This question already has answers here:
PHP upload and resize image
(4 answers)
Closed 9 years ago.
I am currently using this code so users can upload images to my site
$allowed_filetypes = array('.jpg','.gif','.bmp','.png','.jpeg','.JPG','.PNG','.BIF','.GIF','.JPEG'); // These will be the types of file that will pass the validation.
$max_filesize = 524288; // filesize in BYTES (currently 0.5MB).
$uploadpath = "/home/path/to/file/files/avatars/$_SESSION[user]";
$posted9 = hash('md5',$_SESSION["user"]).$ext; /* not for security mind you. */
// Upload the file to your specified path.
$f = file_put_contents(
$upload_path . $posted9,
file_get_contents('php://input')
);
if($f)
$m="Avatar updated<br/>"; // It worked.
else
$m="There was an error during the file upload. Please try again."; // It failed :(.
However, when the images are rezised to fit inside the comments on my website, they become distorted and lose their quality.
How using PHP can I resize the images so that the quality is maintained?
<?php
// Url of the file
$url = "/homepages/0/d502303335/htdocs/foo.jpg";
// Set a maximum height and width, I used the ones on your picture
$width = 49;
$height = 47;
// Get new dimensions
list($width_orig, $height_orig) = getimagesize($url);
// Resample
$image_p = imagecreatetruecolor($width, $height);
$image = imagecreatefromjpeg($url);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height, $width_orig, $height_orig);
// Output, You can use another url, In my case i just overwrite the picture
imagejpeg($image_p, $url);
?>
Here's the result:
http://www.filmgratuiti.org/varie/cenBqHxMD90Q2.jpg
Much more better then your's
So basically after you have uploaded the file you run my code and you are good to go
public function resize($width,$height) {
$new_image = imagecreatetruecolor($width, $height);
imagecopyresampled($new_image, $this->image, 0, 0, 0, 0, $width, $height, $this->getWidth(), $this->getHeight());
$this->image = $new_image;
}
http://us3.php.net/imagecopyresampled
Related
I have a php code to get an image and resize it. Can't get the output as expected.. Please help me figure out what the exact problem is..!!
<?php
$picture_source = 'image.png';
if ($picture_source != null){
$img1=file_get_contents($picture_source);
$new_img1 = resizeImage($img1, 200, 200);
file_put_contents("i1.png", $new_img1);
}
function resizeImage($img,$newwidth,$newheight) {
list($width, $height) = getimagesizefromstring($img);
$thumb = imagecreatetruecolor($newwidth, $newheight);
imagecopyresampled($thumb, $img, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
return $thumb;
}
You've got some confusion with your variable names and types. You're trying to deal with a filename, the file contents, and an image resource at the same time, and you're using the wrong ones for a few of the functions.
imagecopyresampled takes two image resources (source and destination), but you're passing it the file contents in place of the source.
file_put_contents takes a string for the file contents, but you're passing it the resized image resource.
PHP has native functions for reading the image dimensions and creating an image resource from a filename, so you shouldn't need to ever have the source file contents available as a string.
If you change a few of the variable names and function calls around, you end up with:
<?php
$sourceFilename = 'image.png';
if ($sourceFilename != null){
$newImg = resizeImage($sourceFilename, 200, 200);
imagepng($newImg, "i1.png");
}
function resizeImage($imgFilename, $newWidth, $newHeight) {
list($width, $height) = getimagesize($imgFilename);
$img = imagecreatefrompng($imgFilename);
$thumb = imagecreatetruecolor($newWidth, $newHeight);
imagecopyresampled($thumb, $img, 0, 0, 0, 0, $newWidth, $newHeight, $width, $height);
return $thumb;
}
Also, you should turn on PHP notices and warnings in your development environment - they will have been trying to help you.
My image file size is 800x600 and I want to resize this 800x600 to 400x300 then save both images(800x600 and 400x300) in the database base64_encode format. I can save in database first image (800x600) but how to convert a second image (400x300) in base64_encode format and save in database? I don't want to use two input fields. I think one input field enough for that.
$image = ($_FILES["my_image"]["name"]);
$theme_image = ($_FILES["my_image"]["tmp_name"]);
$bin_string = file_get_contents("$theme_image");
$theme_image_enc = base64_encode($bin_string);
You have to make a little script for create the new image from the first one and make the base64_encode on it
$WIDTH = 400; // The size of your new image
$HEIGHT = 300; // The size of your new image
$QUALITY = 100; //The quality of your new image
$DESTINATION_FOLDER = DependOfYourRepository; // The folder of your new image
// The directory where is your image
$filePath = DependOfYourRepository;
// This little part under depend if you wanna keep the ratio of the image or not
list($width_orig, $height_orig) = getimagesize($filePath);
$ratio_orig = $width_orig/$height_orig;
if ($WIDTH/$HEIGHT > $ratio_orig) {
$WIDTH = $HEIGHT*$ratio_orig;
} else {
$HEIGHT = $WIDTH/$ratio_orig;
}
// The function using are different for png, so it's better to check
if ($file_ext == "png") {
$image = imagecreatefrompng($filePath);
} else {
$image = imagecreatefromjpeg($filePath);
}
// I create the new image with the new dimension and maybe the new quality
$bg = imagecreatetruecolor($WIDTH, $HEIGHT);
imagefill($bg, 0, 0, imagecolorallocate($bg, 255, 255, 255));
imagealphablending($bg, TRUE);
imagecopyresampled($bg, $image, 0, 0, 0, 0, $WIDTH, $HEIGHT, $width_orig, $height_orig);
imagedestroy($image);
imagejpeg($bg, $DESTINATION_FOLDER.$filename, $QUALITY);
$bin_string_little = file_get_contents($DESTINATION_FOLDER.$filename);
// I remove the image created because you just wanna save the base64 version
unlike($DESTINATION_FOLDER.$filename);
imagedestroy($bg);
$theme_image_enc_little = base64_encode($bin_string_little);
// And now do what you want with the result
EDIT 1
It's possible to do it without using a directory for the second image but it's quite tricky.
