Create checkboxes in php that correspond to MySQL data - php

Question

I have a php script that pulls information out from my database.
$result = mysqli_query($con,"SELECT * FROM menuitem WHERE id='$id' LIMIT 1");
if (!$result) {
printf("Error: %s\n", mysqli_error($con));// Displays the error that mysql will generate if syntax is not correct.
exit();
}
//DYNAMIC PHP PULLING IN THE DATA AND SPITTING OUT THE RESULTS
while($row = mysqli_fetch_array($result))
{
$id = $row['id'];
$description = $row['description'];
$picturepath = $row['picturepath'];
$name = $row['name'];
$price = $row['price'];
$keywords = $row['keywords'];
$dynamiclist = '<table align="center" width="60%" border="0" cellspacing="5" cellpadding="8">
<tr height="150"></tr>
<tr>
<td width="30% valign="top" align="center"><img style="border: #66cc33 5px solid;" src=" ' .$picturepath . '" height="200" width="200" border="1"/></td>
<td width="70%" valign="top" align="left"> <br />' . $name . ' <br /><br />$' . $price . '<br /><br /><font>Description:</font><br /> ' . $description . ' <br /><br /><br />
<form id="form1" name="form1" method="post" action="cart.php">
<input type="hidden" name="keywords" id="keywords" value=" '. $keywords .'"/>
<input type="hidden" name="pid" id="pid" value=" ' . $name . ' - $' . $price . ' "/>
<input type="submit" name="button" id="button" value="Add to Order"/>
</form>
</td>
</tr>
<tr align="center"><td>View Your Order</td></tr>
</table>';
echo $dynamiclist;
}
mysqli_close($con); //close the db connection
?>
And then I have another page where I want checkboxes created for each keyword listed. I'm not sure if I have my db colum set up correctly, but I have a column set up with multiple keywords: first, second, fifty, none, and more.
I've tried creating this, but it only displays actual "checkboxes" with no text next to any of them.
<?php
require("database.php"); //connect to the database
if(isset($_POST['keywords'])){
$pid = $_POST['keywords'];
}
$result = mysqli_query($con,"SELECT * FROM menuitem ");
if (!$result) {
printf("Error: %s\n", mysqli_error($con));// Displays the error that mysql will generate if syntax is not correct.
exit();
}
//DYNAMIC PHP PULLING IN THE DATA AND SPITTING OUT THE RESULTS
$option = '';
while($row = mysqli_fetch_array($result))
{
$id = $row['id'];
$description = $row['description'];
$picturepath = $row['picturepath'];
$name = $row['name'];
$price = $row['price'];
$keywords = $row['keywords'];
$dynamiclist ="<input type='checkbox' name='checkbox' value='". $keywords ."'>";
echo $dynamiclist;
}
The goal is to have a user select an item from the first page, and on the second page, list several checkbox options for that specific item. Any help would be greatly appreciated.

Answer 1

If you want text next to the checkbox, you have to put it in the HTML. And if the column contains a comma-separated list, you need to split it up.
foreach(explode(',', $keywords) as $keyword) {
$keyword = trim($keyword);
echo "<input type='checkbox' name='checkbox' value='$keyword'>$keyword ";
}

Answer 2

Try this:
<?php
$keywords = explode(',', $keywords);
if(!empty($keywords))
{
foreach($keywords as $keyword) {
$keyword = trim($keyword);
echo "<input type='checkbox' name='checkbox' value='$keyword'>$keyword ";
}
}
?>
Thanks!