Find string in two field with SQL - php

Question

I'm working on a search module, like facebook when you look for a friend.
So, i have in my table user two fields : firstname and name.
If i have for example a user : firstname : Georges and name : Clooney, i want, when i write :
Geo...
Cloo...
loo geor...
geor ney
etc....
retrieve this user.
How can i do that with SQL ? I want to write a very permissive search module..

Answer 1

This will surely help you
Well the below method first calculate all possible combination of the possible words & then matches it with database
<?php
$name ='Georges Clooney'; // you search string
$words=explode(" ", $name);;
function get_all_combination($arr, $temp_string, &$collect) {
if ($temp_string != "")
$collect []= $temp_string;
for ($i=0; $i<sizeof($arr);$i++) {
$arrcopy = $arr;
$elem = array_splice($arrcopy, $i, 1); // removes and returns the i'th element
if (sizeof($arrcopy) > 0) {
get_all_combination($arrcopy, $temp_string ." " . $elem[0], $collect);
} else {
$collect []= $temp_string. " " . $elem[0];
}
}
}
$collect = array();
get_all_combination($words, "", $collect);
/*
$collect now have all possible combination of search string
Array
(
[0] => Georges
[1] => Georges Clooney
[2] => Clooney
[3] => Clooney Georges
)
*/
$sql="SELECT * FROM user_info WHERE (firstname like '%".implode("%' OR firstname like '%",$collect)."%' or name like '%".implode("%' OR name like '%",$collect)."%')" ;
?>
For any more help do ask

Answer 2

What you need, is this little Friend: %
WHERE firstname LIKE '%" . $name . "%' OR name LIKE '%" . $name ."%'
Here is a tutorial:
http://www.webreference.com/programming/php/search/index.html

Answer 3

Try This:
Select * from User where `name` LIKE '%search_string%' OR `firstname`
LIKE '%search_string%' OR CONCAT(firstname,' ',name) LIKE '%search_string'%'

Answer 4

SELECT *
FROM User
WHERE firstname LIKE '%'+#input+'%' OR name LIKE '%'+#input+'%'
where #input is the inserted text in the textbox.

Answer 5

Try this query:
SELECT * from user
WHERE name LIKE '%search_string%'
OR firstname LIKE '%search_string%'
It will match if any firstname or name containing search_string. it will show all users containing this string in name or first name.

Answer 6

Try this
select * from user where `name` like '%trim(search_string)%' OR `firstname`
like '%trim(search_string)%' OR CONCAT(firstname,' ',name) LIKE '%".trim(search_string)."%';
Also concat both the fields and try to match.