Adding comments to a database based on id - php

Question

I am making a recipe site at the moment and am struggling to get my comment function to work, I previously had it working until but now I keep getting an error which tells me I cannot access the database when I try and submit a comment
I know this might seem quite simple but I'm completely stuck I've been trying to figure out a way round this for weeks but really am not making any headway..
Here the PHP process:
if (!$db_server){
die("unable to Connect to MYSQL: " . mysqli_connect_error($db_server));
$db_status = "not connected";
}else{
if(trim($_POST['submit']) =="submit"){
}else{
if (isset($_POST['dropoption']) && ($_POST['dropoption'] != '')){
if (isset($_POST['meal']) && ($_POST['meal'] != '')) {
$dropoption = clean_string($db_server, $_POST['dropoption']);
$meal = clean_string($db_server, $_POST['meal']);
$quer = "SELECT * FROM `recipename` WHERE `cuisine_type` ='$dropoption' AND `b_l_d` ='$meal'LIMIT 0,1";
mysqli_select_db($db_server, $db_database);
$querya= mysqli_query($db_server, $quer);
if (!$querya) die("database access failed: " . mysqli_error($db_server));
while($row = mysqli_fetch_array($querya)){
$recipeid .= $row['recipeid'];
$recipename .="<h1>". "Why dont you have ".$row['mealname']."</h1>";
$ingredients .="<p>".$row['ingredients']."</p>";
$recipe .="<p>" .$row['recipe']."</p>";
$cookingtime .="<h4>" .$row['hours']." Hours".$row['minutes']." Minutes </h4>";
$mealpic .="<img src='http://ml11maj.icsnewmedia.net/Workshops/Week%207/".$row['imagepath']."'/>";
}
if ($comment != ''){
$userid = trim($_SESSION['userid']);
$comment = trim($_POST['comment']);
$userid = clean_string($db_server, $_SESSION['userid']);
$comment = clean_string($db_server, $_POST['comment']);
$query = "INSERT INTO Comments (comment,userid,recipeid) VALUES ('$comment','$userid','$receipeid')";
mysqli_select_db($db_server, $db_database);
mysqli_query($db_server, $query) or
die("Insert failed: " . mysqli_error($db_server));
}
}//if(meal)//
}//if(cuisine)//
} //if(trim)//
}
$query = "SELECT * FROM Comments";
$result = mysqli_query($db_server, $query);
if (!$result) die ("Database access failed: " . mysqli_error($db_server));
while($row = mysqli_fetch_array($result)) {
$str_comments .= "<p>" . $row['comment'] . "</p>";
}
and here is the html form:
<?php echo $recipename;
echo $mealpic;
?>
<h2>Ingredients</h2>
<?php
$ingredientchunks = (explode(",",$ingredients));
for($i = 1; $i < count($ingredientchunks); $i++){
echo "$i.$ingredientchunks[$i] <br/>";}
echo $cookingtime;
?>
<h2>Recipe</h2>
<?php
$recipechunks = (explode(",",$recipe));
for($i = 1; $i < count($recipechunks); $i++){
echo "$i.$recipechunks[$i] </br>";}
?>
<form id="results" form method="post" action="results.php">
<input type="submit" id="Like" name="Like" value="Like" />
<input type="submit" id="Next" name="Next" value="Next" />
</form>
<div id=Comments>
<form id="comments" form method="post" action='results.php?cuisine_type=" . $dropoption ."b_l_d=" . $meal . "'>
Comment: <textarea rows="2" cols="30" name="comment" id="comment" placeholder="Anything to say??"></textarea>
<input type="submit" id="comments" name="comments" value="comments" />
</form>
<?php
echo $str_comments;
require_once "db_close.php";
?>
</div>
</p>
<? require_once ('home_stop.php')?>