Placing another array in my table - php

Question

I currently use 2 arrays to place values in my table like so:
echo "<table>";
foreach ($products as $key => $product){
$number = isset($_POST[$key])?$_POST[$key]:'';
if (!$number){
echo "";
} else {
echo "<tr>";
echo "<td>";
echo $product;
echo "</td>";
echo "<td>";
echo $number;
echo "</td>";
echo "</tr>";
}
}
echo "</table>";
The $product and $number are showing just fine, but my problem is that i need a third column with the $prices in them. Looking like this:
echo "<td>";
echo $price;
echo "</td>";
I made an array for $prices looking like this:
$prices = array(7, 8, 9, 11, 13, 5, 5.50, 6, 0.50, 0.50);
But it gets more complicated.
It needs to be so that $price = $number * $prices.
Meaning that if $number = 5 and $prices = 8 it should place 40 in the $price.
I don't know if this is easy to do or not. But i'd like some help with this since im not really familiar with arrays.
Thanks in advance!

Answer 1

echo "<table>";
$count = 0;
foreach ($products as $key => $product){
$number = isset($_POST[$key])?$_POST[$key]:'';
if (!$number){
$count++;
echo "";
} else {
echo "<tr>";
echo "<td>";
echo $product;
echo "</td>";
echo "<td>";
echo $number;
echo "</td>";
echo "<td>";
$price = $prices[$count] * $number;
echo $price;
echo "</td>";
echo "</tr>";
$count++;
}
}
echo "</table>";