I'm building a form that's in a loop, so that the user can choose how many rows they want to put into the database. And all my input-names have this value art_$i where $i is the number of the rows, that my loop generates.
When the form-button is pressed, I then try to pull out the value of each $_POST['art_X'] by creating a second loop that repeats itself the same amount of times as my $i loop that is naming by inputs as art_1, art_2, art_3 etc. This second loop I call $b, here's how I try to solve the problem.. It just isn't working at all!
$convert_post_to_variable = "$_POST[art_" . $b . "]";
Any suggestions on how I could solve this problem, would be MUCH APPRECIATED! :-D
Don't use quotes around variable names. It makes a mess of things, and then you would have to use curly brackets... just don't do it. You can use an arbitrary string key on an associative array like this:
$convert_post_to_variable = $_POST['art_' . $b];
Use the following code:
$convert_post_to_variable = $_POST[ 'art_' . $b ];
Related
I am trying to build a string made of the results from sql and I do not know how achieve this when the data from the db is bigger than 1.
I was able to do it when the result from the database is one.
$result = $stmt_grade->fetch(PDO::FETCH_ASSOC);
$str ="[{$result['score_access']}, {$result['score_training']},
{$result['score_expectation']}, {$result['score_total']} ]";
but when I needed to loop the fetch_assoc I was not able to assign a value to variables or directly build the string.
while ($resultcount = $stmt_count->fetch(PDO::FETCH_ASSOC)){
$resultcount['subarea'];
}
I have looked everywhere and did not find any solutions or any similar approach to find inspiration. I hope someone can help me. Thank you in advance!
The most obvious way to do this is loop through all of the responses in a while loop, and continually append to your string using the .= operator. You can tell when you run out of records because $result will be false.
I separated each record with a newline. It also looked like you wanted to count results, so I added that, too.
$str = ""; // start with an empty string
$count = 0;
while ( ($result = $stmt_grade->fetch(PDO::FETCH_ASSOC)) !== false ) {
// increment the record count
$count++;
// add a new line to the output string
$str .= "[{$result['score_access']}, {$result['score_training']},{$result['score_expectation']}, {$result['score_total']} ]\n";
}
That should do it.
All you need is to name your string properly.
And then use a proper way to create a JSON string. Which consists of two parts:
Create a array of desired structure. Or at least provide a that structure here to let us to provide you with the code.
Use json_encode().
Assuming you need a nested array like this
[[1,2,3],[1,2,3],[1,2,3]]
the code would be
$result = $stmt_grade->fetchAll(PDO::FETCH_NUM);
echo json_encode($result);
thanks for all the answers provided without you I could not made it. Finally, I achieved the desirable result as follow, probably it is not elegant but works:
$stmt_count= $user->countbyespeciality();
while ($resultcount = $stmt_count->fetch(PDO::FETCH_ASSOC)){
$prueba.= "{$resultcount['subarea']},";
$prueba2.= "{$resultcount['number']},";
}
$string=rtrim($prueba, ",");
$string2=rtrim($prueba2, ",");
$final="[{$string}]";
$final2="[{$string2}]";
The output is [something,something] [1,2,] as expected.
thanks again!
I think this is a naive question, but I can't find the proper syntax.
I have this code:
for ($i=1; $i<count($MyArray1); $i++){
$element=$MyArray1[$i];
$foo = $AnotherArray[$element];
echo $foo;
}
How can I skip the second line? I mean, the third line to be something like
$foo = $AnotherArray[$MyArray1[$i]];
for ($i=1; $i<count($MyArray1); $i++){
echo $AnotherArray[$MyArray1[$i]];
}
You can skip a fair amount of that code to make it a bit clearer. Firstly use foreach instead of for as it's a much more reliable way of iterating over arrays. Secondly I've broken down what you're trying to do, to simplify how you're getting it. Basically using the values of one array as the keys of another. So how to do it in three lines:
foreach(array_intersect_key($AnotherArray, array_flip($MyArray1)) as $value) {
echo $value;
}
This is using the excellent array_intersect_key method to grab all of the values from $AnotherArray with keys that match in the other array. As you want to use the values, we use array_flip to swap the keys and values, then just loop over the result and echo it.
I have this code:
$fookerdos = '';
foreach (glob("records/*/*/kerdos.txt") as $somekerdos) {
$fookerdos .= file_get_contents($someposoA);
//to print them i you want
print $fookerdos;
So my problem that for this code will outputs many numbers becouse of many files.
for example will out output this
3.5 -6.7 6.68 -0.2 and so on..
now i want all this numbers to make them (addition)
i know how to addition some 2-3 variables, but i additions many numbers that I even dont know how many they are.
for example
print "3.5 + "-6.7" "6.68" "-0.2";
Thx :)
Does each file contain only a single number, or can they have more than one numbers?
