How to add comments to post with Mysql and PHP - php

Question

I managed to add comments to the table of Comments but it doesn't appear to the related post. I understand because the foreign key (artID) in the articles table is empty. How do I fetch the primary key from the articles table? Here is the structure of my database.
SQL injections issues will be dealt later. Prepared statements will be done. I just would like to get some help on the query and php function. Thank you.
articles
artID
artTitre
artAuteur
artContenu
artDate
commentaires
commentID
commentPseudo
commentText
artID
commentaires.sql.php
<?php
// INSERT
function insertCommentaire($c){
$PseudoCommentaire = $TexteCommentaire ='';
$PseudoCommentaire = $_POST['PseudoCommentaire'];
$TexteCommentaire = $_POST['TexteCommentaire'];
$IdArticle = $_POST['IdArticle'];
$qryInsertComm = 'INSERT INTO commentaires (commentPseudo,commentText, artID)
VALUES ( \''.$PseudoCommentaire.'\',
\''.$TexteCommentaire.'\',
\''.$IdArticle.'\')
';
if (!mysqli_query($c,$qryInsertComm))
{
die('Error: ' . mysqli_error($c));
}
echo "1 record added";
}
// UPDATE
function updateCommentaire( $IdCommentaire ){
}
// DELETE
function deleteCommentaire( $IdCommentaire ){
}
// CONTROLER //
switch( $action ){
case 'insert' :
$process = insertCommentaire($conn);
if( $process == 'ok' )
header( 'location:index.php?page=home' );
else
$page = 'home';
break;
case 'update' :
$process = updateCommentaire( $_GET[ 'item' ] );
if( $process == 'ok' )
header( 'location:index.php?page=home' );
else
$page = 'home';
break;
case 'delete' :
$process = deleteCommentaire( $_GET[ 'item' ] );
if( $process == 'ok' )
header( 'location:index.php?page=home' );
break;
}
?>

Answer 1

You are using a hidden input val called IdArticle in
<input type="hidden" name="IdArticle" value="" />
To keep track of which article the comment should go against, as shown above in the php script:
$IdArticle = $_POST['IdArticle'];
However, looking at your HTML, you should see that you are passing an empty value to your php script.
To fix this, update your hidden input field like this:
<input type="hidden" name="IdArticle" value="<?php echo $rows['artID'] ?>" />
Now it should work.

Answer 2

How do I fetch the primary key from the articles table?
The same as selecting any other column
SELECT `artID` FROM `articles` WHERE `artID` = ?
That's the only question I can see in your post.