Rendering Yii's Flash message inside the partial view with ajax call - php

Question

I have a problem displaying Flash messages in Yii. Inside my view I have an ajax button, calling method update of my controller. Inside the update method I want to set a Flash message and display it inside my view when it's updated with new data.
*update.php :*
<?php
<h1>Update Campaign <?php echo $campaign->id; ?></h1>
<?php
$tabList = array();
//FORM IS DISPLAYED INSIDE A JUI TAB:
$tabList['General'] = $this->renderPartial('_form', array('campaign'=>$campaign),true);*
...
$this->widget('zii.widgets.jui.CJuiTabs',array(
'tabs'=>$tabList,
'options'=>array(
'collapsible'=>false,
),
));
?>
*_form.php:*
//HERE I WANT TO DISPLAY A FLASH MESSAGE WHEN _form IS RENDERED:
<?php foreach(Yii::app()->user->getFlashes() as $key => $message) : ?>
<div class="flash-<?php echo $key; ?>"><?php echo $message; ?></div>
<?php endforeach; ?>
<?php
Yii::app()->clientScript->registerScript(
'myHideEffect',
'$(".flash-success").animate({opacity: 1.0}, 1000).fadeOut("slow");',
CClientScript::POS_READY
);
?>
<div class="form">
<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'campaign-form',
'enableAjaxValidation'=>false,
)); ?>
<p class="note">Fields with <span class="required">*</span> are required.</p>
<?php echo $form->errorSummary($campaign); ?>
<div class="row">
<div class="span2">
<?php echo $form->labelEx($campaign,'campaign_mode_id'); ?>
</div>
<div class="span2">
<?php echo $form->dropDownList($campaign,'campaign_mode_id', CampaignMode::model()->getModes());?>
<?php echo $form->error($campaign,'campaign_mode_id'); ?>
</div>
</div>
...
<div class="row buttons">
<div class="span2">
<?php
if($campaign->isNewRecord){
echo CHtml::submitButton( 'Create');
}else{
//THIS IS MY AJAX-SUBMIT BUTTON, IT CALL CONTROLLER'S UPDATE METHOD AND UPDATE JUI TAB (DIV WITH ID '#yw0_tab0')
echo CHtml::ajaxSubmitButton(
'Save',
Yii::app()->createUrl("//campaign/update/{$campaign->id}"),
array('beforeSend' => 'function(){
$("#surveyquestions").addClass("ajaxloading");}',
'complete' => 'function(){
$("#surveyquestions").removeClass("ajaxloading");}','update' => "#yw0_tab0"),
array('id' => 'send-link-'.uniqid()));
}
?>
</div>
</div>
<?php $this->endWidget(); ?>
*Contorller:*
public function actionUpdate($id)
{
$campaign=$this->loadModel($id);
if(isset($_POST['Campaign']))
{
$campaign->attributes=$_POST['Campaign'];
if($campaign->save())
{
//HERE I'M SETTING THE FLASH MSG
Yii::app()->user->setFlash('success','Campaign is updated');
if(Yii::app()->request->isAjaxRequest){
//AND UPDATING MY VIEW
$this->renderPartial('_form', array('campaign'=>$campaign), true,true);
}else{
$this->redirect(array('update','id'=>$campaign->id));
}
}
}
$this->render('update',array('campaign'=>$campaign));
}

Answer 1

Actually you are rendering _form view, but without sending it to output (take a look at third param), and then you are rendering update view... The flash message has been rendered once in _form, so it won't be rendered again.
You should simply try this :
if(Yii::app()->request->isAjaxRequest) {
$this->renderPartial('_form', array('campaign'=>$campaign), false, true);
Yii::app()->end();
} else {
$this->redirect(array('update','id'=>$campaign->id));
}