Im joining 3 tables to present a table with users highest score
My tables
game_log:
---ID---user_ID---score---time---
| 1 52 567 10 |
| 2 53 641 13 |
| 3 52 465 8 |
| 4 53 451 14 |
---------------------------------
users:
---ID---name---countyid---
| 52 Dave 1 |
| 53 John 2 |
------------------------
county:
---countyid---countyname---
| 1 Orange wichit |
| 2 Orange clemts |
--------------------------
SQL:
SELECT * FROM game_log
INNER JOIN users ON game_log.user_ID=users.ID
INNER JOIN county ON users.countyid=county.countyid
ORDER BY game_log.score DESC , game_log.time LIMIT 20";
Above code gives me this result:
Rank---Name--------County------Score---Time
1 John Orange clemts 641 13
2 Dave Orange wichit 567 10
3 John Orange clemts 465 8
4 Dave Orange wichit 451 14
My problem is that I want the highscore table to display the top 20 users with the highest score, not the 20 highest scores.
Like this:
Rank---Name--------County------Score---Time
1 John Orange clemts 641 13
2 Dave Orange wichit 567 10
Need som help with this, not familiar with joining tables ;-)
This approach will show the top 20 users and each user's highest score, and if they have multiple instances of the same score, it'll show the information for the earliest one (lowest time value for that user and score).
SELECT *
FROM game_log gl
INNER JOIN users u
ON gl.user_ID = u.ID
INNER JOIN county c
ON u.countyid = c.countyid
WHERE not exists (select 1
from game_log gl2
where gl2.user_id = gl.user_id
and gl2.score > gl.score)
and not exists (select 1
from game_log gl2
where gl2.user_id = gl.user_id
and gl2.time < gl.time
and gl2.score = gl.score)
ORDER BY gl.score DESC, gl.time LIMIT 20;
Without doing this, if the same user in the top 20 had the same score 2+ times, they would be listed 2+ times, and you would not get back 20 people by using LIMIT 20 because the same person would be taking up N rows out of that 20.
SQL Fiddle here showing data with a tie: http://sqlfiddle.com/#!2/0ac931/5/0
GROUP BY should do the job.
SELECT users.ID, users.name, county.countyname, MAX(game_log.score) AS score, game_log.time
FROM game_log
INNER JOIN users ON game_log.user_ID = users.ID
INNER JOIN county ON users.countyid = county.countyid
GROUP BY game_log.user_ID
ORDER BY game_log.score DESC, game_log.time
LIMIT 20;
Try it out with SQL Fiddle.
I would do this with the not exists approach to get the highest score for each user. The rest of the query is the same:
SELECT *
FROM game_log gl INNER JOIN
users u
ON gl.user_ID = u.ID INNER JOIN
county c
ON u.countyid = c.countyid
WHERE not exists (select 1
from game_log gl2
where gl2.user_id = gl.user_id and gl2.score > gl.score
)
ORDER BY gl.score DESC, gl.time
LIMIT 20;
The where clause is saying "keep this row if no other row for the same user has a higher score".
Another way to do this is with the aggregation approach:
SELECT *
FROM (select user_id, max(score) as maxscore
from game_log gl
group by user_id
) gl INNER JOIN
users u
ON gl.user_ID = u.ID INNER JOIN
county c
ON u.countyid = c.countyid
ORDER BY gl.maxscore DESC
LIMIT 20;
But this method loses the information about time. It is possible to include that, but it makes the query more complicated.
Related
Hey can you help me with my simple sql query ?
Tables
Hotel
id | name | country | rating
1 Bali bg 4.5
2 Beach uk 4.0
3 Blue sk 3.7
Tour
id | id_hotel | price
1 2 250
2 2 270
3 1 250
4 1 300
5 3 250
And I want something like this
SELECT t.* FROM tour t LEFT JOIN hotel h ON t.id_hotel = h.id
WHERE h.country = uk GROUP BY h.id ORDER BY t.price
So I wanna get only one row for each one hotel with min tour price.
And best with using Doctrine 2 queryBuilder.
Thanks for help.
