How to include a file, but not execute everything? - php

Question

I'm currently working on making a few amendments to a website.
The way the website currently works is that the page calls for a require once for the config.inc.php page. The config page also has the SQL call for the what is required to show from the database. While this works fine, I need to create a new page that shows the same table, but the SQL has changed to show different data.
The trouble I’m having is that the config.inc.php page has the SQL data on it that pulls in what is wanted. I want to show a different result on a different page, but the website requires the config.inc.php to show everything. I changed the SQL query to test if what I wanted to show will work and it works a charm, but how do I get this to show without having to mess around with the original SQL command.
Here's the original code;
$config = require_once 'link to admin section';
$db_username = $config['components']['db']['username'];
$db_password = $config['components']['db']['password'];
$db_link = mysql_connect('nosey', $db_username, $db_password) or die(mysql_error());
mysql_select_db('nosey', $db_link);
if ( $_SERVER['REQUEST_METHOD'] == 'GET' ) {
if ( isset($_GET['id']) && $_GET['id'] ) {
$selectSqlJSONString = 'SELECT * FROM vacancies WHERE id = '.$_GET['id'].' ORDER BY created ASC LIMIT 1';
$jsonResult = mysql_query($selectSqlJSONString, $db_link);
$jsonRow = mysql_fetch_object($jsonResult);
if ( !isset($_SERVER['HTTP_X_FANCYBOX']) )
include 'details_ajax_header.php';
include 'filename.php';
if ( !isset($_SERVER['HTTP_X_FANCYBOX']) )
include 'details_ajax_footer.php';
exit;
}
}
$region = '1';
if ( isset($_GET['region']) && $_GET['region'] ) {
$region .= ' AND ' . sprintf('county LIKE "%%%s%%"', mysql_real_escape_string(str_replace('-', ' ',$_GET['region']), $db_link ));
}
$selectSqlString = 'SELECT * FROM vacancies WHERE '.$region.' ORDER BY created DESC';
$result = mysql_query($selectSqlString, $db_link) or die(mysql_error());
$vacancies = array();
while ($row = mysql_fetch_object($result)) {
$vacancies[] = $row;
}
and here's what I would to show only on another page to show a different set of results.
$config = require_once 'link to admin section';
$db_username = $config['components']['db']['username'];
$db_password = $config['components']['db']['password'];
$db_link = mysql_connect('nosey', $db_username, $db_password) or die(mysql_error());
mysql_select_db('nosey', $db_link);
if ( $_SERVER['REQUEST_METHOD'] == 'GET' ) {
if ( isset($_GET['id']) && $_GET['id'] ) {
$selectSqlJSONString = 'SELECT * FROM vacancies WHERE id = '.$_GET['id'].' ORDER BY created ASC LIMIT 1';
$jsonResult = mysql_query($selectSqlJSONString, $db_link);
$jsonRow = mysql_fetch_object($jsonResult);
if ( !isset($_SERVER['HTTP_X_FANCYBOX']) )
include 'details_ajax_header.php';
include 'filename.php';
if ( !isset($_SERVER['HTTP_X_FANCYBOX']) )
include 'details_ajax_footer.php';
exit;
}
}
$region = '1';
if ( isset($_GET['region']) && $_GET['region'] ) {
$region .= ' AND ' . sprintf('county LIKE "%%%s%%"', mysql_real_escape_string(str_replace('-', ' ',$_GET['region']), $db_link ));
}
$selectSqlString = 'SELECT * FROM vacancies WHERE featured = "1" ORDER BY created DESC';
$result = mysql_query($selectSqlString, $db_link) or die(mysql_error());
$vacancies = array();
while ($row = mysql_fetch_object($result)) {
$vacancies[] = $row;
}
Notice how all I want to change is the SELECT * FROM vacancies WHERE featured = "1".
This is all I need! But I want to include this without having to alter the config.inc.php page! (which is where this information is coming from) How do I do it?