I have a string
$k="My name is Alice[1]";
What i want is to remove "[1]" from my string Using minimum steps,So that sentence will look like
$k="My name is Alice";
So antything that come inside [] should be removed.
Use this:
$text = preg_replace('/\[[0-9]+\]/','',$text);
You can use preg_replace for this.
echo preg_replace('/\[[0-9]+\]/','',$str);
Do this:
$k="My name is Alice[1]";
$k = preg_replace('/\[[0-9]+\]/','',$k);
Related
I have URL of file which looks like this
movieImages/1`updateCategory.PNG
it should look like this
updateCategory.PNG
you can use like this, simple
$string = 'movieImages/1`updateCategory.PNG';
$ser = 'movieImages/1`';
$trimmed = str_replace($ser, '', $string);
echo $trimmed;
output will be updateCategory.PNG
Find the position of unwanted character and then pick up the substring after that position.
$str="movieImages/1`updateCategory.PNG";
$unwanted="`";
echo substr($str,strpos($str,$unwanted)+1);
Output
updateCategory.PNG
Fiddle
That is if the string can vary in structure and size. If the first part will always remain same you can simply remove the unwanted stuff using str_replace.
echo str_replace('movieImages/1`','',$str);
I am trying to replace smileycodes by a img tag.
I want to replace this:
:blush:
by:
<img src='images/blush.png' />
"blush" is a variabele, so it can be any smiley.
I have to replace everything between the colons. I am not familiar with regex.
Can you help me?
For multiple replacements you could use str_replace with arrays instead of strings to search for, having an array for smiley-codes to be replaced by values of the second array. But you need to configure all values in arrays what is kind of static.
Another solution was to loop over possible smiley-codes and do a str_replace for each of it:
$possibleCodes = array('blush', 'smiley2', 'smiley3');
foreach($possibleCodes as $code) {
str_replace(':'.$code.':', "<img src='images/".$code.".png'", $yourString);
}
This requires to have the image name same as the smiley-code.
Why use regex if you aren't familiar with it? It is very simple and easy to do without regex.
str_replace(":blush:", "<img src='images/blush.png' />", $myString);
You can use preg_replace like as
preg_replace('~(:blush:)~','<img src="images/blush.png" />',$your_string);
Edited
If you had an array of string to replace then you can simply use str_replace like as
$find_array = array('blush', 'smiley2', 'smiley3');
$replace_array = ['<img src="images/blush.png" />','<img src="images/smiley2.png" />','<img src="images/smiley3.png" />']
str_replace($find_array,$replace_array,$your_string);
A column in my spreadsheet contains data like this:
5020203010101/FIS/CASH FUND/SBG091241212
I need to extract the last part of string after forwward slash (/) i.e; SBG091241212
I tried the following regular expression but it does not seem to work:
\/.*$
Any Idea?
Try this:
'/(?<=\/)[^\/]*$/'
The reason your current REGEXP is failing is because your .* directive matches slashes too, so it anchors to the first slash and gives you everything after it (FIS/CASH FUND/SBG091241212).
You need to specify a matching group using brackets in order to extract content.
preg_match("/\/([^\/]+)$/", "5020203010101/FIS/CASH FUND/SBG091241212", $matches);
echo $matches[1];
You could do it like this without reg ex:
<?php
echo end(explode('/', '5020203010101/FIS/CASH FUND/SBG091241212'));
?>
this will do a positive lookbehind and match upto a value which does not contain a slash
like this
[^\/]*?(?<=[^\/])$
this will only highlight the match . i.e. the last part of the url
demo here : http://regex101.com/r/pF8pS2
Make use of substr() with strrpos() as a look behind.
echo substr($str,strrpos($str,'/')+1); //"prints" SBG091241212
Demo
You can 'explode' the string:
$temp = explode('/',$input);
if (!empty($temp)){
$myString = $temp[count($temp)-1];
}
You can also use:
$string = '5020203010101/FIS/CASH FUND/SBG091241212';
echo basename($string);
http://www.php.net/manual/en/function.basename.php
I am trying to use a License PHP System…
I will like to show the status of their license to the users.
The license Server gives me this:
name=Service_Name;nextduedate=2013-02-25;status=Active
I need to have separated the data like this:
$name = “Service_Name”;
$nextduedate = “2013-02-25”;
$status = “Active”;
I have 2 days tring to resolve this problem with preg_match_all but i cant :(
This is basically a query string if you replace ; with &. You can try parse_str() like this:
$string = 'name=Service_Name;nextduedate=2013-02-25;status=Active';
parse_str(str_replace(';', '&', $string));
echo $name; // Service_Name
echo $nextduedate; // 2013-02-25
echo $status; // Active
This can rather simply be solved without regex. The use of explode() will help you.
$str = "name=Service_Name;nextduedate=2013-02-25;status=Active";
$split = explode(";", $str);
$structure = array();
foreach ($split as $element) {
$element = explode("=", $element);
$$element[0] = $element[1];
}
var_dump($name);
Though I urge you to use an array instead. Far more readable than inventing variables that didn't exist and are not explicitly declared.
It sounds like you just want to break the text down into separate lines along the semicolons, add a dollar sign at the front and then add spaces and quotes. I'm not sure you can do that in one step with a regular expression (or at least I don't want to think about what that regular expression would look like), but you can do it over multiple steps.
Use preg_split() to split the string into an array along the
semicolons.
Loop over the array.
Use str_replace to replace each '=' with ' = "'.
Use string concatenation to add a $ to the front and a "; to the end of each string.
That should work, assuming your data doesn't include quotes, equal signs, semicolons, etc. within the data. If it does, you'll have to figure out the parsing rules for that.
When I've a string:
$string = 'word1="abc.3" word2="xyz.3"';
How can I replace the point with a comma after xyz in xyz.3 and keep him after abc in abc.3?
You've provided an example but not a description of when the content should be modified and when it should be kept the same. The solution might be simply:
str_replace("xyz.", "xyz", $input);
But if you explicitly want a more explicit match, say requiring a digit after the ful stop, then:
preg_replace("/xyz\.([0-9])+/", 'xyz\${1}', $input);
(not tested)
something like (sorry i did this with javascript and didn't see the PHP tag).
var stringWithPoint = 'word1="abc.3" word2="xyz.3"';
var nopoint = stringWithPoint.replace('xyz.3', 'xyz3');
in php
$str = 'word1="abc.3" word2="xyz.3"';
echo str_replace('xyz.3', 'xyz3', $str);
You can use PHP's string functions to remove the point (.).
str_replace(".", "", $word2);
It depends what are the criteria for replace or not.
You could split string into parts (use explode or preg_split), then replace dot in some parts (eg. str_replace), next join them together (implode).
how about:
$string = 'word1="abc.3" word2="xyz.3"';
echo preg_replace('/\.([^.]+)$/', ',$1', $string);
output:
word1="abc.3" word2="xyz,3"