I am sure the answer is right in front of me, but I have a UTC dateTime that looks like this:
2014-01-02 04:02:58
All I want to do is add some hours to that.
How can I achieve this in PHP? Further, how would I add days to it if I wanted to?
Use DateTime(). Unlike date()/strtotime() it is timezone and daylight savings time friendly.
// PHP 5.2+
$dt = new DateTime('2014-01-02 04:02:58');
$dt->modify('+2 hours');
echo $dt->format('Y-m-d H:i:s');
$dt->modify('+2 days');
echo $dt->format('Y-m-d H:i:s');
See it in action
Or
// PHP 5.3+
$dt = new DateTime('2014-01-02 04:02:58');
$dt->add(new DateInterval('PT2H'));
echo $dt->format('Y-m-d H:i:s');
$dt->add(new DateInterval('P2D'));
echo $dt->format('Y-m-d H:i:s');
See it in action
Or
// PHP 5.4+
echo (new DateTime('2014-01-02 04:02:58'))->add(new DateInterval('PT2H'))->format('Y-m-d H:i:s');
See it in action
Reference:
DateTime()
DateInterval()
You can use strtotime() try like this :
echo $new_time = date("Y-m-d H:i:s", strtotime( "2014-01-02 04:02:58".'+3 hours'));
Related
When I run the following code in codeigniter, it returns incorrect time and date for the India location. Please let me the solution.
'date_default_timezone_set('Asia/Kolkata');
$date = date('Y-m-d H:i:s', time());
echo $date;'
try this
$now = new DateTime();
$now->setTimezone(new DateTimezone('Asia/Kolkata'));
echo $now->format('Y-m-d H:i:s');
I get how to use strtotime, but I first need to set a timezone, which is causing an issue:
$date = new DateTime();
$date->setTimezone(new DateTimeZone('America/New_York'));
$idate = $date->format('Y-m-d H:i:s');
$fdate=strtotime($idate,"+2 hours");
$idate comes out fine, in the correct timezone, in this format: 2016-07-25 15:56:24
How can I add 2 hours onto this and return a variable in the same format?
Try this:
$fdate=date('Y-m-d H:i:s',strtotime($idate."+2 hours"));
Using your $date, you can do:
$date = $date->add(new DateInterval('PT2H'));
and then format it as you like.
I need to set timestamp eg. 4 hours ahead and 2 hours ahead separately
In my database, I have their columns as timestamp.
I know I could do something similar to this but am not sure if it's correct.
// For 4 hours ahead of time
$dt2 = date("Y-m-d 04:i:s");
//For 2 days ahead
$dt2 = date("Y-m-02 H:i:s");
//For 4 hours ahead of time
$dt2 = date("Y-m-d H:i:s", strtotime('+4 hours'));
//For 2 days ahead of time
$dt2 = date("Y-m-d H:i:s", strtotime('+2 days'));
In my mind it's much better to work with DateTime field and the DateTime class.
You have the ability so modify that objects very easily. For example:
$aktDate = new \DateTime();
Now you have the actual date and time in an object. If you want you can put a string insight the DateTime function so set your date manually.
$aktDate = new \DateTime('Y-m-d 04:i:s');
Not you can modify your dates if you want with the modify function.
in your case:
$pastDate = clone $aktDate;
$pastDate->modify('+2 days');
$futureDate = clone $aktDate;
$futureDate->modify('+4 days');
if($pastDate < $aktDate && $aktDate < $futureDate) {
// do something
}
I like the DateTime function much more because it's readable and you can work directly with your DateTime fields from your MySQL database if you have such fields. You can write that example much shorter but so you have better readability.
$date = new DateTime('now');
$date->modify('+2 days');
echo $date->format('Y-m-d H:i:s');
$date = new DateTime('now');
$date->modify('+4 hours');
echo $date->format('Y-m-d H:i:s');
You need to use the strtotime() function (http://php.net/manual/en/function.strtotime.php).
For your examples:
//+2 hours<br>
strtotime("+2 hours");
// +2 days<br>
strtotime("+2 days")
Edit: for what you ask, about posted values, the syntax is like this:
strtotime("+2".$_POST['field_name']." days");
You can use hours/days/months/weeks/years and either + or -
I have today date and i want to reduce hours\days from it. i get the "hours to reduce interval" in int that indicate number of days.
