insert multiple rows to mysql database [duplicate] - php

Question

This question already has answers here:
Best way to INSERT many values in mysqli?
(4 answers)
Closed 1 year ago.
i am trying to insert multiple rows to mysql but it only sends last row.
i am using javascript to create rows dynamically but it is sending only the last row
this is my form file code
index.php
<style type="text/css">
table,tr,td{border:0px solid black;}
</style>
<table id="titlebar" cellspacing="0px">
<tr>
<td style="width:20px;">✓</td>
<td style="width:160px;">Show</td>
<td style="width:62px;">season</td>
<td style="width:63px;">episode</td>
<td style="width:100px;">language</td>
<td style="width:190px;">Link 1</td>
<td style="width:190px;">Link 2</td>
</tr>
</table>
<form action="send.php" method="POST">
<table id="dataTable" width="auto" style="margin:-4px 0 0 0;" cellspacing="0px">
<tr>
<td style="width:20px;"><INPUT type="checkbox" name="chk" /></td>
<td><INPUT type="text" name="series" style="width:160px;" autocomplete="on" placeholder="Show" required/></td>
<td><INPUT type="text" name="season" style="width:62px;" autocomplete="on" placeholder="season" required/></td>
<td><INPUT type="text" name="episode" style="width:63px;" autocomplete="on" placeholder="episode" required/></td>
<td>
<SELECT name="language" style="width:100px;">
<OPTION value="one">one</OPTION>
<OPTION value="two">two</OPTION>
<OPTION value="three">three</OPTION>
<OPTION value="four">four</OPTION>
<OPTION value="five">five</OPTION>
<OPTION value="six">six</OPTION>
<OPTION value="seven">seven</OPTION>
</SELECT>
</td>
<td><INPUT type="text" name="link_1" style="width:190px;" autocomplete="on" placeholder="link 1" required/></td>
<td><INPUT type="text" name="link_2" style="width:190px;" autocomplete="on" placeholder="link 2" required/></td>
</tr>
</table>
<INPUT type="button" value="Add row" onclick="addRow('dataTable')" />
<INPUT type="button" value="Delete row" onclick="deleteRow('dataTable')" />
<INPUT type="submit" value="Send"/>
</form>
<script language="Javascript">
function addRow(tableID) {
var table = document.getElementById(tableID);
var rowCount = table.rows.length;
var row = table.insertRow(rowCount);
var colCount = table.rows[0].cells.length;
for(var i=0; i<colCount; i++) {
var newcell = row.insertCell(i);
newcell.innerHTML = table.rows[0].cells[i].innerHTML;
//alert(newcell.childNodes);
switch(newcell.childNodes[0].type) {
case "text":
newcell.childNodes[0].value = "";
break;
case "text":
newcell.childNodes[0].value = "";
break;
case "text":
newcell.childNodes[0].value = "";
break;
case "text":
newcell.childNodes[0].value = "";
break;
case "text":
newcell.childNodes[0].value = "";
break;
case "checkbox":
newcell.childNodes[0].checked = false;
break;
case "select-one":
newcell.childNodes[0].selectedIndex = 0;
break;
}
}
}
function deleteRow(tableID) {
try {
var table = document.getElementById(tableID);
var rowCount = table.rows.length;
for(var i=0; i<rowCount; i++) {
var row = table.rows[i];
var chkbox = row.cells[0].childNodes[0];
if(null != chkbox && true == chkbox.checked) {
if(rowCount <= 1) {
alert("Cant delete all rows");
break;
}
table.deleteRow(i);
rowCount--;
i--;
}
}
}catch(e) {
alert(e);
}
}
</script>
and this my post code
send.php
<?php
include('mysql.php');
$seriesV = mysql_real_escape_string(stripslashes($_POST['series']));
$seasonV = mysql_real_escape_string(stripslashes($_POST['season']));
$episodeV = mysql_real_escape_string(stripslashes($_POST['episode']));
$languageV = mysql_real_escape_string(stripslashes($_POST['language']));
$link_1V = mysql_real_escape_string(stripslashes($_POST['link_1']));
$link_2V = mysql_real_escape_string(stripslashes($_POST['link_2']));
$sql="INSERT INTO 0_stock_master (stock_id,category_id,tax_type_id,description,long_description,sales_account,cogs_account)
VALUES
('$seriesV','$seasonV','$episodeV','$languageV','$link_1V','$link_2V','".time()."')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record added";
mysql_close($con);
?>
Please help to submit all the rows in mysql database.

Answer 1

first change the names of your dynamically created elements.
next you could walk though the entire post data with:
foreach ($_POST as $key => $value)
{
//... get your row values and execute sql
}