How to use post() jquery method with codeigniter form_validation - php

I want to validate a form without refreshing the page using the .post() jQuery method.
I use codeigniter for validation. Could you please tell me how to make it right? I find it pretty confusing ...
Here is the jQuery code:
$(document).ready(function(){
$(".form_errors").hide();
$("#send").on("click",function(){ //the submit button has the id="send"
$(".form_errors").hide(); //these are <p> for each input to show the error
var user=$("input.box");
var data={};
var names=$("input.box").attr("name");
for(i=0;i<user.length;i++){
name=names[i];
value=user[i].val();
data.name=value;
}
$.post('ksite/account',
data,
function(result){
$("div.answer").html(result);
for(i=0;i<user.length;i++){
error_message=<?php echo form_error("?>names[i]<?php ");?>;
$("p#error_"+names[i]+".form_errors").html(error_message).show();
}
}
return false;});
});
form_error is a CodeIgniter function. (I suppose someone who used ci is familiar with).
The form:
<p id="error_user" class="form_errors"></p>
<input type="text" class="box" name="user">
<p id="error_password" class="form_errors"></p>
<input type="password" class="box" name="password">
<input type="submit" id="send">
Is the form tag neccessary ? And if yes,do i have to mention action and method ?
Do I have to specify the type of the response?
And in ksite/account I do:
/* ...... */
if (!this->form_validation->run(''account")) {
echo "The account couldn't be made";
} else {
echo "The account was successfully created ";
}
P.S.Although you may not be familiar with codeigniter, I would appreciate if someone could tell me if the code is correct and what improvements could be made.

Here is what I did.
You have to Ajax for getting data without refreshing the page.
HTML Page
$form = $(form);
var url = $form.attr('action');
dataString = $form.serialize();
$.ajax({
type: "POST",
url: url,
data: dataString,
dataType: "json",
success: function(data) {
$(data).each(function(j,details){
var status = details.status;
var message = details.message;
$('#message_ajax_register').show();
$('#message_ajax_register').html('<div class="alert alert-success">'+message+'</div>');
});
}
});//end of $.ajax**
I am first setting up the rules in my controller method and then validating it.
Controller
public function update_fest()
{
if($this->input->post())
{
$this->form_validation->set_rules('txtgpluswebsite', 'Google Plus Page URL', 'trim|xss_clean|prep_url');
$this->form_validation->set_error_delimiters('<div class="error">', '</div>');
if($this->form_validation->run() == false){
$message = validation_errors();
$data = array('message' => $message,'status'=>0);
}
else{
$message = $this->add_fest_database();
$data = $message;
}
}
else{
$message = "Fest details are required";
$data = array('message' => $message,'status'=>0);
}
$this->output->set_content_type('application/json');
$json = $this->output->set_output(json_encode($data));
return $json;
}
If validation run is not false, then go to add_fest_database(other function). In that function,
function add_fest_database()
{
$youtubeWebsite = $this->input->post('txtyoutubewebsite');
$gplusWebsite = $this->input->post('txtgpluswebsite');
$this->load->model('model_fest');
$data = array("fest_youtube"=>$youtubeWebsite,"fest_gplus"=>$gplusWebsite);
return data;
}

Related

I am unable to post data using ajax on url friendly blog detailing page where I am already using url value in Query

