Change a variable of a variable - php

Question

I'm trying to process a large form and hit a bit of a stumbling block. I've tried google for the answer, but I'm not quite sure I'm wording what I need right. My code looks like this.
<?PHP
$exchange = $_POST['exchange'];
$estimate = $_POST['estimate'];
$wp = $_POST['wp'];
$label1 = $_POST['name3'];
$result1 = $_POST['fb1'];
$result2 = $_POST['fb2'];
$username = "-----";
$password = "-----";
$hostname = "-----";
$con = mysql_connect($hostname, $username, $password) or die("Unable to connect to MySQL");
$selected = mysql_select_db("-----", $con) or die("Could not select examples");
$query = "UPDATE btsec SET Status='$result1', TM='result2' WHERE Exchange='$exchange' AND Estimate='$estimate' AND WP='$label1' AND SectionID='$label1'";
if (!mysql_query($query,$con))
{
die('Error: ' . mysql_error($con));
}
}
echo "Sections updated for WP's $wp on $estimate on the $exchange Exchange!";
mysql_close($con);
?>
What I need to do is loop through the query, but each time change the contents of the variable.
$label1 = $_POST['name3']; needs to become $label1 = $_POST['name6'];
$result1 = $_POST['fb1']; needs to become $result1 = $_POST['fb10'];
$result1 = $_POST['fb2']; needs to become $result1 = $_POST['fb11'];
As I say google isn't able to compensate for my bad wording.

Answer 1

The best solution would be to change the form inputs so that they work as arrays:
<input type="text" name="name[3]">
<input type="text" name="name[6]">
<input type="text" name="name[9]">
<input type="text" name="fb[1]">
<input type="text" name="fb[10]">
<input type="text" name="fb[19]">
Then when you submit the form you can iterate over the data:
foreach ($_POST['name'] as $index => $name)
{
}
foreach ($_POST['fb'] as $index => $fb)
{
}
As a side note, you also should look into using prepared statements, or at the very least escaping the data -- you're at risk of SQL injection.