PHP: Echo next 2 lines after finding one - php

<?php
$handle = fopen("wqer.txt", "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
if(preg_match("/aut/i", $line)){
**echo fgets($handle).fgets($handle);**
}
}
} else {
echo "Error loading file.";
}
?>
The textfile wqer.txt looks something like that (but it has 12k lines :D):
bike
*aut*
car
ball
mouse
*aut*
light
house
I want from this script to echo next 2 lines after finding the aut line from this file.
So the output should look like this:
car
ball
light
house
Yep sorry, house should be the last one.
Solved, many thanks to Wrikken, simple solution, I almost feel embarrased :)

$found = 0;
while (($line = fgets($handle)) !== false) {
if(preg_match("/aut/i", $line)){
$found = 2;
continue; // if you don't want "aut" to be printed. remove otherwise.
}
if ($found > 0) {
echo $line;
$found--;
}
}

Add error checking:
$lines = file("wqer.txt", FILE_IGNORE_NEW_LINES);
$lines = array_map('trim', $lines); //in case there are spaces etc. that are not shown
foreach($lines as $key => $val) {
if($val == '*aut*') { //(stripos($val, 'aut') !== false) //to keep similar to how you have it now
echo $lines[$key+1] . "\n" . $lines[$key+2] . "\n";
}
}

Related

Simple string comparison shows wrong results

It sounds very simple and it should be but I've got some issue and can't find it.
I have a file with words on each line, like
dog
dog
dog
dogfirend
dogandcat
dogcollar
dog-food
The above should display me: 3 (since there are only 3 full matches of dog)
I'm trying to read the file and check how many times the word dog is inside. The problem is that it doesn't count at all and shows 0. This is what I have
$word = "dog";
$count = 0;
$handle = fopen("dogs.txt", "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
if ($word == $line) {
$count++;
}
}
fclose($handle);
}
The lines in your file are separated by a newline. This newline is included in your $line variable.
From the fgets() manual: "Reading ends when length - 1 bytes have been read, or a newline (which is included in the return value), or an EOF (whichever comes first)."
You need to trim() your $line first, so those characters get removed:
$word = "dog";
$count = 0;
$handle = fopen("dogs.txt", "r");
if ($handle) {
while (($line = fgets($handle)) !== false) {
if ($word == trim($line)) {
$count++;
}
}
fclose($handle);
}
echo $count

foreach doesn't stop the loop on break

I'm trying to post 3 arrays using foreach and for some reason the break at the end isn't working and it outputs the whole list (40+) on to the page.
$file = fopen('names.csv', 'r');
while (($line = fgetcsv($file)) !== FALSE) {
//$line is an array of the csv elements
shuffle($line);
$i = 0;
foreach ($line as $number) {
{
if($i==3){ break; } else {
$rtime = mt_rand(1, 7);
echo $number; }
$i++;
}
}
}
fclose($file);
This is kind of how it looks: take.ms/cLgIh, instead it should only show 3 of these usernames.
<?php
$i = 0;
//I have opened my contact.csv :P
$file = fopen('contact.csv', 'r');
while (($line = fgetcsv($file)) !== FALSE) {
//$line is an array of the csv elements
shuffle($line);
foreach ($line as $number) {
{
if($i==3){ exit(); } else {
$rtime = mt_rand(1, 7);
echo "<br/> i = ".$i.$number.", "; }
}
$i++;
}
}
fclose($file);
?>
I have downloade first sample CSV from here:-http://www.sample-videos.com/download-sample-csv.php
And this code works for me:-
<?php
$file = fopen('SampleCSVFile_2kb.csv', 'r');
while (($line = fgetcsv($file)) !== FALSE) {
//$line is an array of the csv elements
shuffle($line);
$i = 0;
foreach ($line as $number) {
if($i==3){
exit;
} else {
$rtime = mt_rand(1, 7);
echo $number.'<br/>';
echo $i.'<br/>'; // you can remove this line
}
$i++;
}
}
fclose($file);
?>
Output on each page refresh:-
http://prntscr.com/cln2ju
http://prntscr.com/cln2nf
Note:- if still not work then check your CSV file. May be it is corrupted.
Conclusion:- And after all discussion it comes to an end that your CSV file is corrupted. But yes code improvement is needed too
You need to increment $i otherwise it's value will always be 0
$i = 0;
foreach ($line as $number) {
$rtime = mt_rand(1, 7);
echo "$number";
if($i==3) break;
$i++;
}
Also you need to check if your while statement is closing
$file = fopen('names.csv', 'r');
while (($line = fgetcsv($file)) !== FALSE) {
//$line is an array of the csv elements
shuffle($line);
$i = 0;
foreach ($line as $number) {
$rtime = mt_rand(1, 7);
echo $number;
if($i==3) break;
$i++;
}
} //check for this
As I can see in your code example it is missing the closing brace
Also, remove the double quotes from your $number, it's not necessary.
echo $number
You have a mistake is that the break are in the if($i==3) and you declared $i =0, but never increment this. So $i never arrive at 3.

