Getting results only for today's date - php

Question

I want to get some of the entries from my db which has dates of only today, here is my working code which gets all of the data;
$result = mysql_query("SELECT *FROM products") or die(mysql_error());
// check for empty result
if (mysql_num_rows($result) > 0) {
// looping through all results
// products node
$response["products"] = array();
while ($row = mysql_fetch_array($result)) {
// temp user array
$product = array();
$product["pid"] = $row["pid"];
$product["name"] = $row["name"];
$product["price"] = $row["price"];
$product["description"] = $row["description"];
$product["created_at"] = $row["created_at"];
$product["updated_at"] = $row["updated_at"];
// push single product into final response array
array_push($response["products"], $product);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
}
As well as allowing the user to pick a date and display only the data that was created at that date.
The field is;
name created_at
type timestamp
null No
default CURRENT_TIMESTAMP

Answer 1

In the Mysql query you can use DATE() to strip the time of day off of your timestamp like so:
SELECT * FROM products WHERE DATE(created_at) = '<date>';
i.e. this could be implemented as
$result = mysql_query("SELECT * FROM products WHERE DATE(created_at) = '".date("Y\-m\-d")."'") or die(mysql_error());
or if you have $inputdate set to be the user specified date.
$result = mysql_query("SELECT * FROM products WHERE DATE(created_at) = '".$inputdate->format("Y\-m\-d\")."'") or die(mysql_error());