I am trying to insert to another table the results of a select statement from another table. The select statement works but the insert statement does not work. Please help me.
$query="SELECT * FROM subject WHERE sub_code = '$enrol' ";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)) {
$csubject=$row['sub_name'];
$cday=$row['sub_day'];
$ctime=$row['sub_time'];
echo "<strong>". $csubject . "</strong>";
}
$query = mysql_query("INSERT INTO client (client_csub_code,client_csub_name,client_csub_day,client_csub_time) VALUES ('$enrol','$csubject','$cday','$ctime')");
header("Location:homeclient.php");
?>
You asked for how to do these two as one query.
This is how:
$query = mysql_query("INSERT INTO `client` ( `client_csub_code`, `client_csub_name`, `client_csub_day`, `client_csub_time` ) SELECT `sub_code`, `sub_name`, `sub_day`, `sub_time` FROM `subject` WHERE `code` = '$enrol'");
// I would also add error checking
if ( mysql_errno() )
echo mysql_error();
$query="SELECT * FROM subject WHERE sub_code = '$enrol' ";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)) {
$csubject=$row['sub_name'];
$cday=$row['sub_day'];
$ctime=$row['sub_time'];
echo "<strong>". $csubject . "</strong>";
$query = mysql_query("INSERT INTO client (client_csub_code,client_csub_name,client_csub_day,client_csub_time) VALUES ('$enrol','$csubject','$cday','$ctime')");
}
header("Location:homeclient.php");
?>
Try changing to this. Currently your query is outside of your while, it will only run once and the values of $csubject etc are always going to be the last values of your fetched results.
Related
The SQL query returns just Array in the browser even if there is values in the database. I have tried the query in phpmyadmin and it works but not in my php document.
require_once('connect.php');
$query = "SELECT `id` FROM `questions` WHERE round='1' AND year='2016'";
$sql = mysqli_query($dbconnect, $query);
$row = mysqli_fetch_array($sql, MYSQLI_ASSOC);
Almost the same query works in different php documents. Any suggestions what is wrong? Should also say that the query should return integers.
$query = "SELECT `id` FROM `questions` WHERE round='1' AND year='2016'";
You're only selecting the id column. If you wish to echo more columns, then you need to add them in the query.
I.e.:
$query = "SELECT `id`, `col2`, `col3` FROM `questions` WHERE round=1 AND year=2016";
then loop over results:
while ($row = mysqli_fetch_array($sql, MYSQLI_ASSOC)) {
echo $row['id'];
// echo "<br>";
// echo $row['col2'] . "<br>";
// echo $row['col3'];
}
Check for errors on the query also and assuming a successful mysqli_ connection.
http://php.net/manual/en/mysqli.error.php
Other reference:
http://php.net/manual/en/function.mysqli-connect.php
if you want to display other column's data so have to add * in the place of 'id'
require_once('connect.php');
$query = "SELECT * FROM `questions` WHERE round='1' AND year='2016'";
$sql = mysqli_query($dbconnect, $query);
I'm new to both PHP & mySQL, but I suspect some apostrophe related bug here (maybe).
For some reason the first query always seems to return null because the
echo "result: $result\n";
never prints any data. At the first call that is expected, but at the second call the player has been added to the db. My database works in the sense that I can see that rows with correct ids are added to the database (via phpMyAdmin).
Can you help me spot the error?
<?php
require_once('Db.php');
$db = new Db();
// Quote and escape form submitted values
$id = $db->quote($_POST['id']);
$score = $db->quote($_POST['score']);
$result = $db->query("SELECT `id` FROM `xxxxxx`.`Player` WHERE `id` = `$id`");
echo "result: $result\n"; // Never prints any data
if($result->num_rows == 0) {
// Row not found. Create it!
$result = $db->query("INSERT INTO `xxxxxx`.`Player` (`id`,`score`) VALUES (" . $id . "," . 0 . ")");
}
?>
First, drop those backticks from id in WHERE clause, otherwise it will take the field name from id column instead of 'id'.
Then you need to fetch data from $result:
$result = $db->query("SELECT id FROM `xxxxxx`.`Player` WHERE id = '$id'");
$row = $result->fetch_array();
echo $row['id'];
Or if there are more rows than one:
while($row = $result->fetch_array())
{
echo $row['id'];
}
You are using backticks in your query for $id. Remove them and try again.
Your query should be
$result = $db->query("SELECT `id` FROM `xxxxxx`.`Player` WHERE `id` = $id");
OR
$result = $db->query("SELECT `id` FROM `xxxxxx`.`Player` WHERE `id` = ".$id."");
<?php
mysql_connect("localhost", "root", "");
mysql_select_db("students");
$id = $_POST['id'];
$grade = $_POST['grade'];
$query = "INSERT INTO `st_table` (`St_id`,`Grade`) VALUES ('$id','$grade')";
$result = mysql_query($query);
$query = "SELECT * from `st_table`";
$result = mysql_query($query);
echo "<table>";
echo "<th>St_id</th><th>Grade</th>";
while($row = mysql_fetch_array($result)){
echo "<tr><td>" . $row['St_id'] . "</td><td>" . $row['Grade'] . "</td></tr>";
}
This code adds values into a table both ID and Grade. I want another query that will be able to count how many As, Bs, Cs, etc. and OUTPUT it on an html table.
Here, Your query is ok just group by Grade not Grades
"SELECT `Grade`, COUNT(*) AS count FROM `st_table` GROUP BY `Grade`";
Here is sqlfiddle
After edit
The query i am mentioning should work for you, you can check fiddle for that as for as you modified code is concerned you have to change your table a bit since you are going to include St_id as well so make it 3 column and correspondingly change query too.
