I wanto to copy a pdf file to another folder, and it works, but the file that I open in the destination folder is decoded incorrectly and I can not open.
My code:
$fsrc = fopen($srcz,'r');
$fdest = fopen($destz,'w+');
copy($fsrc,$fdest)
Thanks
Try this:
copy($srcz,$destz);
The copy function in PHP needs the source and destination. Consult the php manual: Php copy
I don't know how that code you have works... see the function copy takes the names of the files:
copy($srz,$destz);
If you want to copy the files opened with fopen you use stream_copy_to_stream, like so:
$fsrc = fopen($srcz,'r');
$fdest = fopen($destz,'w+');
stream_copy_to_stream($fsrc, $fdest);
fclose($fsrc);
fclose($fdest);
Do not forget to close the files!
you should use copy without using fopen because fopen create a resource and copy too .
$old = '/tmp/yesterday.txt';
$new = '/tmp/today.txt';
copy($old, $new) or die("Unable to copy $old to $new.");
Related
I am trying to move files from my FTP server to a local directory. First I need to find the correct file from the FTP server, as there can be a few hundreds:
//Search for the file.
$fileName= array_filter(Storage::disk('ftp')->files(), function ($file)
{
return preg_match('/('.date("Y-m-d" ,time()).').*.XLSX/', $file);
});
Above finds the correct file. If I dd($fileName), I get this:
My File Name.XLSX
I then try to move that file, to my public disk:
$ftp_file = Storage::disk('ftp')->get($fileName);
$local_file = Storage::disk('public')->move($ftp_file, "moved_file.xlsx");
However above code doesn't work. I get below error:
preg_match() expects parameter 2 to be string, array given
Which I have identified being on below function:
$ftp_file = Storage::disk('ftp')->get($fileName);
What am I doing wrong? How can I move the file, which I am able to find on my FTP server, to my local disk?
Thank you in advance.
As #Loek pointed out, $fileName was an array, and therefore to access it I needed to use:
$ftp_file = Storage::disk('ftp')->get($fileName[0]);
I am making an Android application that need to be able to push files onto a server.
For this I'm using POST and fopen/fwrite but this method only appends to the file and using unlink before writing to the file has no effect. (file_put_contents has the exact same effect)
This is what I have so far
<?php
$fileContent = $_POST['filecontent'];
$relativePath = "/DatabaseFiles/SavedToDoLists/".$_POST['filename'];
$savePath = $_SERVER["DOCUMENT_ROOT"].$relativePath;
unlink($savePath);
$file = fopen($savePath,"w");
fwrite($file,$fileContent);
fclose($file);
?>
The file will correctly delete its self when I don't try and write to it after but if I do try and write to it, it will appended.
Anyone got any suggestions on overwriting the file contents?
Thanks, Luke.
Use wa+ for opening and truncating:
$file = fopen($savePath,"wa+");
fopen
w+: Open for reading and writing; place the file pointer at the beginning of the file and truncate the file to zero length. If the file does not exist, attempt to create it.
a+: Open for reading and writing; place the file pointer at the end of the file. If the file does not exist, attempt to create it.
file_put_contents($savePath,$fileContent);
Will overwrite the file or create if not already exist.
read this it will help show all the options for fopen
http://www.php.net/manual/en/function.fopen.php
Found the error, i forgot to reset a string inside of my application
If I have some text files inside zip files, is it possible to manipulate this text files and change information inside this zip file?
For example, if I have the file test.txt inside test.zip, is it possible to open this text file and change the content and put other, the same as if I use fopen, fputs and fclose but all inside the zip?
Yes, you can! :)
Like this:
$zip = new ZipArchive();
$zip->open('test.zip');
// Read from file
$contents = $zip->getFromName('test.txt');
var_dump($contents);
// Write to file
$zip->addFromString('test.txt', 'foo bar');
// Close (and re-pack) zip file. Don't miss that!
$zip->close();
Check the documentation of the ZipArchive class.
I know you can create a temporary file with tmpfile and than write to it, and close it when it is not needed anymore. But the problem I have is that I need the absolute path to the file like this:
"/var/www/html/lolo/myfile.xml"
Can I somehow get the path, even with some other function or trick?
EDIT:
I want to be able to download the file from the database, but without
$fh = fopen("/var/www/html/myfile.xml", 'w') or die("no no");
fwrite($fh, $fileData);
fclose($fh);
because if I do it like this, there is a chance of overlapping, if more people try to download the same file at exactly the same time. Or am I wrong?
EDIT2:
Maybe I can just generate unique(uniqID) filenames like that, and than delete them. Or can this be too consuming for the server if many people are downloading?
There are many ways you can achieve this, here is one
<?php
// Create a temp file in the temporary
// files directory using sys_get_temp_dir()
$temp_file = tempnam(sys_get_temp_dir(), 'MyFileName');
echo $temp_file;
?>
The above example will output something similar to:
/var/tmp/MyFileNameX322.tmp
I know you can create a temporary file with tmpfile
That is a good start, something like this will do:
$fileHandleResource = tmpfile();
Can I somehow get the path, even with some other function or trick?
Yes:
$metaData = stream_get_meta_data($fileHandleResource);
$filepath = $metaData['uri'];
This approach has the benefit of leaving it up to PHP to pick a good place and name for this temporary file, which could end up being a good thing or a bad thing depending on your needs. But it is the simplest way to do this if you don't yet have a specific reason to pick your own directory and filename.
References:
http://us.php.net/manual/en/function.stream-get-meta-data.php
Getting filename (or deleting file) using file handle
This will give you the directory. I guess after that you are on your own.
For newer (not very new lol) versions of PHP (requires php 5.2.1 or higher) #whik's answer is better suited:
<?php
// Create a temp file in the temporary
// files directory using sys_get_temp_dir()
$temp_file = tempnam(sys_get_temp_dir(), 'MyFileName');
echo $temp_file;
?>
The above example will output something similar to: /var/tmp/MyFileNameX322.tmp
old answer
Just in case someone encounters exactly the same problem. I ended up doing
$fh = fopen($filepath, 'w') or die("Can't open file $name for writing temporary stuff.");
fwrite($fh, $fileData);
fclose($fh);
and
unlink($filepath);
at the end when file is not needed anymore.
Before that, I generated filename like that:
$r = rand();
$filepath = "/var/www/html/someDirectory/$name.$r.xml";
I just generated a temporary file, deleted it, and created a folder with the same name
$tempFolder = tempnam(sys_get_temp_dir(), 'MyFileName');
unlink($tempFolder);
mkdir($tempFolder);
This might sound really "nooby" but I need to find a way for PHP to download an XLS file to a server folder. This file is not stored in another server, it is dynamically generated with another PHP script.
This is what I got from browsing the web but it's not working:
<?php
$url = "http://localhost/ProyectoAdmin/admin/export_to_excel.php?id=1&searchtype_id=2";
$local_file_path = './xls_tmp/Report.xls';
$xlsFile = file_get_contents($url);
file_put_contents($file_path,$xlsFile);
?>
I'd really appreciate any hint.
You're missing an end quote on your second line.
It should be: $local_file_path = './xls_tmp/Report.xls';