I tried something like this:
$today_date = date('Y-m-d H:i:s');
$temp_interval_date = $settings->days_back;
$interval_date = date('H',$temp_interval_date*24);
$final = $temp_interval_date - $interval_date;
My final goal is to get todaydate - interval period in this format
'Y-m-d H:i:s'
I am c# dude :)
Thanks
I'm not entirely clear on what you're asking but I think this is what you're looking for.
$date = new DateTime();
$date->sub(new DatePeriod('P'.$settings->days_back.'D'));
echo $date->format('Y-m-d H:i:s');
You can also do (if you're using PHP 5.2)
$date = new DateTime();
$date->modify('-' . $settings->days_back . ' days'));
echo $date->format('Y-m-d H:i:s');
reference
DateTime()
DatePeriod()
maybe this could be helpful:
echo date('Y-m-d', strtotime('-1 day', date('Y-m-d') ));
Another way to do it
<?php
$temp_interval_date = 2; //in hours (for example =2)
echo date('Y-m-d H:i:s', strtotime('-'.($temp_interval_date*24).' hours',strtotime(date('Y-m-d H:i:s'))));
?>
In certain situations I want to add 1 day to the value of my DATETIME formatted variable:
$start_date = date('Y-m-d H:i:s', strtotime("{$_GET['start_hours']}:{$_GET['start_minutes']} {$_GET['start_ampm']}"));
What is the best way to do this?
There's more then one way to do this with DateTime which was introduced in PHP 5.2. Unlike using strtotime() this will account for daylight savings time and leap year.
$datetime = new DateTime('2013-01-29');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.3
$datetime = new DateTime('2013-01-29');
$datetime->add(new DateInterval('P1D'));
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.4
echo (new DateTime('2013-01-29'))->add(new DateInterval('P1D'))->format('Y-m-d H:i:s');
// Available in PHP 5.5
$start = new DateTimeImmutable('2013-01-29');
$datetime = $start->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
If you want to do this in PHP:
// replace time() with the time stamp you want to add one day to
$startDate = time();
date('Y-m-d H:i:s', strtotime('+1 day', $startDate));
If you want to add the date in MySQL:
-- replace CURRENT_DATE with the date you want to add one day to
SELECT DATE_ADD(CURRENT_DATE, INTERVAL 1 DAY);
The DateTime constructor takes a parameter string time. $time can be different things, it has to respect the datetime format.
There are some valid values as examples :
'now' (the default value)
2017-10-19
2017-10-19 11:59:59
2017-10-19 +1day
So, in your case you can use the following.
$dt = new \DateTime('now +1 day'); //Tomorrow
$dt = new \DateTime('2016-01-01 +1 day'); //2016-01-02
Use strtotime to convert the string to a time stamp
Add a day to it (eg: by adding 86400 seconds (24 * 60 * 60))
eg:
$time = strtotime($myInput);
$newTime = $time + 86400;
If it's only adding 1 day, then using strtotime again is probably overkill.
You can use
$now = new DateTime();
$date = $now->modify('+1 day')->format('Y-m-d H:i:s');
You can use as following.
$start_date = date('Y-m-d H:i:s');
$end_date = date("Y-m-d 23:59:59", strtotime('+3 days', strtotime($start_date)));
You can also set days as constant and use like below.
if (!defined('ADD_DAYS')) define('ADD_DAYS','+3 days');
$end_date = date("Y-m-d 23:59:59", strtotime(ADD_DAYS, strtotime($start_date)));
I suggest start using Zend_Date classes from Zend Framework. I know, its a bit offtopic, but I'll like this way :-)
$date = new Zend_Date();
$date->add('24:00:00', Zend_Date::TIMES);
print $date->get();
Using server request time to Add days. Working as expected.
25/08/19 => 27/09/19
$timestamp = $_SERVER['REQUEST_TIME'];
$dateNow = date('d/m/y', $timestamp);
$newDate = date('d/m/y', strtotime('+2 day', $timestamp));
Here '+2 days' to add any number of days.
One liner !
echo (new \DateTime('2016-01-01 +1 day'))->format('Y-m-d H:i:s');