PDO select and count IN HAVING DISTINCT to appear in dropdown - php

Question

I have this mysql select working great. It returns the proper data. I can't seem to get the context correct to place the actual count of the custnum so it will appear on the end of the dropdown option select.
This statement returns the proper location names
$statement = $pdo->prepare("SELECT locationname FROM location WHERE locationname IN (SELECT locationname FROM location_user WHERE custnum= :custnum GROUP BY locationname HAVING COUNT( DISTINCT email) < 6 )");
$statement->execute(array(':custnum' => $session->custnum));
while($row = $statement->fetch(PDO::FETCH_ASSOC)){
echo'<option value="'.$row['locationname'].'">'.$row['locationname'].'('. $row['COUNT(total)'] .')</option>';
}
Here's one of my attempts to grab the total for each custnum
$statement = $pdo->prepare("SELECT locationname, COUNT(custnum) AS total FROM location WHERE locationname IN (SELECT locationname FROM location_user WHERE custnum= :custnum GROUP BY locationname HAVING COUNT( DISTINCT email) < 6 )");
$statement->execute(array(':custnum' => $session->custnum));
while($row = $statement->fetch(PDO::FETCH_ASSOC)){
echo'<option value="'.$row['locationname'].'">'.$row['locationname'].'('. $row['total'] .')</option>';
}
Here's my tables
table location table location_user
custnum | locationname custnum | locationname | email | userlevel
1 location1 1 location1 1me#you.com 3
1 location2 1 location1 1me#you.com 1
1 location1 2me#you.com 2
1 location1 3me#you.com 2
1 location1 4me#you.com 2
1 location1 5me#you.com 2
1 location2 1me#you.com 2
1 location2 1me#you.com 3
The first select returns
location1()
location2()
The second select returns
location1(2)
I actually need the count of the distinct email which the query is doing and returning only the locationnames of the distinct email in the table less then 6 but how do I get the actual number of distinct emails for each locationname.
This select will retrieve the total for DISTINCT email, but how do I combine the two into one for my while loop?
$statement2 = $pdo->prepare("SELECT COUNT(email) AS total FROM location_user WHERE custnum= :custnum GROUP BY locationname HAVING COUNT( DISTINCT email) < 6");
$statement2->execute(array(':custnum' => $session->custnum));
Here's the working version from the help of Peter and a little prodding from Tin.
$statement = $pdo->prepare("SELECT l.locationname, COUNT(DISTINCT lu.email) AS total
FROM location l LEFT JOIN location_user lu ON l.locationname = lu.locationname AND l.custnum = lu.custnum WHERE l.custnum = :custnum GROUP BY l.locationname HAVING COUNT(DISTINCT lu.email) < 5 ");
$statement->execute(array(':custnum' => $session->custnum));
while($row = $statement->fetch(PDO::FETCH_ASSOC)){
echo'<option value="'.$row['locationname'].'">'.$row['locationname'].'('. $row['total'] .')</option>';
}
Here's another version that I'm working on to skip the user that adds the locations to the table. This user will always have a userlevel > 2. The uselevel is placed in the location_user table only as a value between 1-9. So I still need the location name but I don't want their location included in the count. I just realized that I could actually go a better route because the only email that I want to count will have a userlevel of 2. I was using the distinct email to filter out the userlevel of 1. I'll give it a go. The below version drops my locations that arn't in the location_user table but it's returning the proper count.
SELECT l.locationname, COUNT(lu.userlevel) AS total
FROM location l LEFT JOIN location_user lu
ON l.locationname = lu.locationname
AND l.custnum = lu.custnum
WHERE l.custnum = :custnum
AND lu.userlevel = 2
GROUP BY l.locationname
HAVING COUNT(lu.userlevel) < 6

Answer 1

UPDATE2: based on your comments. Try it this way
SELECT l.locationname, COUNT(DISTINCT lu.email) AS total
FROM location l LEFT JOIN location_user lu
ON l.locationname = lu.locationname
AND l.custnum = lu.custnum
AND lu.userlevel < 3 -- consider only users with user level < 3
WHERE l.custnum = ?
GROUP BY l.locationname
HAVING COUNT(DISTINCT lu.email) < 6
Sample output:
| LOCATIONNAME | TOTAL |
|--------------|-------|
| location1 | 5 |
| location2 | 1 |
| location3 | 0 |
Here is SQLFiddle demo

Answer 2

you don't actually need to query from table location since you already have locationname field from table location_user
SELECT locationname, count(DISTINCT email) as total FROM location_user WHERE custnum = :custnum GROUP BY locationname HAVING count(DISTINCT email) < 6