How can I write this multiple-count loop as a single query? - php

Question

I'm really stumped here, I've tried using:
sum(case when date_format(from_unixtime(l.date_updated), '%Y-%m-%d') = date_format(now(), '%Y-%m-%d') then 1 else 0 end) AS day0_leads,
in my query, and it did not work as intended, so I ended up using this:
<?php
$total_days = '14';
for ($i = $total_days - 1; $i >= 0; $i--)
{
$day = strtotime('-'.$i.' days');
$day_string = date('n/j', $day);
$leads = mysql_result(mysql_query("select count(*) from `leads` where date_format(from_unixtime(`date_updated`), '%m-%d-%Y') = date_format(from_unixtime($day), '%m-%d-%Y')"), 0);
$assigns = mysql_result(mysql_query("select count(*) from `assigns` where date_format(from_unixtime(`date_assigned`), '%m-%d-%Y') = date_format(from_unixtime($day), '%m-%d-%Y') and `id_dealer` not in (1,2,3)"), 0);
echo "['$day_string', $leads, $assigns]";
if ($i > 0)
echo ',';
}
?>
It is making the page load slow, obviously due to unnecessary queries. What is the proper way of writing this as a single query and outputting the results? Like I said, I've tried a sum with a then else, and it did not product the correct numbers.
Any help would greatly be appreciated.

Answer 1

Heres my solution:
$total_days = '14';
// get leads count array
$sql = mysql_query("select count(*) as `count`, `date_updated`
from `leads`
where date_format(from_unixtime(`date_updated`), '%Y-%m-%d') >= date_format(now() - interval $total_days day, '%Y-%m-%d')
group by date(from_unixtime(`date_updated`));") or die(mysql_error());
$leads_count = array();
while ($row = mysql_fetch_assoc($sql))
$leads_count[date('n/j', $row['date_updated'])] = $row['count'];
// get assigns count array
$sql = mysql_query("select count(*) as `count`, `date_assigned`
from `assigns`
where date_format(from_unixtime(`date_assigned`), '%Y-%m-%d') >= date_format(now() - interval $total_days day, '%Y-%m-%d') and `id_dealer` not in (1,2,3,4)
group by date(from_unixtime(`date_assigned`));") or die(mysql_error());
$assigns_count = array();
while ($row = mysql_fetch_assoc($sql))
$assigns_count[date('n/j', $row['date_assigned'])] = $row['count'];
for ($i = $total_days - 1; $i >= 0; $i--)
{
$day = strtotime('-'.$i.' days');
$day_string = date('n/j', $day);
$leads = ((empty($leads_count[$day_string])) ? '0' : $leads_count[$day_string]);
$assigns = ((empty($assigns_count[$day_string])) ? '0' : $assigns_count[$day_string]);
echo "['$day_string', $leads, $assigns]";
if ($i > 0)
echo ',';
}