Find string in file and display lines number

I'm new at PHP so I'm need help to build this script.
I have a file.txt file with following lines:
aaaa 1234
bbba 1234
aaaa 1236
cccc 1234
aaaa 1238
dddd 1234
I want to find the line with string "aaaa" and print:
String "aaaa" found 3 times at lines: 1, 3, 5.
And better it can print these lines.
I tried this code:
<?
function find_line_number_by_string($filename, $search, $case_sensitive=false ) {
$line_number = '';
if ($file_handler = fopen($filename, "r")) {
$i = 0;
while ($line = fgets($file_handler)) {
$i++;
//case sensitive is false by default
if($case_sensitive == false) {
$search = strtolower($search); //convert file and search string
$line = strtolower($line); //to lowercase
}
//find the string and store it in an array
if(strpos($line, $search) !== false){
$line_number .= $i.",";
}
}
fclose($file_handler);
}else{
return "File not exists, Please check the file path or filename";
}
//if no match found
if(count($line_number)){
return substr($line_number, 0, -1);
}else{
return "No match found";
}
}
$output = find_line_number_by_string('file.txt', 'aaaa');
print "String(s) found in ".$output;
?>
But I dont know how to count total of strings found (3) and print each found line.
Thank in advance.
There are lots of ways to do this that produce the same final result but differ in the specifics.
Assuming that your input is not large enough that you are concerned about loading it in memory all at once, one of the most convenient approaches is to use file to read the file's contents into an array of lines, then preg_grep to filter the array and only keep the matching lines. The resulting array's keys will be line numbers and the values will be whole lines that matched, perfectly fitting your requirements.
Example:
$lines = file('file.txt');
$matches = preg_grep('/aaaa/', $lines);
echo count($matches)." matches found.\n";
foreach ($matches as $line => $contents) {
echo "Line ".($line + 1).": ".$contents."\n";
}
$str = "aaaa";
$handle = fopen("your_file.txt", "r");
if ($handle) {
echo "String '".$str."' found at lines : ";
$count = 0;
$arr_lines = array();
while (($line = fgets($handle)) !== false) {
$count+=1;
if (strpos($line, $str) !== false) {
$arr_lines[] = $count;
}
}
echo implode(", ", $arr_lines).".";
}
UPDATE 2 :
$file = "your_file.txt";
$str = "aaaa;";
$arr = count_line_no($file, $str);
if(count($arr)>0)
{
echo "String '".$str."' found at lines : ".implode(", ", $arr).".";;
}
else
{
echo "String '".$str."' not found in file ";
}
function count_line_no($file, $str)
{
$arr_lines = array();
$handle = fopen("your_file.txt", "r");
if ($handle) {
$count = 0;
$arr_lines = array();
while (($line = fgets($handle)) !== false) {
$count+=1;
if (strpos($line, $str) !== false) {
$arr_lines[] = $count;
}
}
}
return $arr_lines;
}
**Try it for solve your problam **
if(file_exists("file.txt")) // check file is exists
{
$f = fopen("file.txt", "r");
// Read line by line until end of file
$row_count = 0;
while(!feof($f))
{
$row_count += 1;
$row_data = fgets($f);
$findme = 'aaaa';
$pos = strpos($row_data, $findme);
if ($pos !== false)
{
echo "The string '$findme' was found in the string '$row_data'";
echo "<br> and line number is".$row_data;
}
else
{
echo "The string '$findme' was not found ";
}
}
fclose($f);
}

