Listing Dates In Order (Options Drop-Down) - php

Question

I want to produce a form that has a dropdown options box containing dates in order and in a format but I have no idea how to display them as a string.
I assume that you need to do this sort of thing to get the start and finish but how can I get the dates for each "Option"?
<?php
date_default_timezone_set('UTC');
$start = date('Ymd');
$end = date('Ymd', strtotime('+60 days'));
while (strtotime($start) <= strtotime($end)) {
echo "$start\n";
$date = date ("Ymd", strtotime("+1 day", strtotime($start)));
}
?>

Answer 1

$dates = array();
$dates[] = time();
for ($i = 1; $i < 60; $i++) { $dates[] = strtotime("+{$i} days"); }
$html = NULL;
foreach ($dates as $date) { $dates .= "<option value='" . date('Ymd', $date) . "'>" . date('d F Y', $date) . "</option>"; }
$html = "<select id='dates'>{$dates}</select>";
echo $html;

Answer 2

I would just like to add to Publi Design's answer to make the answer more specific to the question.
PHP courtesy of Publi Design:
// Start date
$date = '2009-12-06';
// End date
$end_date = '2020-12-31';
?>
<select id="dates">
<?php while (strtotime($date) <= strtotime($end_date)) { ?>
<option name="date"><?php echo (string)$date; ?></option>
<?php $date = date ("Y-m-d", strtotime("+1 day", strtotime($date)));
}?>
</select>

Answer 3

Using a basic PHP while loop:
// Set timezone
date_default_timezone_set('UTC');
// Start date
$date = '2009-12-06';
// End date
$end_date = '2020-12-31';
while (strtotime($date) <= strtotime($end_date)) {
echo "$date\n";
$date = date ("Y-m-d", strtotime("+1 day", strtotime($date)));
}
Original source: here

Answer 4

This might be what you're looking for..
<select id="dates">
<option></option>
<?php
$curr_date = date('YYMMDD');
for ($i = 0; $i < 60; $i++) {
$date = strtotime("+$i day", $curr_date);
echo '<option name="date" value="'.$date.'">'.date('DD m YY', strtotime($date)).'</option>'."\n";
}
?>
</select>