I know that it may be so tricky!
In detail:
on the blog detailing page(blog-single.php/title) I have a subscription form this subscription form is working fine on another page with the same PHP action file and ajax
and blog-single.php/title is also working fine until I did not submit the form
On this page in the starting, I have bellow query
<?php
$query_head="SELECT * FROM blog_post WHERE friendly_url = '{$_GET['url']}' ";
$result_head= $fetchPostData->runBaseQuery($query_head);
foreach ($result_head as $k0 => $v0)
{
//----- some echo
}
?>
and my subscription form code:
<form action="" method="post" class="subscribe_frm" id="subscribe_frm2">
<input type="email" placeholder="Enter email here" name="email" id="subscribe_eml2">
<button type="button" id="subscribe2">Subscribe</button>
</form>
and ajax code is bellow:
$(document).ready(function() {
$("#subscribe2").click( function() {
subscribe_frm_val2 = false;
/*email validation*/
var emailReg2 = /^([\w-\.]+#([\w-]+\.)+[\w-]{2,4})?$/;
if ($("#subscribe_eml2").val().length <= 0) {
$("#subscribe_eml_Err2").html("Required field");
//console.log("Required");
subscribe_frm_val2 = false;
}
else if(!emailReg2.test($("#subscribe_eml2").val()))
{
$("#subscribe_eml_Err2").html("Enter a valid email");
}
else{
$("#subscribe_eml2").html("");
subscribe_frm_val2 = true;
//console.log("final else");
if(subscribe_frm_val2 == true)
{
console.log("frm true");
var form = $('#subscribe_frm2')[0];
var data = new FormData(form);
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: "updation/subscribe_action.php",
data: data,
processData: false,
contentType: false,
cache: false,
timeout: 6000000,
beforeSend: function(){
// Show image container
$("#submition_loader").show();
//alert ("yyy");
},
success: function (data) {
// console.log();
$(document).ajaxStop(function(){
$("#subscribe_eml_Err2").html(data);
});
},
complete:function(data){
// Hide image container
$("#submition_loader").hide();
}
});
}
else{
alert('Please fill all required field !');
}
}
});
});
When I submit my form above the first query is giving a warning like below:
Warning: Invalid argument supplied for foreach() in D:\xamp\htdocs\my\bootstrapfriendly\category.PHP on line 13
and after warning page doing misbehave
I think the error because of URL passing but I am not sure how to solve it
Please help me with solving it.
Thank's
I got the solution
its very simple just converted my relative URL into an absolute URL
I just created a PHP function for base URL
function base_url(){
if(isset($_SERVER['HTTPS'])){
$protocol = ($_SERVER['HTTPS'] != "off") ? "https" : "http";
}
else{
$protocol = 'http';
}
return $protocol . "://" . $_SERVER['HTTP_HOST'];
}
and then using this base URL function inside script like this
$.ajax({
----
url: "<?php echo base_url()?>/updation/subscribe_action.php",
-----
});

Ajax send no data [ Codeigniter ]

i have a problem in ajax, indeed, i try to send value with ajax to my upload function before submit.
But when i check the $_POST array in my php code, there is only the value of the form, and not from the ajax, and I don't know why.
Here is my code :
HTML:
<button id="btn_saisie" class="btn btn-app saver adddocu" ><i class="fa fa-save whiter"></i></button>
<form action="/uploader/adddocu" id="form_saisie" class="form_saisie" method="POST" enctype="multipart/form-data">
<input type="file" name="document" class="val_peage form-control form_num" id="document" data-rest="document" placeholder="Document">
<input type="text" name="description" class="val_parking form-control form_num" id="description" data-rest="description" placeholder="Description">
JS :
$( ".adddocu" ).click(function() {
if ($('#document').val() != "" && $('#description').val() != ""){
api_sendvalue_adddoc();
}
if ($('#document').val() == "")
alert('test');
else if ($('#description').val() == "")
alert('test2'); });
function api_sendvalue_adddoc(){
user = JSON.parse(sessionStorage.getItem('user'));
pays = localStorage.getItem("pays");
magasin = localStorage.getItem("magasin");
$.ajax({
type: 'POST',
url: '/uploader/adddocu',
data: {pays:pays, magasin:magasin},
success: function(data){
alert(data);
$("#form_saisie").submit();
console.log(data);
},
error: function(xhr){
alert(xhr.responseText);
console.log(xhr.responseText);
}
}); }
PHP:
public function adddocu(){
$path = './asset/upload/pdf/';
$path2 = '/asset/upload/pdf/';
$config['upload_path'] = $path;
$config['encrypt_name'] = false;
$config['file_ext_tolower'] = true;
$config['allowed_types'] = 'pdf';
// die(var_dump($_POST));
$this->load->library('upload', $config);
foreach($_FILES as $id => $name)
{
$this->upload->do_upload('document');
$upload_data = $this->upload->data();
$url = $path2 . $upload_data['file_name'];
$data = array('nom' => $upload_data['raw_name'], 'description' => $_POST['description'], 'url' => $url, 'user_id' => '17');
$this->db->insert('pdf', $data);
}
redirect("/login/docu");
}
So, when I var_dump the $_POST array, I only have the value of "description", and not of "pays" and "magasin".
Can you help me please?
Thanks for your time.
Seems like you are accessing localstorage value , you are posting it somewhere and then submiting the form.
More you are submiting the form which dont have this pays & magasin so i have a trick using which you can achieve it.
Create two hidden inputs inside your HTML form like
<input type="hidden" name="pays" id="pays">
<input type="hidden" name="magasin" id="magasin">
Now before ajax call give them values after getting it from local storage, like this.
user = JSON.parse(sessionStorage.getItem('user'));
pays = localStorage.getItem("pays");
magasin = localStorage.getItem("magasin");
$("#pays").val(pays);
$("#magasin").val(magasin);
$.ajax({ .... });
Continue your code and enjoy.
Hopefully it will work for you.
The issue is because you are not preventing the form from being submit normally, so the AJAX request is cancelled. Instead of using the click event of the button, hook to the submit event of the form and call preventDefault(). Try this:
$('#form_saisie').submit(function(e) {
e.preventDefault();
if ($('#document').val() != "" && $('#description').val() != ""){
api_sendvalue_adddoc();
}
if ($('#document').val() == "")
alert('test');
else if ($('#description').val() == "")
alert('test2');
});
EDIT:
Here is a working example of a ajax post to codeigniter:
View
<script>
$( document ).ready(function () {
// set an on click on the button
$("#button").click(function () {
$.ajax({
type: 'POST',
url: "[page]",
data: {pays: "asd", magasin: "dsa"},
success: function(data){
alert(data);
$("#text").html(data);
console.log(data);
},
error: function(xhr){
alert(xhr.responseText);
console.log(xhr.responseText);
}
});
});
});
</script>
Controller
<?php
// main ajax back end
class Time extends CI_Controller {
// just returns time
public function index()
{
var_dump($_POST);
echo time();
}
}
?>
Output
array(2) {
["pays"]=>
string(3) "asd"
["magasin"]=>
string(3) "dsa"
}
1473087963
Working example here
So you should check the request that you're making from AJAX, on dev console. There you should get the response with the var_dump($_POST).
to debug try to make your controller return only the $_POST data, comment the rest. and same thing on javascript side, test only the ajax post and data received.

