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I'm a PHP newbie trying to debug someone's code. The very first line of the code has what I think is a constant as shown below:
<?php
set_time_limit (0);
require_once (SITE_PATH. '/server/php/libs/dbase/handler.php');
I have written a debug statement and I have gotten a null.
echo "SITE_PATH"
How should PHP constants be declared. Should'nt the require statement be $SITE_PATH instead of SITE_PATH?
php constants must be defined as :
define('SITE_PATH','http://localhost/site');
and are used as :
echo SITE_PATH;
Look at this : php constants
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$b=number_format($number[12],2);
$sql01=mysql_query("UPDATE t_maindbfordashboard SET valueVar=".$a." WHERE managementName=dds");
I am absolutely sure that there are no problems connecting to the database or such. This query works when I try "SELECT * FROM tableName". Where do you think I'm making a mistake?
Ask if you need more help, and side note be careful with the sql, yours can be injected.
$b=number_format($number[12],2);
$sql01= $MysqliHandler->prepare('UPDATE t_maindbfordashboard SET valueVar=? WHERE managementName="dds"');
$sql01->bind_param('s', $b); //you typed $a here but where is that value from? guess its $b?
$sql01->execute();
$sql01->close();
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I am learning PHP. Currently, I have:
<?php
echo "<p>This text was brought to you by PHP.</p>";
?>
What this does is outputs "This text was brought to you by PHP." and then on the next line: "; ?>
I cant figure out what i'm doing wrong, the code is seemingly correct.
PS. I made sure its a php file.
You cannot run a php file off the filesystem (file://) you need to install a web server with php enabled and then the server side code will run.
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Is there way to create database in one file?
I have a PHP script, is there possible to use PHP
syntax (as Apache) to read correct data from one
single database file?
Something like: http://www.sqlite.org/about.html But this requires more than 1 file.
You can use just simple Comma Separated Vlaues (CSV) file.
PHP has several standart function to work with CSV-files data:
fgetcsv;
fputcsv.
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Can someone please explain to me what this piece of php code means.
echo "<a href='product.php?product_id".$product_id."'>
Is it saying that the link is taken from a variable from the product.php page and its named $product_id?
This is a GET parameter in the URL (it's also wrong btw). Say $product_id = 1.
echo "<a href='product.php?product_id".$product_id."'>
This would be "product.php?product_id1"
echo "<a href='product.php?product_id=".$product_id."'>
This would be "product.php?product_id=1", which would would handle by using
$_GET["product_id"]; //yields 1
Ths snippet outputs an HTML <a> tag. The $product_id is a variable, and echo is the command to output a string.
But I'd recommend to follow some basic Tutorials about HTML and PHP, as these are some of the most basic things.
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I am trying to separate my code into functions to make it more readable.
I made a function to update a field in a database. What I am trying to do is that when they change the username it goes to update Account function then updates the session variable , the smarty var,and the database regarding the name.
Everything gets updated after the form is submitted but the smarty variable and I can't figure out why(i know its something to do with the scope) because if i declare it out of the function it works fine.
All the magic that i need fixed is in the Home portion of the routing section of my code. Thank you for any help :)
code :http://pastebin.com/VdRPz3hc