php solution too huge if statement - php

Question

Is there a way that I can approach this to some other solution?
I have 7 arrays (monday, tuesday, wednesday, thrusday, friday, saturday, sunday).
Each one of this arrays have arrays inside of them. and I need to check if all days have the same amount of data.
So im comparinng something like this:
if(count($monday) == count($tuesday)){
if(count($tuesday) == count($wednesday)){
if(count($wednesday) == count($thursday)){
if(count($thursday) == count($fruday)){
if(count($fruday) == count($saturday)){
if(count($saturday) == count($sunday)){
echo 'ok whole week is the same';
}
else{
//print sunday
//compare the rest which could print and keep comparing rest of the days
}
}
else{
//print saturday and comapre
}
}
else{
//print friday and compare
}
}
else{
//print thurdasy and compare
}
}
else{
//print wednesday and compare
}
}
else{
//print tuesday and compare
}
}
else{
//print monday
//compare rest of the days
}
As you can see it would become a huge if statement tree, I dont have that much of experience to know any other approach to this, but id you do, please help me!
thank you!

Answer 1

Use $diff = array_diff($monday,$tuesday,$wednesday, etc...);
$diff will contain the differences if there are any...

Answer 2

$bol = 0;
if(count($monday) == count($tuesday)){
$bol = $bol+1
} else {print $moday;}
//continue for all weeks
if ($bol ==6) {
echo 'ok whole week is the same';
}

Answer 3

How about this:
<?php
echo "<pre>";
$days = array('sunday' => array(1,2), 'saturday' => array(1,2,3), 'friday' => array(1,2,3,5), 'thursday' => array(1,2,3), 'wednesday' => array(1,2,3,4,5,6), 'tuesday' => array(1), 'monday' => array(1,2, 3,4,5,6,7,8));
//Create a count array
$count = array();
//populate count array
foreach ($days as $k => $v)
{
$count[$k] = count($v);
}
//reverse sort it
arsort($count);
//if both end of array elements are the same all are the same
if (reset ($count) == end($count))
{
echo 'ok whole week is the same';
} else {
foreach ($count as $d => $c)
{
echo $d . ": " . implode ( ", " , $days[$d] ) . "\n";
}
}
echo "</pre>";
?>
Initial array of days:
Array
(
[sunday] => Array
(
[0] => 1
[1] => 2
)
[saturday] => Array
(
[0] => 1
[1] => 2
[2] => 3
)
[friday] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 5
)
[thursday] => Array
(
[0] => 1
[1] => 2
[2] => 3
)
[wednesday] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
)
[tuesday] => Array
(
[0] => 1
)
[monday] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
[6] => 7
[7] => 8
)
)
and Output:
monday: 1, 2, 3, 4, 5, 6, 7, 8
wednesday: 1, 2, 3, 4, 5, 6
friday: 1, 2, 3, 5
thursday: 1, 2, 3
saturday: 1, 2, 3
sunday: 1, 2
tuesday: 1

Answer 4

This solution uses the fact that the two comparison variables are quite predictable (ie. a single day is compared with the very next day).
All the daily arrays are placed into a single weekly array, which is then looped over. If there is a discrepancy, the contents of the last variable are displayed and the loop continues.
If there are no discrepancies then the success message is displayed.
<?php
$bIsCorrect = true;
$weeks_array = array($monday,$tuesday,$wednesday,$thursday,$friday,$saturday,$sunday);
//Loop through weeks starting from $monday and going only to $saturday
for($i=0,$max_count=6; $i<$max_count; $i++) {
if(count($weeks_array[$i]) != count($weeks_array[$i+1])) {
$bIsCorrect = false;
$array_text = var_export($weeks_array[$i+1], true);
echo "Discrepancy : <br> $array_text";
echo "<hr>";
}
}
if($bIsCorrect) {
echo "ok whole week is the same";
}