I'm working with a file and I'm attempting to do multiple select statements one after another and insert some values. So far the insert and the select I've got working together but when attempting to get the last SELECT to work I get no value. Checking the SQL query in workbench and everything works fine. Here's the code:
$id = "SELECT idaccount FROM `animator`.`account` WHERE email = '$Email'";
$result = mysqli_query($dbc, $id) or die("Error: ".mysqli_error($dbc));
while($row = mysqli_fetch_array($result))
{
echo $row[0];
$insert_into_user = "INSERT INTO `animator`.`user` (idaccount) VALUES ('$row[0]')";
}
$select_userid = "SELECT iduser FROM `animator`.`user` WHERE iduser = '$row[0]'";
$results = mysqli_query($dbc, $select_userid) or die("Error: ".mysqli_error($dbc));
while($rows = mysqli_fetch_array($results))
{
echo $rows[0];
}
I do not want to use $mysqli->multi_query because of previous problems I ran into. Any suggestions? And yes I know the naming conventions are close naming... They will be changed shortly.
Your code makes no sense. You repeatedly build/re-build the $insert_int-User query, and then NEVER actually execute the query. The $select_userid query will use only the LAST retrieved $row[0] value from the first query. Since that last "row" will be a boolean FALSE to signify that no more data is available $row[0] will actually be trying to de-reference that boolean FALSE as an array.
Since you're effectively only doing 2 select queries (or at least trying to), why not re-write as a single two-value joined query?
SELECT iduser, idaccount
FROM account
LEFT JOIN user ON user.iduser=account.idaccount
WHERE email='$Email';
I'm not sure what you're trying to do in your code exactly but that a look at this...
// create select statement to get all accounts where email=$Email from animator.account
$id_query = "SELECT idaccount FROM animator.account WHERE email = '$Email'";
echo $id_query."\n";
// run select statement for email=$mail
$select_results = mysqli_query($dbc, $id_query) or die("Error: ".mysqli_error($dbc));
// if we got some rows back from the database...
if ($select_results!==false)
{
$row_count = 0;
// loop through all results
while($row = mysqli_fetch_array($result))
{
$idaccount = $row[0];
echo "\n\n-- Row #$row_count --------------------------------------------\n";
echo $idaccount."\n";
// create insert statement for this idaccount
$insert_into_user = "INSERT INTO animator.user (idaccount) VALUES ('$idaccount')";
echo $insert_into_user."\n";
// run insert statement for this idaccount
$insert_results = mysqli_query($dbc, $insert_into_user) or die("Error: ".mysqli_error($dbc));
// if our insert statement worked...
if ($insert_results!==false)
{
// Returns the auto generated id used in the last query
$last_inisert_id = mysqli_insert_id($dbc);
echo $last_inisert_id."\n";
}
else
{
echo "insert statement did not work.\n";
}
$row_count++;
}
}
// we didn't get any rows back from the DB for email=$Email
else
{
echo "select query returned no results...? \n";
}
$sql1 = "SELECT SIDno FROM class WHERE SubjID='$SubjName' and SecID='$SecName'";
$result1 = mysql_query($sql1);
while ($row1 = mysql_fetch_assoc($result1)){
$IDno = $row1["SIDno"];
$sql2="INSERT INTO registered ( ServiceID, IDno, Stype)VALUES('$RecCode','$IDno','$Stype')";
}
this is my code. its working but it only insert one data into the database. How can make it away to insert all the possible data from the loop. Can anyone help me?
You’re probably executing the query after the loop so only the last record is being inserted.
Try to execute the insertion query at the end of the loop:
while ($row1 = mysql_fetch_assoc($result1)) {
$IDno = $row1["SIDno"];
$sql2 = "INSERT INTO registered (ServiceID, IDno, Stype) VALUES ('".mysql_real_escape_string($RecCode)."', '".mysql_real_escape_string($IDno)."', '".mysql_real_escape_string($Stype)."')";
mysql_query($sql2);
}
Or you first collect all data and then do one query to insert all records:
$values = array();
while ($row1 = mysql_fetch_assoc($result1)) {
$IDno = $row1["SIDno"];
$values[] = "('".mysql_real_escape_string($RecCode)."', '".mysql_real_escape_string($IDno)."', '".mysql_real_escape_string($Stype)."')";
}
if (!empty($values)) {
$sql2 = "INSERT INTO registered (ServiceID, IDno, Stype) VALUES ".implode(',', $values);
mysql_query($sql2);
}
But don’t forget to prepare the values for the query (see mysql_real_escape_string function).
If you are not planing to do anything with the fetched data, you could use INSERT .. SELECT .. statement.
Example:
INSERT INTO registered (ServiceID, IDno, Stype)
SELECT field1, field2, field3
FROM class
WHERE SubjID='$SubjName' and SecID='$SecName'"
And like written before me, escape your variables...
Note: make sure you're escaping your variables with mysql_real_escape_string.
$sql1 = "SELECT SIDno FROM class WHERE SubjID='$SubjName' and SecID='$SecName'";
$result1 = mysql_query($sql1);
$sql2 = "INSERT INTO registered (ServiceID, IDno, Stype) VALUES ";
$addComma = false;
while ($row1 = mysql_fetch_assoc($result1)){
$IDno = $row1["SIDno"];
$sql2 .= ($addComma ? ", " : "") . "('$RecCode','$IDno','$Stype')";
$addComma = true;
}
Change this line:
$sql2="INSERT INTO registered..."
to this:
$sql2 .= "INSERT INTO registered..."
inside the loop. You are accidentally overwriting the insert statement each time. If you use .= you will append the next statement to the previous one, creating a batch of insert scripts, one for each record.