How to print PHP line inside echo - php

Question

I'm creating a Dynamic Navigation using PHP, and i want to insert a php code inside a php code
on an <li>, i want to insert this line of code inside a list item
<?php printf('<li' if (strpos($_SERVER['PHP_SELF'], 'index.php')) echo 'class="current"';>); printf('%s %s </a></li> ', $row['name'],$row['DESCRIPTION']); } ?>

Answer 1

Wouldn't be better this way (?):
$content = "<li ";
if (strpos($_SERVER['PHP_SELF'], 'index.php')){
$content .= "class='current'";
}
$content .= "> </a></li>" . $row['name'] . " " . $row['description'];

Answer 2

Try this way:
<?php
$index = ((strpos($_SERVER['PHP_SELF'], 'index.php')) ? true : false);
printf('<li' . (($index) ? 'class="current"' : '' ) . '%s %s </a></li> ', $row['name'],$row['DESCRIPTION']);
?>

Answer 3

<?php
printf('<li' . (strpos($_SERVER['PHP_SELF'], 'index.php')) ? 'class="current"' : '' . '>');
printf('%s %s </a></li> ', $row['name'], $row['DESCRIPTION']);
?>

Answer 4

$is_current = '';
if(strpos($_SERVER['PHP_SELF'], 'index.php')){ $is_current = 'class="current"'; }
printf('<li'.$is_current.'>%s %s </a></li>', $row['name'],$row['DESCRIPTION']);

Answer 5

Not totally clear what you are asking, but I guess you can get what you want writing it differently, e.g.
<?php
echo "<li ";
if (strpos($_SERVER['PHP_SELF'], 'index.php')) {
echo ' class="current"';
}
// missing: '><a ...>'
printf(' %s %s </a></li> ', $row['name'], $row['DESCRIPTION']);
?>
(there's a final } without an opening {, I've just stripped it, without asking myself if it had to be the closing } of the missing opening { of the if).
Or you can use the ?: operator.

Answer 6

For good pratices and best identification in your code, try this:
if (strpos($_SERVER['PHP_SELF'], 'index.php')){
$class = "";
}else{
$class = "current";
}
printf('<li class="current"> %s %s </a></li>', $row['name'], $row['DESCRIPTION']);