How to display certain comments stored on a database - php

Question

I've created a form for a comment box that I'm going to use on a couple of different pages. It sends the data to a table called "comments" in my database that has columns "id" "author" "body" "created" and "page_name". I'm new to php and I'm trying to figure out how to just display the comments that have the same "page_name" value as the current page.
To get the "page_name", I used this code in the form:
<input type="hidden" name="page_name" value="<?=$_SERVER['REQUEST_URI']?>" />
This is the code I'm building to display the comments:
<div id="comments">
<?php foreach($comments as $comment): ?>
<div class="comment" style="margin-bottom: 2em;">
<div class="author">
<b><?php echo htmlentities($comment->author); ?>:</b>
</div>
<div class="meta-info" style="font-size: 0.8em;">
<?php echo datetime_to_text($comment->created); ?>
</div>
<div class="body">
<?php echo strip_tags($comment->body, '<strong><em><p>'); ?>
</div>
</div>
<?php endforeach; ?>
<?php if(empty($comments)) { echo "No Comments."; } ?>
</div>
I'm just not sure how to tell the page to display only the comments that have the same "page_name" value as the page the user is on. Any help would be appreciated!

Answer 1

You have to query the data corresponding to the url like.
For database connection use the code below:
<?php
// Create connection
$db_con=mysql_connect('servername','db username','dbpassword');
if (!$db_con)
{
die('Could not connect: ' . mysql_error());
}
$connection_string=mysql_select_db('db name',$db_con);
?>
For query use the code:
$url=$_SERVER['REQUEST_URI'];
$query=mysql_query("select * from comments where page_name='".$url."'");
while($result=mysql_fetch_row($query))
{
echo $result[0]."<br>".$result[1]."<br>"; // echo all values that are needed for displaying. You can do the coding for displaying formatted values inside this loop.
}