There is a property $modelName in class A that is accessed in this class using $this->modelName.
This property contains a name of another class B.
I want to call a static method of class B not creating an object of B.
Working code:
$b = $this->modelName;
$b::model()->findAll();
Question:
How to call model()->findAll() not using $b?
I tried $this->modelName::model()->findAll(); but it’s not working.
Do it:
class A{
public $modelName = 'B';
function callB(){
call_user_func(array($this->modelName, 'model'))->findAll();
}
}
class B{
private static $model = null;
static function model(){
if (!self::$model) {
self::$model = new B();
}
return self::$model;
}
function findAll(){
print __CLASS__.' method `findAll()`';
}
}
$A = new A;
$A->callB();
// B method `findAll()`
Related
I am working on an application and I have run into this dilemma. Below is a very simplified version but I am wondering if its possible
Example:
class A{
public $test = null;
public function method1(){
$this->test = 'finished';
}
}
class B extends A{
public function getMethod1Test(){
return $this->test;
}
}
$a = new A();
$a->method1();
$b = new B();
$b->getMethod1Test(); //this currently returns NULL
How can I modify this such that it returns the value 'finished' without reinserting the modified value into class B?
Thanks
If you create class A like this..
class A{
public $test = null;
public function __construct(){ // constructor
$this->test = 'finished';
}
}
I haven't tested it though but should work.
Consider the following snippet:
Class A {
private $a = 'foo';
public function F() {
return $this->a;
}
}
Class B extends A {
private $a = 'bar';
}
echo (new B)->F();
The result is foo. Well, it's a fait accompli that php works this way. But I wonder why. If in parent's method F() declaration I use pseudo-variable $this, it refers to object context. So when I call child inherited method F() $this variable means current instance of B with private $a = 'bar', doesn't it?
Update
Thanks AbraCadaver for your reply.
One circumstance is still unclear for me: if $this variable is an object of B during call of F(), how can it access parent's private member?
Did I understand correctly that $this within parent's method implementation is something similar to:
public function F(B $obj) {
return $obj->a;
}
So interpreter checks property visibility from parent class and in case of private scope it subsitutes B $obj for A $obj
From PHP: Visibility:
Members declared
protected can be accessed only within the class itself and by
inherited and parent classes. Members declared as private may only be
accessed by the class that defines the member.
In your example, regardless of the object being of class B, class A cannot access a private property of another class.
Also, if B has a protected property, that cannot override the class A property because it is private.
Both your example and the following yield foo:
Class A {
private $a = 'foo';
public function F() {
return $this->a;
}
}
Class B extends A {
protected $a = 'bar';
public function F() {
return parent::F();
}
}
echo (new B)->F();
However, if class A is also protected then it can be overridden by class B and class A has access to the property in class B.
Yields bar:
Class A {
protected $a = 'foo';
public function F() {
return $this->a;
}
}
Class B extends A {
protected $a = 'bar';
public function F() {
return parent::F();
}
}
echo (new B)->F();
I'm new to programming. I have this going on:
I have Class A, which have many functions. One of those functions is functionX.
In functionX I need to make a call to functionY which belongs to another class: Class B.
So how do I acces to functionY from inside functionX?
I use Codeigniter.
Thanks in advance.
Try and experiment with this.
class ClassA {
public function functionX() {
$classB = new ClassB();
echo $classB->functionY();
}
}
class ClassB {
public function functionY() {
return "Stahp, no more OO, stahp!";
}
}
Class function? A static method?
If you have an instance (public) method, you just call $classB->functionY().
If you have a static method, you would call ClassB::functionY();
So:
class ClassA {
public function functionX(){
$classB = new ClassB();
// echo 'foo';
echo $classB->functionY();
// echo 'bar';
echo ClassB::functionYStatic();
}
}
class ClassB {
public $someVar;
public static $someVar2 = 'bar';
function __construct(){
$this->someVar = 'foo';
}
public function functionY(){
return $this->someVar;
}
public static function functionYStatic(){
return self::$someVar2;
}
}
Well that depends. If that function is a static function or not.
First off you must include the file with the class...
include_once('file_with_myclass.php');
If it is static you can call it like this:
ClassName::myFunction()
If it is not, then you create an instance of the class and then call the function on that instance.