$theme_image_little = imagecreatefromstring(base64_decode($theme_image_enc));
$image_little = imagecreatetruecolor($WIDTH, $HEIGHT);
// $org_w and org_h depends of your image, in your case, i guess 800 and 600
imagecopyresampled($image_little, $theme_image_little, 0, 0, 0, 0, $WIDTH, $HEIGHT, $org_w, $org_h);
// Thanks to Michael Robinson
// start buffering
ob_start();
imagepng($image_little);
$contents = ob_get_contents();
ob_end_clean();
$theme_image_enc_little = base64_encode($contents):
This question already has answers here:
Resize image in PHP
(13 answers)
Closed 8 years ago.
I came across few solutions but all those were based on uploading an image. What I want is that it should fetch the image from one folder, resize it of particular size and then save it in other folder.
I normally use the GD library for this. It works fine. For an example, please see this url: http://runnable.com/UnF-tFdudNt1AABt/how-to-resize-an-image-using-gd-library-for-php
Try PHP library function imagecopyresized()
Here is a sample programme,
// File and new size
$filename = 'test.jpg';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb);
Here is the manual for imagecopyresized().
http://www.php.net/manual/en/function.imagecopyresized.php
Scenario : Earlier I was reading the url of image directly and resized the image into 4 different size . But I had execution time out . Now I read the url and copy it into a temporary folder and pass the images in local temporary folder to imagecreatefromjpeg().
protected static function saveImage($row,$url){
$percent = 1.0;
$imagethumbsize = 200;
$db = PJFactory::getDbo();
$details = $db->getImageDetails();
$max = sizeof($details);
$tempfilename = "C:".DS."xampp".DS."htdocs".DS."opg-uat".DS."img".DS."temp".DS.$row['CategoryID'].".jpg";
$tempcopy = copy($url,$tempfilename);
foreach ($details as $array) {
$new_width=$array[2];
$new_height=$array[3];
$newfilename = "C:".DS."xampp".DS."htdocs".DS."opg-uat".DS."img".DS."c".DS.$row['CategoryID']."-".$array[1].".jpg";
$image_p = imagecreatetruecolor($new_width, $new_height);
$image = imagecreatefromjpeg($tempfilename);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $new_width, $new_height, $width, $height);
imagejpeg($image_p, $newfilename);
}
}
Error : The images are correctly being saved in temp folder . But in the destination folder images of all sizes are created but the image looks only black . (Not getting the actual image) . I guess there is some problem with the file reading from local .
Any idea ?
Thanks in advance.
If you are trying to read files other than JPG files, it will return only black images,
So while reading images, check which filetype your file really has and then call the correct function between the three (jpeg, png, gif).
Do you set $width and $height anywhere?
$width = imagesx($image);
$height= imagesy($image);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $new_width, $new_height, $width, $height);
I am working on improving my Facebook app. I need to be able to resize an image, then save it to a directory on the server. This is the code I have to resize:
<?php
// The file
$filename = 'test.jpg';
$percent = 0.5;
// Content type
header('Content-type: image/jpeg');
// Get new dimensions
list($width, $height) = getimagesize($filename);
$new_width = $width * $percent;
$new_height = $height * $percent;
// Resample
$image_p = imagecreatetruecolor($new_width, $new_height);
$image = imagecreatefromjpeg($filename);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $new_width, $new_height, $width, $height);
// Output
imagejpeg($image_p, null, 100);
?>
My question is, how would I save this resized image? Would I need to? Is there a way to manipulate the resized image without saving it?
According to the manual on imagejpeg(), the optional second parameter can specify a file name, which it will be written into.
Filename
The path to save the file to. If not set or NULL, the raw image stream will be outputted directly.
To skip this argument in order to provide the quality parameter, use NULL.
It's usually a good idea to write the results to disk for some basic caching, so that not every incoming request leads to a (resource intensive) GD call.
function resize($img){
/*
only if you script on another folder get the file name
$r =explode("/",$img);
$name=end($r);
*/
//new folder
$vdir_upload = "where u want to move";
list($width_orig, $height_orig) = getimagesize($img);
//ne size
$dst_width = 110;
$dst_height = ($dst_width/$width_orig)*$height_orig;
$im = imagecreatetruecolor($dst_width,$dst_height);
$image = imagecreatefromjpeg($img);
imagecopyresampled($im, $image, 0, 0, 0, 0, $dst_width, $dst_height, $width_orig, $height_orig);
//modive the name as u need
imagejpeg($im,$vdir_upload . "small_" . $name);
//save memory
imagedestroy($im);
}
it should be work
http://www.php.net/manual/en/function.imagecopyresampled.php#90038