Creating drop down menu using php, sql connected to database table - php

Question

I'm creating currently database with tables and trying to do it using second normalization form for my school.
I have list of institutional partners which has to be displayed in two tables.
I got this far that I have created database tables:
The first one called "as_partners_id" which contain columns: "Partner_ID" (this is primary key INT) and "Partner" (just a VARCHAR).
The other table called "as_partners" has some more columns, like: "Partner_ID, Country, EU terms, NON-EU terms, More info".
What I want to do is create drop down menu above first table from which you can choose ID from e.g. 1 to 30. After picking it will display the second table with more information about this particular ID. But I actually don't know how to do it properly. Here is the code that I have so far:
<?php
// Create connection
$con=mysqli_connect("localhost","easj_admin","","easj");
// Check connection
if (mysqli_connect_errno())
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
} else {
echo "We are connected.";
}
$result = mysqli_query($con,"SELECT Partner_ID, Partner FROM as_partners_id");
?>
BODY PART:
<table>
<tr>
<?php
// Get field information for all fields
while ($fieldinfo=mysqli_fetch_field($result))
{
echo "<th>" . $fieldinfo->name ."</th>";
}
echo "</tr>";
// <form>
// <input typ="select">
// </form>
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['Partner_ID'] . "</td><td>" . $row['Partner'] . "</td>" ;
echo "</tr>";
}
?>
</table>
How can I add to my code this drop down menu that will display the second table called as_partners?
Please help.

Answer 1

<form name="myform" method="get">
<select name='whatever' onclick="if(this.value != ''){ myform.submit(); }">
<?
while($row = mysqli_fetch_array($result))
{
echo "<option value='" . $row['Partner_ID'] . "'>" . $row['Partner'] . "</option>";
}
?>
</select>
</form>
That will get you the drop down. Then from there you can submit the form using post or get and use the submitted id to generate the second table.
Then you'll need to add php code similar to this:
if(isset($_GET['whatever']))
{
[build 2nd table here]
}