Append a div without refreshing jquery - php

Question

I want to add a div without refreshing the page.
Here is my Javascript:
<input class="btnsubmit" type="button" value="+Add Trivia" id="add_triviamodal">
function add_trivia()
{
var PHOTO_TRIVIA = CKEDITOR.instances.Trivia_Photo.getData();
var TITLE_TRIVIA = $('#TRIVIA_TITLE').val();
var CAPTION_TRIVIA = CKEDITOR.instances.triviacap.getData();
$.post('insert_home.php',{TRIVIA_TITLE:TITLE_TRIVIA,TRIVIA_PHOTO:PHOTO_TRIVIA,TRIVIA_CAP:CAPTION_TRIVIA}).done(function(data){
alert ("Trivia Successfully Added");
location.reload(); \\what i do is just refresh the page
});
}
This is how i output the the data that will be added using the ajax above
echo "<div class=\"view view-sixth\">
".$Tri_IMAGE."
<div class=\"mask\">
<div class=\"divbutton\">
<input onclick='TRIVIA_EDIT($Tri_ID);' class=\"btnsubmit\" type=\"button\" value=\"Edit\" id=\"edit_trivia\">
<input onclick='TRIVIA_DELETE($Tri_ID,this);' class=\"btnsubmit\" type=\"button\" value=\"Delete\" id=\"delete_trivia\">
</div>
<h2>".$Tri_TITLE."</h2>
<p>".$Tri_CAPTION."</p>
</div>
</div>";
}

Answer 1

You can use append() in jQuery to append elements to the DOM. If the div is returned by your PHP. Then append it to a DOM element by using i.e. $('#trivias').append(data);
EDIT (using the question authors code as an example):
I've replaced the location.reload() part with the code to append the returning div.
$.post('insert_home.php',{TRIVIA_TITLE:TITLE_TRIVIA,TRIVIA_PHOTO:PHOTO_TRIVIA,TRIVIA_CAP:CAPTION_TRIVIA}).done(function(data){
$('#trivias').append(data);
}
Here I assume you've got a element with the trivias id. For example <div id="trivias">...</div> somewhere in your code already.

Answer 2

just put your response data into whatever you want it in
$.post('insert_home.php',{TRIVIA_TITLE:TITLE_TRIVIA,TRIVIA_PHOTO:PHOTO_TRIVIA,TRIVIA_CAP:CAPTION_TRIVIA}).done(function(data){
alert ("Trivia Successfully Added");
$('#idOfTheDivYouwantToPutResponseIn').html(data);
});

Answer 3

Change your $.post() callback to also append the HTML response from insert_home.php into the DIV.
$.post('insert_home.php',{
TRIVIA_TITLE: TITLE_TRIVIA,
TRIVIA_PHOTO: PHOTO_TRIVIA,
TRIVIA_CAP: CAPTION_TRIVIA
}).done(function(data){
alert ("Trivia Successfully Added");
$('#trivias').html(data);
});

Answer 4

in PHP use json_encode
$str = "<div class=\"view view-sixth\">
".$Tri_IMAGE."
<div class=\"mask\">
<div class=\"divbutton\">
<input onclick='TRIVIA_EDIT($Tri_ID);' class=\"btnsubmit\" type=\"button\" value=\"Edit\" id=\"edit_trivia\">
<input onclick='TRIVIA_DELETE($Tri_ID,this);' class=\"btnsubmit\" type=\"button\" value=\"Delete\" id=\"delete_trivia\">
</div>
<h2>".$Tri_TITLE."</h2>
<p>".$Tri_CAPTION."</p>
</div>
</div>";
echo json_encode($str);
then use he post request like this
$.ajax({
type: "POST",
url: 'insert_home.php',
data: {TRIVIA_TITLE:TITLE_TRIVIA,TRIVIA_PHOTO:PHOTO_TRIVIA,TRIVIA_CAP:CAPTION_TRIVIA},
dataType:'json',
success: function (data) {
$('#your_id').html(data);
}
});