$obj = new ClassName();
$obj->myFunction();
As you can guess the function being static means you can call it without the need of creating an instance. That is useful for example if you have a class Math and want to define a function that takes to arguments to calculate the sum of them. It wouldn't really be useful to create an instance of Math to do that, so you can declare as static and use it that way.
Here's a link to the docs with further info
http://www.php.net/manual/en/keyword.class.php
If functionY is static you can call ClassB::functionY(). Else you must create instance of Class B first. Like:
$instance = ClassB;
$instance->functionY();
But maybe you mean something else?
Looks like one of your class has a dependency to another one:
<?php
class A
{
public function x()
{
echo 'hello world';
}
}
class B
{
private $a;
public function __construct(A $a)
{
$this->a = $a;
}
public function y()
{
$this->a->x();
}
}
$a = new A();
$b = new B($a);
$b->y();
Depending how your code looks like, if it makes sense, you can inject class A into y()
public function y(A $a)
{
// your code with $a
}
I code something like this to give you an example
This is using "$this->"
<?php
class A{
public function example(){
echo "A";
}
}
class B extends A{
public function example2(){
$this->example();
}
}
$b = new B();
echo $b->example2();
?>
and This is using parent::
<?php
class A{
public function example(){
echo "A";
}
}
class B extends A{
public function example2(){
parent::example();
}
}
$b = new B();
echo $b->example2();
?>
What is different between $this-> and parent:: in OOP PHP?
The difference is that you can access a function of a base class and not of the currient implementation.
class A {
public function example() {
echo "A";
}
public function foo() {
$this->example();
}
}
class B extends A {
public function example() {
echo "B";
}
public function bar() {
parent::example();
}
}
And here some tests:
$a=new A();
$a->example(); // echos A
$a->foo(); // echos A
$b=new B();
$b->example(); // echos B
$b->foo(); // echos B
$b->bar(); // echos A
parent::example() calls the parent class method, where $this->example() call the current class method.
In your example there's no difference, since class B doesn't override example() method. It is common to write something like this (maybe it will help you to understand better this concept):
class A {
public function example(){
echo 'A';
}
}
class B extends A {
public function example(){
echo 'B';
}
public function example2(){
$this->example();
}
public function example3() {
parent::example();
}
}
$b = new B();
$b->example2();//print B
$b->example3();//print A
In simple words
$this is an instance reference, so whenever you use $this it starts referencing current class methods and properties.
parent is a parent reference which can be used to access parent class properties and methods with public or protected access modifier.
parent:: will call a method or an attribute of the parent. However, since this is refering to the class and not any kind of instance, you can only call a static method or attribute.
$this-> refers to the current instance of the object you call this in.
You could also want to refer to self:: which refers to the current class (once again, no instance involved here) within an object or a static method.
I have a class which initiates another class, i'm not concerned with having a reference to the object i only need the method and have to pass in new parameters.
class A {
__set .....
}
class B extends A {
$anotherA = new A;
$anotherA->myName = 'stackoverflow';
}
in short i'd like to have class B extend A, init a new instance of A but i don't want to have to type "new" everytime, i've seen the following syntax:
B::A // something like that
but not sure if how to use it or if that would do what i'm trying to do?
What you could do is define a static method on the class that returns the new instance. It's basically a 'shortcut', but it does exactly the same in the background.
class C {
public static function instance()
{
return new C();
}
public function instanceMethod()
{
echo 'Hello World!';
}
}
Now you can call it like:
C::instance()->instanceMethod();
Here are some examples of static functions - they can be called without using 'new A' or 'new B'.
class A {
static function message($msg = 'I am Alpha') {
echo "hi there, $msg\n";
}
}
class B {
static function message() {
A::message("I am Beta");
}
}
A::message();
B::message();
I would create the instance of A in B's constructor, then you can instantiate B using either its constructor or static B::create(), which just acts as a shortcut. You could make the constructor private if you wanted all instantiation go through create().
class A {
// __set .....
}
class B extends A {
public function __construct() {
parent::__construct();
$anotherA = new A;
$anotherA->myName = 'stackoverflow';
}
public static function create() {
return new self();
}
}
new B();
B::create();
Since you are extending A in B, you could call the method of class A:
class B extends A {
public function someMethod() {
parent::someMethodName();
}
}
Alternatively, you could create a static method in the class:
class A {
public static function someStaticMethod() { ... }
}
A::someStaticMethod();
If you really want a new instance of A, you have to use the new operator. That's what it is for.