Hey prbably I have solution
SELECT MIN(tour.id), hotel.* FROM `tour` INNER JOIN (
SELECT MIN(t.final_price) as final_price, t.id_hotel FROM tour t GROUP
BY t.id_hotel) ht
ON tour.id_hotel = ht.id_hotel AND tour.final_price =
ht.final_price
LEFT JOIN hotel ON hotel.id = tour.id_hotel GROUP BY tour.id_hotel
Use group by with order by to accomplish your result, try below query
select hotel.name,Tour.id,Tour.price,Hotel.rating from Hotel inner join Tour on Tour.id_hotel = Hotel.id group where hotel.country = 'uk' group by Tour.id_hotel order by Tour.price asc
Let me know if it helps
[Edit] This query should work with you
I have these two tables - user_schedules and user_schedule_meta, shown below:
------------------------------------
| id | scheduler_id | status |
------------------------------------
1 3 pending
2 5 active
3 6 active
and
----------------------------------------------
| id | user_schedule_id | meta_key |meta_value
----------------------------------------------
1 3 course-id 135
2 3 session-id 15
3 3 schedule-id 120
I want to write a query to enable me select, for example, from both tables where EVERYONE of the below 5 conditions are met:
user_schedule_id = 3
scheduler_id = 6
session_id = 15
course-id = 135
schedule-id = 120
This is what I have so far, but it is not working:
SELECT user_schedule_meta.`id` FROM user_schedule_meta, user_schedules
WHERE user_schedules.`scheduler_id` = 6
AND user_schedules.id = user_schedule_meta.`user_schedule_id`
AND (
(user_schedule_meta.`meta_key` = 'course-id' AND user_schedule_meta.`meta_value` = 135)
OR (user_schedule_meta.`meta_key` = 'session-id' AND user_schedule_meta.`meta_value` = 15)
OR (user_schedule_meta.`meta_key` = 'daily-schedule-id' AND user_schedule_meta.`meta_value` = 120)
)
GROUP BY user_schedule_meta.`id`
Any suggestions what I am not doing right?
This is a typical key-value store lookup problem. These are trickier than they look in SQL, in that they require multiple JOIN operations.
You need a virtual table with one row per user_schedules.id value, then you can filter it. So
SELECT u.id, u.scheduler_id
FROM user_schedules u
JOIN user_schedule_meta a ON u.id=a.user_schedule_id AND a.meta_key='course-id'
JOIN user_schedule_meta b ON u.id=b.user_schedule_id AND b.meta_key='session-id'
JOIN user_schedule_meta c ON u.id=c.user_schedule_id AND c.meta_key='daily-schedule-id'
WHERE a.meta_value = 135 -- value associated with course-id
AND b.meta_value=15 -- value associated with session-id
AND c.meta_value=120 -- value associated with daily-schedule-id
Notice also that you can list your table with associated attributes like this. This trick of joining the key/value table multiple times is a kind of pivot operation. I use LEFT JOIN because it will allow the result set to show rows where an attribute is missing.
SELECT u.id, u.scheduler_id, u.status,
a.meta_value AS course_id,
b.meta_value AS session_id,
c.meta_value AS daily_schedule_id
FROM user_schedules u
LEFT JOIN user_schedule_meta a ON u.id=a.user_schedule_id AND a.meta_key='course-id'
LEFT JOIN user_schedule_meta b ON u.id=b.user_schedule_id AND b.meta_key='session-id'
LEFT JOIN user_schedule_meta c ON u.id=c.user_schedule_id AND c.meta_key='daily-schedule-id'
try this is code
select * from user_schedule_meta where user_schedule_id=3 and
(meta_key='session-id' AND meta_value=15
or meta_key='daily-schedule-id' AND meta_value=120
or meta_key='course-id' AND meta_value=135
)
well this question is related to my previous question How to left join 2 tables with SUM() and MAX() grouped by date
what i changed is i added user_id column (auto incremented) and want to select value with highest user_id per date
i have table loadhistory ( wanted to "select only value with highest user_id per date" group by and order by date DESC.)
