Using PHP write an anagram function? - php

Question

Using PHP write an anagram function? It should be handling different phrases and return boolean result.
Usage:
$pharse1 = 'ball';
$pharse2 = 'lbal';
if(is_anagram($pharse1,$pharse2)){
echo $pharse1 .' & '. $pharse2 . ' are anagram';
}else{
echo $pharse1 .' & '. $pharse2 . ' not anagram';
}

Answer 1

There's simpler way
function is_anagram($a, $b) {
return(count_chars($a, 1) == count_chars($b, 1));
}
example:
$a = 'argentino';
$b = 'ignorante';
echo is_anagram($a,$b); // output: 1
$a = 'batman';
$b = 'barman';
echo is_anagram($a,$b); // output (empty):

Answer 2

function is_anagram($pharse1,$pharse2){
$status = false;
if($pharse1 && $pharse2){
$pharse1=strtolower(str_replace(" ","", $pharse1));
$pharse2=strtolower(str_replace(" ","", $pharse2));
$pharse1 = str_split($pharse1);
$pharse2 = str_split($pharse2);
sort($pharse1);
sort($pharse2);
if($pharse1 === $pharse2){
$status = true;
}
}
return $status;
}

Answer 3

function check_anagram($str1, $str2) {
if (count_chars($str1, 1) == count_chars($str2, 1)) {
return "This '" . $str1 . "', '" . $str2 . "' are Anagram";
}
else {
return "This two strings are not anagram";
}
}
ECHO check_anagram('education', 'ducatione');

Answer 4

I don't see any answers which have addressed the fact that capital letters are different characters than lowercase to count_chars()
if (isAnagram('Polo','pool')) {
print "Is anagram";
} else {
print "This is not an anagram";
}
function isAnagram($string1, $string2)
{
// quick check, eliminate obvious mismatches quickly
if (strlen($string1) != strlen($string2)) {
return false;
}
// Handle uppercase to lowercase comparisons
$array1 = count_chars(strtolower($string1));
$array2 = count_chars(strtolower($string2));
// Check if
if (!empty(array_diff_assoc($array2, $array1))) {
return false;
}
if (!empty(array_diff_assoc($array1, $array2))) {
return false;
}
return true;
}

Answer 5

here is my variant :
public function is_anagram($wrd_1, $wrd_2)
{
$wrd_1 = str_split ( strtolower ( utf8_encode($wrd_1) ) );
$wrd_2 = str_split( strtolower ( utf8_encode($wrd_2) ) );
if ( count($wrd_1)!= count($wrd_2) ) return false;
if ( count( array_diff ( $wrd_1 ,$wrd_2) ) > 0 ) return false;
return true;
}

Answer 6

Heheh little large but work as well :)
public static function areStringsAnagrams($a, $b)
{
//throw new Exception('Waiting to be implemented.');
$a = str_split($a);
$test = array();
$compare = array();
foreach ($a as $key) {
if (!in_array($key, $test)) {
array_push($test, $key);
$compare[$key] = 1;
} else {
$compare[$key] += 1;
}
}
foreach ($compare as $key => $value) {
if ($value !== substr_count($b, $key)) {
return false;
}
}
return true;
}