SELECT RECORDS INTO ARRAY - php

Question

I'm neubie with PHP. I need to build some Web Service so, I have problems.. please help me.
I have this code, I have to put in array the Select's records and the return in JSON.
The CODE...
function redeem() {
// Check for required parameters
if (isset($_POST["id_cliente"]) && isset($_POST["id_sucursal"])) {
// Put parameters into local variables
$cliente = $_POST["id_cliente"];
$sucursal = $_POST["id_sucursal"];
$stmt = $this->db->prepare('SELECT id_arbitro FROM arbitro WHERE id_cliente =? AND id_sucursal =?') or die(mysqli_error($this->db));
$stmt->bind_param("ii", $cliente, $sucursal);
$stmt->execute();
//$stmt->bind_result($id_arbitro);
$result = $stmt->fetchAll(PDO::FETCH_ASSOC);
$cuantos = count($result);
echo "$cuantos";
$registros = 0;
/*while ($stmt->fetch()) {
$registros ++;
// Return unlock code, encoded with JSON
$result = array("id_arbitro" => $stmt,);
echo "$id_arbitro !";
}
*/
$stmt->close();
if ($registros < 0) {
sendResponse(400,"No existen arbitros con los parámetros recibidos");
return false;
}
//echo json_encode($result);
sendResponse(200, "FIN");
//printf("ERROR %s",$registros);
return true;
}
sendResponse(400, 'Invalid request');
return false;
}

Answer 1

To encode the results of your query, use something like that
$statement=$pdo->prepare("SELECT * FROM table");
$statement->execute();
$results=$statement->fetchAll(PDO::FETCH_ASSOC);
$json=json_encode($results);

Answer 2

Based on your comment, you're having trouble understanding how to put them all into an array.
First, make sure that whatever you use for database calls doesn't already have a fetchAll style function that could do this for you.
If you still need to do, you need to define an array first and then add to it:
$results = array();
while ($record = $stmt->fetch()) {
$registros ++;
$results[] = $record;
}
print json_encode($results);
The syntax might vary slightly for your database class but this gives you an idea.