so in this case, i want to select 150 for 2015-02-27 since it has the highest user_id in that date and 50 for 2015-02-28
| user_id | customer_id | date | bal |
1 1 2015-02-27 100
2 1 2015-02-27 150
3 1 2015-02-28 150
4 1 2015-02-28 50
and table transactionrecord (want to sum up values per date using SUM(bal) group by and order by date DESC)
| user_id |customer_id | date | bal |
1 1 2015-02-27 50
2 1 2015-02-27 20
3 1 2015-02-28 10
And i want to join the 2 tables which would look like this:
| date | balance | amount paid |
2015-02-28 50 10
2015-02-27 150 70
this is the code so far (i used the code i got from my previous question and edited it here in my new question hoping to arrive desired result but did not)
SELECT a.customer_id, a.date, (b.bal AS bal WHERE b.user_id = MAX(b.user_id) , a.paid
FROM (
SELECT customer_id, date, SUM(bal) AS paid
FROM transactionrecord
GROUP BY customer_id, date
) AS a LEFT JOIN loadhistory AS b
ON a.customer_id = b.customer_id AND a.date = b.date
WHERE a.customer_id = 1
GROUP BY a.customer_id, a.date, a.paid
ORDER BY a.date DESC
help please. thanks in advance
MySQL use the first row by group by, so you must order it before you can use group by like this:
SELECT * FROM (SELECT * FROM `loadhistory` ORDER BY user_id DESC) history GROUP BY date
So you can use the following query as solution:
SELECT h.date,h.bal as balance, t.amount as 'amount paid' FROM
(SELECT * FROM (SELECT * FROM `loadhistory` ORDER BY user_id DESC) history GROUP BY date) as h
JOIN
(SELECT SUM(bal) as amount, customer_id, date FROM `transactionrecord` GROUP BY date) as t
ON h.date = t.date AND h.customer_id = t.customer_id
ORDER BY date DESC
I have those 3 tables
candidates
cdid cdname
1 Moussa
2 Moustafa
3 Haitham
positions
posid posname
1 pos1
2 pos2
3 pos3
joboffers
cdid posid salary
1 1 600
1 2 800
1 3 700
2 1 500
2 2 700
2 3 900
3 2 1000
3 3 500
I need to make a query that get the cdname with max salary for every position
the table should be like this
cdname posname salary
moussa pos1 600
haitham pos2 1000
moustafa pos3 900
I am using this query but it's not getting the correct cdid
$sql="select joboffers.cdid,joboffers.posid,Max(joboffers.salary),candidates.cdname
FROM joboffers,candidates
Where joboffers.cdid=candidates.cdid
Group by joboffers.posid";
Try this :)
SELECT sub.cdname, sub.posname, sub.salary
FROM (
SELECT * FROM joboffers jo
INNER JOIN positions ps USING (posid)
INNER JOIN candidates cd USING (cdid)
ORDER BY posid, salary DESC
) sub
GROUP BY sub.posid
I think you need to group by all non-aggregated columns, like this:
SELECT j.cdid, c.cdname, j.posid, MAX(j.salary)
FROM joboffers j
JOIN candidates c ON j.cdid = c.cdid
GROUP BY j.cdid, c.cdname, j.posid
SELECT c.cdname, p.posname, MAX(j.salary)
FROM joboffers j
INNER JOIN candidates c ON j.cdid = c.cdid
INNER JOIN positions p ON j.posid = p.posid
GROUP BY c.cdname, p.posname
enter code hereSELECT customerNumber, MAX(amount)
FROM payments
GROUP BY customerNumber
ORDER BY MAX(amount);
In my table 1 I have something like this
name | age
George 42
Bob 30
Ken 23
In my table 2, I have something like this, this is where i store votes for each person.
name | votes |
George 1
Ken 1
George 1
George 1
Ken 1
My goal is to combine the 2 tables, and return all the rows in table 1 even it doesn't exist in table 2.
Desire results:
name | age | total_votes
George 42 3
Bob 30 0
Ken 23 2
But instead I get:
name | age | total_votes
George 42 3
Ken 23 2
I have tried something like this
SELECT `table_1`.*, coalesce(COUNT(`table_2`.votes), 0) AS total_votes
FROM `table_1`
LEFT JOIN `table_2`
ON `table_1`.name = `table_2`.name
You can do one of these:
1) Use Right Join instead of current Left Join.
Or
2) Exchange table1 and table2 places in your join expression, like:
FROM table_2
LEFT JOIN table_1
Try this. This works in MS Access , I think this will work on your's too just convert the query to SQL:
SELECT Table1.name, First(Table1.age) AS age, Count(Table2.Votes) AS totalVotes
FROM Table1 LEFT JOIN Table2 ON Table1.name = Table2.name
GROUP BY Table1.name;
Left Join table1 to table2 so that all entry from table1 , even if its is corresponding data is null, will be included. GROUP BY your query by name so that votes will be counted by name .