul>';
}
}
}
?>
the issue is with the recursive is not able to get the full path. I did a href but if a folder is inside 1 folder, then in another sub folder , then another sub folder which is folder1/folder2/folder3/file.txt then its display only file.txt which is wrong.
echo "<a href='$file'>$file</a>" will be the basics of it, though you'd need to build the FULL path leading up the file, since you're doing a recursive dump and only dealing with the "local" sub-path.
I have a basic PHP script that displays the file contents of a directory. Here is the script:
<?php
$Dept = "deptTemplate";
if(isset($_REQUEST['dir'])) {
$current_dir = $_REQUEST['dir'];
} else {
$current_dir = 'docs';
}
if ($handle = opendir($current_dir)) {
while (false !== ($file_or_dir = readdir($handle))) {
if(in_array($file_or_dir, array('.', '..'))) continue;
$path = $current_dir.'/'.$file_or_dir;
if(is_file($path)) {
echo '`'.$file_or_dir.' - [Delete button/link]<br/>`';
} else {
echo '``'.$file_or_dir."\n`` - [Delete button/link]`<br/>`";
}
}
closedir($handle);
}
?>
I am trying to create a delete link/button that displays next to each file and when clicked, the corresponding file will be deleted. Would you know how to do this?
Use the built-in unlink($filepath) function.
Sure, you'd have to use unlink() and rmdir(), and you'd need a recursive directory removal function because rmdir() doesn't work on directories with files in them. You'd also want to make sure that the deletion script is really secure to stop people from just deleting everything.
Something like this for the recursive function:
function Remove_Dir($dir)
{
$error = array();
if(is_dir($dir))
{
$files = scandir($dir); //scandir() returns an array of all files/directories in the directory
foreach($files as $file)
{
$fullpath = $dir . "/" . $file;
if($file == '..' || $file == '.')
{
continue; //Skip if ".." or "."
}
elseif(is_dir($fullpath))
{
Remove_Dir($fullpath); //recursively remove nested directories if directory
}
elseif(is_file($fullpath))
{
unlink($fullpath); //Delete file otherwise
}
else
{
$error[] = 'Error on ' . $fullpath . '. Not Directory or File.' //Should be impossible error, because everything in a directory should be a file or directory, or . or .., and thus should be covered.
}
}
$files = scandir($dir); //Check directory again
if(count($files) > 2) //if $files contains more than . and ..
{
Remove_Dir($dir);
}
else
{
rmdir($dir); //Remove directory once all files/directories are removed from within it.
}
if(count($error) != 0)
{return $error;}
else
{return true;}
}
}
Then you just need to pass the file or directory to be deleted through GET or something to the script, probably require urlencode() or something for that, make sure that it's an authorized user with permissions to delete trying to delete the stuff, and unlink() if it's a file, and Remove_Dir() if it's a directory.
You should have to prepend the full path to the directory or file to the directory/file in the script before removing the directory/file.
Some things you'll want for security is firstly making sure that the deletion is taking place in the place it's supposed to, so someone can't do ?dir=/ or something and attempt to delete the entire filesystem from root, which can probably be circumvented by prepending the appropriate path onto the input with something like $dir = '/home/user/public_html/directories/' . $_GET['dir'];, of course then they can potentially delete everything in that path, which means that you need to make sure that the user is authorized to do so.
Need to keep periodic backups of files just in case.
Something like this? Not tested...
<?php
echo '`'.$file_or_dir.' - [Delete button/link]<br/>`';
?>
<?php
if ($_GET['del'] == 1 && isset($_GET['file_or_dir']){
unlink ("path/".$_GET['file_or_dir']);
}
?>
I've worked it out:
I added this delete link on the end of each listed file in the original script:
- < a href="delete.php?file='.$file_or_dir.'&dir=' . $dir . '"> Delete< /a>< br/>';
This link takes me to the download script page, which looked like this:
<?php
ob_start();
$file = $_GET["file"];
$getDir = $_GET["dir"];
$dir = 'docs/' . $getDir . '';
$isFile = ($dir == "") ? 'docs/' . $file . '' : '' . $dir . '/' . $file . '';
if (is_file($isFile)){
if ($dir == "")
unlink('docs/' . $file . '');
else
unlink('' . $dir . '/' . $file . '');
echo '' . $file . ' deleted';
echo ' from ' . $dir . '';
}
else{
rmdir('' . $dir . '/' . $file . '');
echo '' . $dir . '/' . $file . ' deleted';}
header("Location: indexer.php?p=" . $getDir . "");
ob_flush();
?>
It all works brilliantly now, thank you all for your help and suggestions :)