Search String and Return Line PHP

I'm trying to search a PHP file for a string and when that string is found I want to return the whole LINE that the string is on. Here is my example code. I'm thinking I would have to use explode but cannot figure that out.
$searchterm = $_GET['q'];
$homepage = file_get_contents('forms.php');
if(strpos($homepage, "$searchterm") !== false)
{
echo "FOUND";
//OUTPUT THE LINE
}else{
echo "NOTFOUND";
}
Just read the whole file as array of lines using file function.
function getLineWithString($fileName, $str) {
$lines = file($fileName);
foreach ($lines as $lineNumber => $line) {
if (strpos($line, $str) !== false) {
return $line;
}
}
return -1;
}
You can use fgets() function to get the line number.
Something like :
$handle = fopen("forms.php", "r");
$found = false;
if ($handle)
{
$countline = 0;
while (($buffer = fgets($handle, 4096)) !== false)
{
if (strpos($buffer, "$searchterm") !== false)
{
echo "Found on line " . $countline + 1 . "\n";
$found = true;
}
$countline++;
}
if (!$found)
echo "$searchterm not found\n";
fclose($handle);
}
If you still want to use file_get_contents(), then do something like :
$homepage = file_get_contents("forms.php");
$exploded_page = explode("\n", $homepage);
$found = false;
for ($i = 0; $i < sizeof($exploded_page); ++$i)
{
if (strpos($buffer, "$searchterm") !== false)
{
echo "Found on line " . $countline + 1 . "\n";
$found = true;
}
}
if (!$found)
echo "$searchterm not found\n";
If you use file rather than file_get_contents you can loop through an array line by line searching for the text and then return that element of the array.
PHP file documentation
You want to use the fgets function to pull an individual line out and then search for the
<?PHP
$searchterm = $_GET['q'];
$file_pointer = fopen('forms.php');
while ( ($homepage = fgets($file_pointer)) !== false)
{
if(strpos($homepage, $searchterm) !== false)
{
echo "FOUND";
//OUTPUT THE LINE
}else{
echo "NOTFOUND";
}
}
fclose($file_pointer)
Here is an answered question about using regular expressions for your task.
Get line number from preg_match_all()
Searching a file and returning the specified line numbers.

How to get a recuring parts from a file in php

I have a file file.txt. This file has portions and parts that recur throughout the file. I
am trying to read the parts between the last and the first key words.
I have managed to get the first and the last key words but I can't read the lines between the key words.
Here is my script
$file=file('file.txt');
$begin = 'first_line';
$end='last_line';
foreach ($file as $lineNumber => $line) {
$lineNumber++;
if (strpos($line,$begin))
{
echo $lineNumber.$line."<br/>";
}
elseif (strpos($line,$end))
{
echo $value."<br/>";
}
echo $lineNumber. $line."<br/>";
}
Please some one assist me.
Here you go:
$lines=file('data.txt');
$begin = 'first_line';
$end='last_line';
$switch = false;
$content = "";
foreach ($lines as $line_num => $line) {
if(strpos($line, $begin) !== false) {$switch = true;continue;}
if(strpos($line, $end) !== false) $switch = false;
if(!$switch) continue;
$content .= "Line #<b>{$line_num}</b> : " . htmlspecialchars($line) . "<br />\n";
}
echo $content;
This will do it:
$file = file('file.txt');
$begin = 'first_line';
$end = 'last_line';
$isInside = false;
foreach ($file as $lineNumber => $line)
{
$lineNumber++;
if (!(strpos($line,$begin)===false))
$isInside = true;
if ($isInside)
echo $lineNumber." : ".$line."<br/>";
if (!(strpos($line,$end)===false))
$isInside = false;
}
Some points:
You were displaying everything regardless, my script only shows lines between $begin and $end.
Your comparison is case-sensitive
You had a major bug using strpos and assuming it returns true if it matches. It could also return 0 if the string matches at the beginning,hence using === to catch this. See the disclaimer on the strpos page.
$file=fopen("welcome.txt","r");
while(!feof($file))
{
$open=fgets($file);
print $open;
}
fclose($file);

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