php - codeigniter ajax form validation

Hi I’m quite new to jquery -ajax and I’d like some help please to join it with CI.
I have followed this tutorial on Submitting a Form with AJAX and I’d like to add this functionality to my CodeIgniter site. What I’d like to do is when the user submits the form, if there are any validation errors to show the individually on each input field (as in native ci process), or if this is not possible via validation_errors() function. If no errors occured to display a success message above the form.
Here's my code so far:
my view
// If validation succeeds then show a message like this, else show errors individually or in validation_errors() in a list
<div class="alert alert-success">Success!</div>
<?php echo validation_errors(); //show all errors that ajax returns here if not individualy ?>
<?php echo form_open('admin/product/add, array('class' => 'ajax-form')); ?>
<p>
<label for="product_name">Product *</label>
<input type="text" name="product_name" value="<?php echo set_value('product_name', $prod->product_name); ?>" />
<?php echo form_error('product_name'); ?>
</p>
<p>
<label for="brand">Brand</label>
<input type="text" name="brand" value="<?php echo set_value('brand', $prod->brand); ?>" />
<?php echo form_error('brand'); ?>
</p>
...
my controller
public function add($id){
// set validation rules in CI native
$rules = $this->product_model->rules;
$this->form_validation->set_rules($rules);
if ($this->form_validation->run() === true) {
// get post data and store them in db
$data = $this->input_posts(array('product_name', 'brand', 'category_id', 'description'));
$this->product_model->save($data, $id);
// no errors - data stored - inform the user with display success-div
} else {
// validation failed - inform the user by showing the errors
}
//load the view
$this->load->view('admin/products/add', $data);
}
and here’s the js script
$(document).ready(function () {
$('form.ajax-form').on('submit', function() {
var obj = $(this), // (*) references the current object/form each time
url = obj.attr('action'),
method = obj.attr('method'),
data = {};
obj.find('[name]').each(function(index, value) {
// console.log(value);
var obj = $(this),
name = obj.attr('name'),
value = obj.val();
data[name] = value;
});
$.ajax({
// see the (*)
url: url,
type: method,
data: data,
success: function(response) {
console.log(response); // how to output success or the errors instead??
}
});
return false; //disable refresh
});
});
How should I pass my validation results (either success or the post errors) throught the ajax request and display them on my view??
From some little research I did I've found that you can use a single controller, that holds both the native proccess and the ajax request (instead of using 2 controllers), but my main difficulty is, I don't understand how the results of the validation will pass through the js script and display them on my view?? Please note that I don't want to display anything on an alert box, instead show the results on a div or the errors individualy(if possible).
EDIT I did some changes to my application, here's the code so far:
the controller
public function manage($id = NULL){
$this->load->library('form_validation');
$data['categ'] = $this->category_model->with_parents();
//fetch a single product or create(initialize inputs empty) a new one
if (isset($id) === true) {
$data['prod'] = $this->product_model->get($id);
$data['attr'] = $this->attribute_model->get_by('product_id', $id, null, true);
} else {
$data['prod'] = $this->product_model->make_new();
$data['attr'] = $this->attribute_model_model->make_new();
}
if (isset($_POST['general_settings'])) {
if ($this->form_validation->run('product_rules') === true) {
// get post inputs and store them in database
$data = $this->product_model->input_posts(array('product_name', 'brand', 'category_id', 'general_description'));
$this->product_model->save($data, $id);
$status = true;
} else {
// validation failed
$status = validation_errors();
}
if ( $this->input->is_ajax_request() ) {
echo json_encode($status);
exit;
}
redirect('admin/product');
}
//if (isset($_POST['attributes_settings'])) { the same thing here }
// load the view
$this->load->view('admin/products/manage', $data);
}
and the js
success: function(response) {
//console.log(response);
if (data.status === true) {
$('#ajaxResults').addClass('alert alert-success').html(response);
} else {
$('#ajaxResults').addClass('alert alert-error').html(response);
};
}
But I'm having some issues
Although I get the error messages from validation_errors() as an alert-error when there are no errors I get the true in an alert-error too, insted of alert-success.
2.how should I return the success message too? eg. a message saying "Saves were done!".
Althought in a non-ajax-request the data are stored in the database, in case fo ajax the don't store. Any ideas What may be wrong???
HTML:
<div id="ajaxResults"></div>
Javascript ajax:
success: function(response) {
$('#ajaxResults').text(response);
}
this script you've wrote is only if the validation succeeds, right?
Wrong. The code in "success" gets executed any time you get a response back from the server (assuming the HTTP header is 200). Does your javascript knows if the server has any error for you? No.
You need your JavaScript to recognize if the validation failed or succeeded. You have many ways to do that. One of these could be sending the message to display followed by a 0 or 1.
So your PHP will looks like:
return "0 " . $errorMessage;
and
return "1 " . $successMessage;
and your javascript should then recognize, with if statement and substring, if the message starts with 0 or with 1.
Use this way i hope this will work for you
<script type='text/javascript'>
var base_url = '<?=base_url()?>';
function ajax_call()
{
var ids = $("#all_users").val();
$.ajax({
type:"POST",
url: base_url+"expense/home/get_expense",
data: "userid=" + ids,
success: function(result){
$("#your_div_id").html(result);
}
});
}
</script>

