users near a specific zip code: PHP mysql - php

Question

Happy new year! Suppose user1 is located at zip code 12345. I want to find other users within X miles from that zip code.
First, I created the form:
<div id="wrapper">
<form action="L1.php" method="post">
<select name="radius">
<option value="5">5</option>
<option value="10">10</option>
<option value="20">20</option>
<option value="30">30</option>
<option value="40">40</option>
<option value="50">50</option>
</select>
Miles within Zip Code:
<input name="zip" type="text" value="13126" />
<input type="submit" value="refine" />
</form>
</div>
Now I am listing all the zip codes within X miles from 12345: (L1.php):
<?php
include('includes/db_AF.php'); //includes the db credentials
$connection = #new mysqli(HOSTNAME, MYSQLUSER, MYSQLPASS, MYSQLDB);
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
//look up the zip code in the searchbox
$whereClauses = array();
if (! empty($_POST['zip'])) $whereClauses[] ="zip_code='".mysqli_real_escape_string($connection,$_POST['zip'])."'";
$where = '';
if (count($whereClauses) > 0) { $where = ' WHERE '.implode(' AND ',$whereClauses); }
$sql = "SELECT * FROM zip " .$where." ";
$result=mysqli_query($connection,$sql) or die("Error: ".mysqli_error()."<br />Query: ".$sql);
//find out the corresponding lat and long
while ($row = mysqli_fetch_assoc($result)) {
echo '<br />';
echo '<br />';
$lat=$row['latitude'];
echo '<br />';
$lon=$row['longitude'];
echo '<br />';
}
$radius=$_POST['radius'];
//here I am generating an array of all the zip codes within x miles from 12345.
$query="SELECT * FROM zip WHERE (3958*3.1415926*sqrt((latitude-'$lat')*(latitude-'$lat') + cos(latitude/57.29578)*cos('$lat'/57.29578)*(longitude-'$lon')*(longitude-'$lon'))/180) <= '$radius'";
$result_obj = '';
$result_obj = $connection->query($query);
while($resultx = $result_obj->fetch_array(MYSQLI_ASSOC)) {
$items[] = $resultx;
}
foreach ($items as $item) {
echo $item['zip_code'];
echo '<br />';
}
$queryz="SELECT zip FROM customer"; // I am generating an array of all customer zip codes.
$resultz_obj = '';
$resultz_obj = $connection->query($queryz);
while($resultzz = $resultz_obj->fetch_array(MYSQLI_ASSOC)) {
$itemsz[] = $resultz;
}
$resultv = array_intersect($items, $itemsz);
print_r($resultv);
So now I have an array of zip codes. I want to list users that live at those zip codes. I know I have to intersect two arrays but get "Notice: Array to string conversion" error. Any thoughts?

Answer 1

If You have zip code in $items then i think you don't need $itemsz for all customer zipcodes.
First you need to format $items array to like this :
$zips = (12345,12346,12347,12348)
Then just run a query like this in customer:
Select * from customer where customer.zipcode IN $zips
demo: https://eval.in/84652
SAMPLE code:
$items =array( '0' => array( 'zip_code' => 13121, 'latitude' => 43.483379, 'longitude' => -76.315044, 'city' => 'New Haven', 'state' => 'NY', 'county' => 'Oswego' ), '1' => array( 'zip_code' => 13126, 'latitude' => 43.465388 ,'longitude' => -76.342172 ,'city' => 'Oswego' ,'state' => 'NY', 'county' => 'Oswego' ) );
$strzipCodes="";
foreach($items as $item){
$strzipCodes .= $item['zip_code']." ,";
}
$strzipCodes = rtrim($strzipCodes,',');
$sql ="SELECT * FROM customer where zip IN(".$strzipCodes.")";
echo $sql;
// then execute query we will get all users inside those zipcodes
I think you get the idea.