Function in an if statement - php

Question

I am trying to do an if statement if a function returns true and the else if it doesn't
Basically i need to show a html class in the return 1. I have try that below but I got an error.
syntax error, unexpected 'if' (T_IF)
This is what I have tried
<div class="inner">
<div class="stat"
<?php $access->getAccess()
if (getAccess == 1) {
class="unpublished"
}
else {
}
?>
>
</div>
</div>
this is what the function looks like
public function getAccess()
{
return $this->access;
}
How can I do this right?

Answer 1

Try with:
<div class="stat <?php echo $idea->getAccess() ? 'unpublished' : ''; ?>"></div>

Answer 2

You PHP code isn't echoing anything, plus you are missing semicolons.
Try to simplify this a bit:
<div class="stat <?=$idea->getAccess() == 1 ? 'unpublished' : ''?>">
P.S. You need to put all your classes into the same attribute.

Answer 3

To call a function you need to use brackets:
$access = getAccess();//Not getAccess
I note that you call another getAccess function too so you may have meant to do:
$access = $idea->getAccess() ;
if ($access == 1) {
Edit: Others have pointed out you are also missing a ;.

Answer 4

You need to conceptually separate PHP from your HTML. What is happening is that your PHP is being interpreted by your web server resulting in a HTML document that will be delivered to the client. What you want is to add a class to the div if an $idea has access, something like this:
<div class="inner">
<div class="stat <?php echo $idea->getAccess() ? "unpublished" : ""?>">
</div>
</div>
This is equivalent to a much more complex (and in my opinion harder to read):
<div class="inner">
<div class="stat <?php
if ($idea->getAccess()) {
echo "unpublished";
}
?>">
</div>
</div>

Answer 5

You forgot a semi-colon:
getAccess();