From your previous edits, it seems as if one file contain only a number.
In that case, you can store the values in an array and sum the numbers using array_sum() or perform any other calculation as needed.
Here is a sample code for you:
$fookerdos = array ();
foreach (glob("records/*/*/kerdos.txt") as $somekerdos) {
$fookerdos[] = file_get_contents($somekerdos);
}
echo array_sum ($fookerdos);
I had this working by simply passing the data from one variable to another like so:
$CalcsSets = $DisplayCalcs;
without the need to use the loop inside the first if() statement and it inserted the data without quotes but all of a sudden it's stopped working and I'm not sure why (it only started showing last integer), so I went with the more complex code trying to get it to work again as shown below.
Here's the complex code I'm working with:
for($i=1; $i<=$CalcSets; $i++){
$calculations = PerformCalc($min, $highest, $OperatorType);
echo 'Calculations performed for '.$SetText[$i];
foreach ($calculations as $key => $DisplayCalcs) {
echo $SetCalc[] = $DisplayCalcs.', '; //stores calculations with ',' in
//array.
}
if($CalcSets == 1){
for($i=0;$i<$CalcSets;$i++){
$SetResults = $SetCalc[$i];
echo '<strong>'.(string)$SetResults.'</strong>';
}
DB_Insert($SetResults);
}
What it's supposed to do is insert values in the following format (1,2,3,4,5,) into the database in a VARCHAR row but now all it shows is the last integer with no comma. I originally wanted to just store the integers and not a comma but I couldn't get it to display on the page with commas after each integer so I went this route as mentioned earlier.
I realize I'm probably going about this the wrong way, but if any of you know a much easier, and shorter, way to do what I want, I'd be extremely appreciative of the help.
Reason I'm doing it this way, is because on the results page, it needs to show in the format mentioned above.
FYI, I did check the DB row and it is still set to VARCHAR with a length of 10 at the moment.
UPDATE TO MAKE INTENTIONS MORE CLEAR
Ok, I'm going to go back to square one and try to make my intention as clear as possible. I've been rewriting this code snippet more times than I care to count and my brain is all foggy lol.
array1 = array(1, 2, 3, 4, 5, 6);
foreach(array1 as $key => $data){
echo $data.',';
// will display 1,2,3,4,5,6, in browser.
}
if(is_true == 1){
INSERT ALL $data values into DB here.
}
That's what I'm trying to accomplish in it's simplest form, I'm just have extreme difficulty achieving my goal.
Second Update - Topic Solved
Apparently, the DB field had to be set to Text rather than VarChar. I guess we learn something new everyday.
Again, thanks everyone for all of your help. It was greatly appreciated!
I'm sorry but I couldn't make much sense from the original code but focusing only on the last IF and the containing LOOP, I think the problem is with the assignment statement:
$SetResults = $SetCalc[$i];
It should instead use .= for concatenation. Here is how it should look:
if($CalcSets == 1){
for($i=0;$i<$CalcSets;$i++){
$SetResults .= $SetCalc[$i];
echo '<strong>'.(string)$SetResults.'</strong>';
}
DB_Insert($SetResults);
}
Hope it works!
I completely agree with the solution from #KemalFadillah for using the implode() method. From your code snippet, I understand that $calculations is the array that stores the main values, i.e. Array(1, 2, 3, 4, 5). So you can do:
$calculations = PerformCalc($min, $highest, $OperatorType);
$s = implode (', ', $calculations);
DB_Insert($s);
I hope that makes sense?
You are executing the last for loop only if $calcSets == 1 and have an $i<$calcSets condition
How about doing it like this
$SetCalc = "";
foreach ($calculations as $key => $DisplayCalcs) {
echo $SetCalc .= $DisplayCalcs.', ';
}
DB_Insert("(".$SetCalc.")");
You're looking for the implode() function to format the numbers.
$formatted = implode(',', $calculations); // Produce 1,2,3,4,etc...
http://php.net/manual/en/function.implode.php
I am hacking together a theme for wordpress and I am using the following code to pull out data from a custom field with several values:
<?php $mykey_values = get_post_custom_values('services');
foreach ( $mykey_values as $key => $value ) {
echo "<span>$value, </span>";
} ?>
I use a comma to seperate the results, but I don't want a comma after the last result. How do I get around this?
Best way is with implode:
echo('<span>' . implode('</span>, <span>', $mykey_values) . '</span>');
Many ways to do this... the first one I can think of is instead of using echo, concatenate all the results into a string, then remove the last , character.
Another way would be to use a for loop instead of foreach and then iterate to the size of $mykey_values - 1 and then print the last one without a ,. And I'm sure others will post other ways (maybe with real code too - my PHP is too rusty for me to risk a real code sample).
echo "<span>" . implode(',</span><span>',$mykey_values) . "</span>;
Edit: BTW, you don't use the loop if you use this code.