PHP echo values outside conditional if - php

Question

I have the following PHP code:
<?php
//Connection to PDO Database
?>
<form method="post" action="">
<p>Busisness telephone 1</p><input id="business_telephone_01" name="business_telephone_01" tabindex="auto" value="<?php echo $result['business_telephone_01']; ?>" type="text" />
<input name="submit" type="submit" value="Save Changes"></form>
<?php
//Get from Form
if((empty($_POST['submit']) === false)){
$business_telephone_01 = $_POST['business_telephone_01'];
//Formating of telephone numbers
$message = 'This message I want to display';
echo 'This is another message';
}
echo $message;
//Code to update table through PDO
?>
Regardless of where I do the echo whether it is echo 'This is another message'; within the conditional brackets or _ echo $message;_ outside the brackets nothing is being echoed and no error is being displayed.
The html form and the PDO are working correctly and are being updated but nothing is being echoed. No error is being shown in the error log.
UPDATE:
If I use if((empty($_POST['submit']) === false)){ I get PHP
Notice: Undefined variable: hello
If I use if (isset($_POST['submit'])) { I get PHP Notice:
Undefined variable: hello
If I use if (!isset($_POST['submit']))
{ it gives me a list of undefined variables that I use e.g. from
my code above business_telephone_01
My full code
if((empty($_POST['submit']) === false)){
//Get from Form
$address_building_name = $_POST['address_building_name'];
$address_building_number = $_POST['address_building_number'];
$address_street = $_POST['address_street'];
$address_locality = $_POST['address_locality'];
$address_postcode = $_POST['address_postcode'];
$address_country = $_POST['address_country'];
//Formating of address
$address_building_number = strtoupper($address_building_number);
$address_building_number = str_replace(' ','',$address_building_number);
$address_building_name = ucwords($address_building_name);
$address_street = ucwords($address_street);
$address_locality = ucwords($address_locality);
$address_postcode = strtoupper($address_postcode);
$address_country = ucwords($address_country);
echo 'Hello';
$good = 'Good bye';
}
echo $good;

Answer 1

I'd be willing to bet $message isn't being echo'd because it's never initialized. (The if block, where it is supposed to be initialized, is not being executed because the conditional is failing.)
First off, you should use isset to determine if a POST variable has been submitted:
if (isset($_POST['submit'])) {
Or, to see if it has not been submitted:
if (!isset($_POST['submit'])) {
Secondly, you should enable error reporting on your program and let us know what errors (if any) you are getting:
error_reporting(E_ALL);
ini_set("display_errors", 1);
You can add these two lines to the very top of your script, right after the opening <?php line, which should help shed some light on the situation.

Answer 2

The problem could be that the $message variable is never set within your if statement.
If the 'if' condition is not matched, then $message is never set and you will not be able to echo the value.
To test, you could set the $message variable to some value before you start your if statement.
$message = 'condition failed';
if(isset($_POST['submit'])){
....
$message = 'This message I want to display';
}
echo $message;
If the condition is met, it will echo "This message I want to display".
If the condition fails, it will echo 'condition failed';
A quick dirty test, but it will tell you if the $message variable will be initialized inside your 'if' statement.