ajax form after 'submit' validation errors

I have created a form using ajax and php. The initial load and entering values into the form are all working fine, but where I am getting errors, is after the submit button has been pressed. Here is the markup for the form, and the ajax and php handlers:
relevant parts of form:
<form id="edit_time">
<!-----form fields here----!>
<button class="saveRecurrence" type="button" onclick="editTimeDriver('.$_GET['driver_id'].')">Save</button>
ajax part:
function editTimeDriver(driver_id) {
var time = "";
if (driver_id)
{
time += "&driver_id="+driver_id;
}
var data = $("#edit_time").serialize();
$.ajax({
url: "ajax.php?action=save_driver_event"+time,
dataType: "json",
type: "post",
data: data,
beforeSend: function()
{
$(".error, .success, .notice").remove();
},
success: function(json)
{
if (json["status"]=="success")
{
alert(json["message"]);
$("#edit_time")[0].reset();
}else{
if(json["error"]["date_from"]){
$("input[name=date_from]").after("<div class="error">"+json_time["error"]["date_from"]+"</div>");
}
}
}
});
}
This then passes to the php part which is:
$json = array();
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
$date_from = tep_db_prepare_input($_POST['date_from']);
if (preg_match("/^([0-9]{4})-([0-9]{2})-([0-9]{2})$/", $date_from)) {
$json['error']['date_from'] = 'Start Date is not valid!';
}
if (isset($json['error']) and !empty($json['error'])){
$json['status'] = 'error';
$json['message'] = 'Please check your error(s)!';
}else{
$json['status'] = 'success';
$json['message'] = 'Time Data has been successfully updated!';
}
}
echo json_encode($json);
Now for some reason, if the date_from field is left blank, and the form submitted, it doesn't come back with error message, instead it returns the success message. Can anyone tell me why it is not reading the errors?
Change your code by this one
onclick="editTimeDriver('<php echo $_GET['driver_id'] ?>'); return false;"
The return false statement prevent the form to be submitted using http (as you want to send an ajax request)
And You where doing something weird with your $_GET['driver_id']
Don't forget that php is running server-side

