sort mysql rows by column? - php

Question

I have following sql query:
SELECT job_id, job_type FROM jobs
I'm getting the following result (set of rows) from mysql query:
RESULT (print_r):
Array
(
[0] => stdClass Object
(
[job_id] => 239
[job_type] => 'type1';
}
[1] => stdClass Object
{
[job_id] => 53
[job_type] => 'type2';
}
[2] => stdClass Object
{
[job_id] => 76
[job_type] => 'type3';
}
[3] => stdClass Object
{
[job_id] => 78
[job_type] => 'type1';
}
)
As you can see I've got three types of job: type1, type2, type3
Is there any way to map/regroup these results by job_type?
Basically I'd like to have something similar to this:
Array
(
['type1'] => Array (
[0] => stdClass Object
{
[job_id] => 239
[job_type] => 'type1';
}
[1] => stdClass Object
{
[job_id] => 76
[job_type] => 'type1';
}
)
['type2'] => Array (
[0] => stdClass Object
{
[job_id] => 53
[job_type] => 'type2';
}
)
['type3'] => Array (
[0] => stdClass Object
{
[job_id] => 78
[job_type] => 'type3';
}
)
)
Or maybe I should use different query?
I've tried to use array_map() with no luck, but I was getting only one array with elements from only one job_type.
Thanks in advance.

Answer 1

You cannot do this with predefined PHP functions. But you can do it yourself pretty easily.
For example: Assuming you have your MySQL result as written in your question in a variable called $rows, you can do the following to get the desired map.
$map = array();
foreach($rows as $row) {
if (!isset($map[$row->job_type])) {
$map[$row->job_type] = array($row);
} else {
$map[$row->job_type][] = $row;
}
}
Now $map contains your desired array.

Answer 2

Unfortunately for this task does not have a native solution in pure PHP/MySQL. So You need to sort it on PHP side manualy. I think You should write function for this an use it when You need
function sortBy($array, $key, $sortKeys=false){
// I don't test this function, just write it for answer, so it may contain errors
$tmp = array();
foreach($array as $k=>$v){
$tmp[$array[$k][$key]][] = $v;
}
if($sortKeys)
ksort($tmp);
return $tmp;
}
And use it like
print_r(sortBy(mySQLSelect(),'job_type'));