Oracle/PHP oci_fetch_all() issue - php

Question

Pretty new to PHP using Oracle. I'm following examples online. I'm using this example 1 from the official site. My issue is, it displays all the records like I want, but it's missing the column/field names. Does anyone now how to alter this so that it includes the headers? (ex, my employee table would have... First Name, Last Name....) Thanks
<?php
$conn = oci_connect('hr', 'welcome', 'localhost/XE');
if (!$conn) {
$e = oci_error();
trigger_error(htmlentities($e['message'], ENT_QUOTES), E_USER_ERROR);
}
$stid = oci_parse($conn, 'SELECT * FROM employee');
oci_execute($stid);
$nrows = oci_fetch_all($stid, $res);
echo "$nrows rows fetched<br>\n";
var_dump($res);
// Pretty-print the results
echo "<table border='1'>\n";
foreach ($res as $col) {
echo "<tr>\n";
foreach ($col as $item) {
echo " <td>".($item !== null ? htmlentities($item, ENT_QUOTES) : "")."</td>\n";
}
echo "</tr>\n";
}
echo "</table>\n";
oci_free_statement($stid);
oci_close($conn);
?>

Answer 1

Most DBMS(I haven't worked with them all so I can't say "all") systems have a separate table that stores this sort of meta information, so you'd want to query it. In Oracle, it's stored as a dictionary, probably in some sort of table header data or meta info (I really don't know Oracle's underlying structure well) and it's called user_tab_columns
So what do ya do? Query it as though it were a table.
SELECT * FROM user_tab_columns WHERE TABLE_NAME='employee'
However, I don't know why you'd want to query this after the fact given your code, as you already know the column names and could easily just hardcode them in.