MySQL column values to array. Wrong values as a result - php

Question

Trying to get all the values from a single column.
After all simply trying to print all the values to check if everything is OK. Unfortunately all the values I get printed are the same - "Array" (without quotes).
I am quite new working with MySQL. Here is my code:
$sql_connect = mysql_connect("localhost","db_user_name","db_password") ;
if (!$sql_connect) {
die("Database connection failed: " . mysql_error());
}
mysql_select_db("db_name") or die ("no database");
$result = mysql_query("SELECT column_name FROM table_name");
$video_IDs = array();
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$video_IDs[] = $row[$key];
}
then, I print the $video_IDs array
$test = 1 ;
while (each($video_IDs)) {
echo "{$test} - {$video_IDs}<br />" ;
$test++ ;
}
mysql_close($sql_connect);
As a result i get printed all 10 values as 10 row are in my table. But all the values are "Array" (without quotes).
My result:
1 - Array
2 - Array
3 - Array
4 - Array
5 - Array
6 - Array
7 - Array
8 - Array
9 - Array
10 - Array
Looking forward to get any suggestions.

Answer 1

There is no native way to echo an array without using a loop or recursion or accessing a specific element of said array. You're using the each function improperly as well since it returns a key/value pair as a result (and you're not capturing that result for the loop.) You should do something like this instead:
$test = 1 ;
foreach ($video_IDs as $v) {
echo "{$test} - {$v}<br />";
$test++;
}
If you must use each, here's a slight change to your original code so that the key/value pair is stored in $v over every iteration
$test = 1 ;
while ($v = each($video_IDs)) {
echo "{$test} - {".$v['value']."}<br />" ;
$test++ ;
}
If you're just trying to display the array without any specific formatting, use var_dump or print_r
It is also necessary to note that you're using a depreciated function (mysql_*) and you should use MySQLi or PDO for your SQL queries.

Answer 2

If $video_IDs is an array, you need to use print_r or loop through each element. The code below will output the data you are
$test = 1 ;
foreach( $video_IDs as $key => $value) {
if( is_array($value) ){
echo "$test $key =>";
print_r($value);
echo "<br/>";
}else{
echo "$test $key => $value <br/>";
}
$test++ ;
}

Answer 3

if you want to print array content then use print_r(array_name)
Best way to see the content is
echo "<pre>";
print_r(array_name);
echo "</pre>";

Answer 4

Solution found
Thank you for suggestions and pointing the depreciated function (mysql_*). I have changed the connection to MySQL DB functions and everything else and now i have a proper results.
$link = mysqli_connect('localhost', 'username', 'password', 'db_name');
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "SELECT column_name FROM table_name";
$result = mysqli_query($link,$query);
while ($video_IDs = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
$rows[] = $video_IDs ;
}
foreach($rows as $video_IDs)
{
echo $video_IDs['column_name']."<br />";
}
Thank you all for comments!