Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about programming within the scope defined in the help center.
Closed 9 years ago.
Improve this question
I've a table with some records like this
date price
01/02/2000 20
02/02/2000 20
03/02/2000 20
the user will choose on my site the date of check-in and out. For example:
check-in: 01/02
check-out: 02/02
I' can i do a function that count the day from 01/02 to 02/02, and sum the price of the 2 days?
Thanks a lot
Pretty simple SQL to calculate the count and sum of the fields between your dates:
SELECT COUNT(*) AS count_dates, SUM(price) AS total_price
FROM your_table
WHERE date >= '01/02/2000'
AND date <= '02/02/2000'
Well, this is not enough infromation what you realy want to get. But my best gues:
SELECT SUM(Price), Count(*) as count_day
Where date>check-in and date<check-out
Related
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 2 years ago.
Improve this question
I need to show monthly average of total using SQL and PHP.
For example this table has total=254 in June & total=315 in July. I need to show their average i.e. (254+315)/2= 284.5
What SQL query should I make to print their average using PHP?
One method is:
select sum(total) / count(distinct extract(year_month from date))
from t;
This sums the total column and divides by the number of months. If you need this for the particular two months, then include a where clause:
select sum(total) / count(distinct extract(year_month from date))
from t
where date >= '2020-06-01' and date < '2020-08-01'
If you wanted to count missing months as 0 for the average purposes, then use a constant:
select sum(total) / 2
from t
where date >= '2020-06-01' and date < '2020-08-01'
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
I have got the mysql table which includes data about users who visited my web service (IP address, date). The one IP address can be logged in my database only once per day.
What is the best way to create the table contains visits from last month? I want something like:
30.10.2016 | 1457
31.10.2016 | 1604
01.11.2016 | 1590
etc
Sorry for English and maybe the very simple question, first time on stack :)
use this sql code to create a table for last month visitor count.
CREATE TABLE last_mon_visit AS
SELECT DISTINCT date, COUNT(ip_address)
FROM visit
WHERE YEAR(date) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(date) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)
GROUP BY date
i would suggest to create view instead of table.
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 6 years ago.
Improve this question
I have 2 columns in mysql database i.e. totalRating and ratingDate. There exists multiple values of totalRating against on date e.g. there can be 5 totalRatings on date 2016-08-29, 4 on 2016-08-30. I am using ChartJs to show a graph of totalRating and ratingDate. I want to take the average of totalRatings of a single date and plot it on graph i.e. one totalRating for one date. I am using PHP for the backend. Can somebody help me with the queries?
Using below query you can find average rating for all dates.
select AVG(totalRatings) as avgRating, date from YOUR_TABLE group by date;
I think what you need is the AVG mysql function, your query should be something like:
select AVG(totalRatings) from YOUR_TABLE where date=YOUR_DATE;
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 8 years ago.
Improve this question
What i want to do is to limit a user to deposit/withdraw money in the account only 5 times a week , and after the 5 times user must wait next week to be able to deposit again.
I have a table named depuser with the following rows : uid(userid), date(date of dep/witdraw), type(deposit/witdraw) and the amount. thanks in advance
This query will count the # of deposits recorded in the last 7 days, based on your table structure:
SELECT COUNT(uid) AS total_deposits FROM depuser
WHERE `type` LIKE 'deposit' AND
DATE(`date`) <= NOW() AND
DATE(`date`) >= DATE_SUB( NOW(), INTERVAL 7 DAY)`
From here you can compare the total_deposits value returned and make logic decisions.
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
I can't find an answer to my question, it's probably easy but... anyway!
I have a database with every NHL game for one specific team in a table. Every game has been entered in the good order.
On my home page, I would like to display the upcoming game as well as the result of the previous game. How can I create a mySQL query to display the previous game based on today's date?
Thanks!
Do your game records have a timestamp or datetime value?
If so you could write a query ordering your games by the date smaller that now() and limit by one.
The query should look like this:
select * from games where gamedate < now() order by gamedate desc limit 1