Getting the option value without using submit button - php

Question

Good day. Im trying to have some functionality on my project, but im stuck with this.
I want to display my database depending on what the user select
Here is my html code:
<table>
<tr><td>Select Request Status:</td>
<td><select class="form-control" name="status" style="width:200px;">
<option value="1">Pending Request</option>
<option value ="2">Requests On-Process</option>
<option value="3">Unassigned Requests</option>
<option>All Requests</option>
</select></td>
</tr>
</table>
And here is my php code:
if ($status = $_SESSION['status'] == 'Pending Request')
{
$query = "select * from tblrequest where status='Pending Request'";
$request = mysql_query($query)or die(mysql_error());?>
<table class="table">
<tr>
<th>Request ID</th>
<th>Requestor</th>
<th>Department</th>
<th>Category</th>
<th>Assigned to</th>
<th>Status</th>
<th>Created Date</th>
<th>Created Time</th>
</tr>
<?php while($row = mysql_fetch_array($request)){
?>
<tbody class="table table-hover">
<tr>
<td style="width:100px;"><?php echo $row['RequestNumber']; ?></td>
<td style="width:100px;"><?php echo $row['Requestor']; ?></td>
<td style="width:100px;"><?php echo $row['Department']; ?></td>
<td style="width:50px;"><?php echo $row['category']; ?></td>
<td style="width:100px;"><?php echo $row['AssignedTo']; ?></td>
<td style="width:100px;"><?php echo $row['status']; ?></td>
<td style="width:100px;"><?php echo $row['DateRequested']; ?></td>
<td style="width:100px;"><?php echo $row['TimeRequested']; ?></td>
</tr>
</tbody>
<?php
}
}?>
Im a newbie to php so please help me.

Answer 1

Can you try this,
HTML:
<form method="post">
<table>
<tr><td>Select Request Status:</td>
<td>
<?php $Statuses = array("0"=>"All Requests", "1"=>"Pending Request", "2"=>"Requests On-Process", "3"=>"Unassigned Requests" );?>
<select class="form-control" name="status" style="width:200px;" onchange="this.form.submit();">
<?php foreach($Statuses as $key=>$status):?>
<?php
$selected ="";
$statusPost = $_POST['status'];
if($key == $statusPost): $selected =" selected"; endif;
?>
<option value="<?php echo $key;?>" <?php echo $selected;?>><?php echo $status;?></option>
<?php endforeach;?>
</select></td>
</tr>
</table>
</form>
PHP:
if (isset($_POST['status'])){
$status= $_POST['status'];
$Where ='';
if($status!='0'){
$Where =" where status='".$Statuses[$status]."' ;
}
}
$query = "select * from tblrequest $Where";
$request = mysql_query($query)or die(mysql_error());?>
<table class="table">
<tr>
<th>Request ID</th>
<th>Requestor</th>
<th>Department</th>
<th>Category</th>
<th>Assigned to</th>
<th>Status</th>
<th>Created Date</th>
<th>Created Time</th>
</tr>
<?php while($row = mysql_fetch_array($request)){
?>
<tbody class="table table-hover">
<tr>
<td style="width:100px;"><?php echo $row['RequestNumber']; ?></td>
<td style="width:100px;"><?php echo $row['Requestor']; ?></td>
<td style="width:100px;"><?php echo $row['Department']; ?></td>
<td style="width:50px;"><?php echo $row['category']; ?></td>
<td style="width:100px;"><?php echo $row['AssignedTo']; ?></td>
<td style="width:100px;"><?php echo $row['status']; ?></td>
<td style="width:100px;"><?php echo $row['DateRequested']; ?></td>
<td style="width:100px;"><?php echo $row['TimeRequested']; ?></td>
</tr>
</tbody>
<?php
}
?>

Answer 2

put select dropdown in a form with id,action,method etc.
give id to a select element(say "mySelect")
Now, in jquery,
$("#mySelect").on("change",function(){
if($("#mySelect").val() != ""))
{
$("#form1").submit();
}
})