Unable to simultaneously POST and JSON with ajax jquery

I suspect that this might be a server issue, but since I do not have access to our server, I was hoping maybe someone else had a fix or could explain to me exactly what is causing the problem.
The problem ....
Using JQuery AJAX I am unable to simultaneously POST data to a php file and receive json encoded data from the php file. If the json dataType is included I am unable to POST data from the form to the php file. If I do not specify the json dataType (i.e. comment it out) then I can POST data to the php file but cannot receive the json encoded data.
I've tried this with my own js/php code and for source code that I downloaded, in order to compare results in case it was just a mistake in my coding. Both are 'submit forms' and both exhibit the problems outlined above. In case its relevant, I include the downloaded source code below. My js/php code uses similar ajax requests.
javaScript:
<script type="text/javascript">
$(document).ready(function(){
$("#myForm").submit(function(){
dataString = $("#myForm").serialize();
$.ajax({
type: "POST",
url: "postForm_ajax.php",
data: $("#myForm").serialize(),
dataType: "json",
contentType: "application/json; charset=utf-8",
success: function(msg){
$("#formResponse").removeClass('error');
$("#formResponse").addClass(msg.status);
$("#formResponse").addClass(msg.status);
},
error: function(){
$("#formResponse").removeClass('success');
$("#formResponse").addClass('error');
$("#formResponse").html("There was an error submitting the form. Please try again.");
}
});
//make sure the form doens't post
return false;
});
});
</script>
the PHP:
<?php
//function to validate the email address
//returns false if email is invalid
function checkEmail($email){
if(!preg_match("/^[_\.0-9a-zA-Z-]+#([0-9a-zA-Z][0-9a-zA-Z-]+\.)+[a-zA-Z]{2,6}$/i", $email)) {
//if(eregi("^[a-zA-Z0-9_]+#[a-zA-Z0-9\-]+\.[a-zA-Z0-9\-\.]+$]", $email)){
return FALSE;
}
list($Username, $Domain) = explode("#",$email);
if(#getmxrr($Domain, $MXHost)){
return TRUE;
} else {
if(#fsockopen($Domain, 25, $errno, $errstr, 30)){
return TRUE;
} else {
return FALSE;
}
}
}
//response array with status code and message
$response_array = array();
//validate the post form
//$name = $_POST['name'];
//check the name field
if(empty($_POST['name'])){
//set the response
$response_array['status'] = 'error';
$response_array['message'] = 'Name is blank';
//check the email field
} elseif(!checkEmail($_POST['email'])) {
//set the response
$response_array['status'] = 'error';
$response_array['message'] = 'Email is blank or invalid';
//check the message field
} elseif(empty($_POST['message'])) {
//set the response
$response_array['status'] = 'error';
$response_array['message'] = 'Message is blank';
//form validated. send email
} else {
//send the email
$body = $_POST['name'] . " sent you a message\n";
$body .= "Details:\n\n" . $_POST['message'];
mail($_POST['email'], "SUBJECT LINE", $body);
//set the response
$response_array['status'] = 'success';
$response_array['message'] = 'Email sent!';
}
echo json_encode($response_array);
?>
EDIT....One Solution
Ok...so I found a hack that works. I don't specify the dataType:'json', i.e. comment that line and the contenType line out. Then I'm able to POST the data. Still have the php file echo the json_encode($response_array). Then put the following code in the success function
var obj = jQuery.parseJSON(msg);
$("#formResponse").addClass(obj.status);
$("#formResponse").html(obj.message);
This is not as nice as being able to specify the dataType:'json' in the ajax call. If anyone has a better solution or can explain why this problem is occurring, let me know.
Thanks
According to me you are doing nothing wrong... except you are specifying to many things...
For eg:
dataType: "json",
is sufficient for ajax call to work.... there is no need for
contentType: "application/json; charset=utf-8",
in your code, if you add this line it returns the empty array in return for some reason (not very sure about the actual reason)....
But moment I specify just
dataType: "json",
it works like a charm where in return I get the object, which I need not parse.
edit:
What I tried is as followring... just change the input name to fname from name and it worked very well
<form id="myForm" name="myForm" method="POST"
action="postform_ajax.php">
name: <input type="text" name="fname" /> <br /> email: <input
type="text" name="email" /> <br /> message: <input type="message"
name="message" /> <br /> <input type="submit" />
<div id="formResponse"></div>
</form>
<script type="text/javascript"
src="http://code.jquery.com/jquery-1.7.2.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#myForm").submit(function() {
dataString = $("#myForm").serialize();
$.ajax({
type : "POST",
url : "postForm_ajax.php",
data : $("#myForm").serialize(),
dataType : "json",
success : function(msg) {
$("#formResponse").removeClass('error');
$("#formResponse").addClass(msg.status);
$("#formResponse").html(msg.status);
},
error : function() {
console.log('err', msg);
$("#formResponse").removeClass('success');
$("#formResponse").addClass('error');
$("#formResponse").html("There was an error submitting the form. Please try again.");
}
});
//make sure the form doens't post
return false;
});
});
</script>

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