MySQL Prepared Statement, write multiple rows - php

Question

So far I have used prepared statements to get ONE row from a database. But how do I write multiple rows onto the page. Looked online and people only seem to be showing how to get the one row.
if ($count_sets->num_rows > 0) {
$query = "SELECT id,jpg,udate,imageset FROM images WHERE dodelete = ? AND udate = ? AND imageset = ?";
if ($stmt = $mysqli->prepare($query)) {
//echo "Prepare failed: (" . $mysqli->errno . ") " . $mysqli->error;
$stmt->bind_param("isi",$deleted,$session_date,$imageset);
$stmt->execute();
$stmt->store_result();
//Get result
$stmt->bind_result($result_id,$result_jpg,$result_date,$result_imageset);
//Number of rows returned
$count_rows = $stmt->num_rows;
}
} else {
echo "No images to process, do an upload first!";
}
$folder = str_replace("/", "", $session_date);
if ($count_rows > 0) {
echo "hel<br />";
echo $result_jpg[0];
}

Answer 1

Found some example code:
$db = new mysqli("host","user","pw","database");
$stmt = $db->prepare("SELECT * FROM mytable where userid=? AND category=? ORDER BY id DESC");
$stmt->bind_param('ii', intval($_GET['userid']), intval($_GET['category']));
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($column1, $column2, $column3);
while($stmt->fetch())
{
echo "col1=$column1, col2=$column2, col3=$column3 \n";
}
$stmt->close();
It's the following part I didn't know how to do.
while($stmt->fetch())
{
echo "col1=$column1, col2=$column2, col3=$column3 \n";
}