i have tag in cakephp like this:
var url_save = "<?php echo $this->Html->url(array('controller' => 'users','action' => 'save_template')) ;?>";
$.ajax({
url : url_save,
type : "POST",
data : JSON.stringify(templates),
dataType : 'json'
});
how the controller can take the data value?
You can use $this->request->data on the Controller the usual way.
you can get json data using $this->data in controller, you can check if the request is ajax if you want using $this->RequestHandler->isAjax() but you must also add RequestHandler in component variable.
Related
I'm using Ajax to get and display content in a Laravel view. I'd like to know how I can access the second parameter in the URL. It's currently giving me back a random string:
for(var i=0;i<array.length;i++){
html+="<a href={{ route('showAnnouncement',"array[i].id_announcement") }}>";
}
When I alert array{i].id_announcement I get its value, but it doesn't pass in the URL.
Thank you!
You can't access a JS value inside a php code.
{{route('showAnnouncement',"array[i].id_announcement") }}
This not possible, If you are making ajax request you try something like this below.
var an_id = array[i].id_announcement;
$.ajax({
url: '{{route('showAnnouncement')}}',
data: {'an_id':an_id },
type: 'POST',
success: function (result)
{
}
});
Route
Route::post('showAnnouncement/{an_id?}', ['as' => 'showAnnouncement', 'uses' => 'YourController#showAnnouncement']);
Guys finally I found a solution and it worked like a charm
for(var i=0;i<array.length;i++){
var url = '{{ route("showAnnouncement", ":id") }}';
url = url.replace(':id', array[i].id_announcement);
html+="<a href='"+url+"'>";
I'm trying to return a query made in a controller to the view file so I can use that data in my form. But I am unable to successfully return the data without errors. I know the function is working because it returns the right data but has an error.
Here is my CustomersController fill function which is running the sql query.
public function fill(){
$layout = 'ajax';
$this->autoRender = false;
if ($this->request->is('post')) {
$id = $this->request->data['id'];
$query = $this->Customers->find()
->where([
'id' => $id
])->first();
echo json_encode($query);
}
}
and here is my blah.ctp which is the view file.
<?php use Cake\Routing\Router; ?>
<?= $this->Form->create(Null, ['type' => 'POST']) ?>
<?php
echo $this->Form->input('customer_id', ['options' => $customers, 'empty' => true,'id'=>'customers']);
?>
<?= $this->Form->end() ?>
<script>
document.getElementById('customers').addEventListener('change',function(){
var id = this.value;
var csrfToken = $('[name=_csrfToken]').val();
$.ajax({
type: "POST",
url: '<?php echo Router::url(array("controller" => "Customers", "action" => "fill")); ?>',
data: {'id' : id},
beforeSend: function(xhr){
xhr.setRequestHeader('X-CSRF-Token', csrfToken);
},
success: function(data){
alert(data);
}
});
});
</script>
Currently this is what happens when I select a customer in my drop down box which triggers the script in the view.
As you can see it returns the array of data I need but also has the error cannot emit headers. I have tried solving this error following other questions on stack overflow but can't solve it.
I've tried using $this->set instead of echo json_encode but it always returns nothing. I'm not sure what other way to do this.
First of all, If you're selecting a single record by a unique ID, you can call
->get($id) on the table object directly, instead of building a query chain with ->find().
CakePHP 3.x should automatically handle converting your view to JSON by using the RequestHandlerComponent. Typically, you must enable it if your scaffolding or installation didn't.
1) Enable request handler component. (If not already enabled) https://book.cakephp.org/3.0/en/controllers/components/request-handling.html
2) Remove the echo json_encode($query) line; you should not echo anything as this will break the request/response cycle. This is the cause of your error.
Instead, you should serialize your data to the view. Assuming you have the fetched data in $data: $this->set(compact('data')). Then, make sure you add $this->set('_serialize', ['data']) (again, assuming the data is stored in variable name 'data').
3) Reference this doc for information on how you can request the json. You can use a file extension (.json, .xml).
Also, make sure you add the 'Accept: application/json' header to your request.(https://book.cakephp.org/3.0/en/development/routing.html#Cake\Routing\Router::extensions).
I apologize for the fuzzy response. There are many ways to achieve this with CakePHP3. Please see this doc page for more information: https://book.cakephp.org/3.0/en/views/json-and-xml-views.html
This is in script .ready() function which fetch existing files from database and putting in jquery var splitfiles. which is in array formate.
var splitfiles = '<?php echo #$projectDetails->upload_file; ?>';
this line gives array of attached file from view in controller
$arrayoffiles = json_encode($joinfiles);
I want to get this splitfiles var in controller and then merge with $arrayoffiles after that store in database with other form data.
I tried with this solution to pass 'splitfiles' to controller by this bellow code but i am not getting in the controller
$(document).ready(function() {
$.ajax({
url: '<?php echo site_url("trusts/fundsRaisingModule"); ?>',
type: 'GET',
dataType: 'json',
data: {
splitfiles:splitfiles,
// key : value pair. You can send as many pair as you want like this
}
});
});
In controller i am not getting the 'splitfiles'
$files=$_REQUEST['splitfiles'];
giving error :undefined index 'splitfiles'
so help me to pass jquery variable from view to controller in codeigniter
after that i will try to merge the two arrays
Thanks in advance.
To achieve this use jquery ajax() and send the js variable to controller method and use it as you want.
Its syntax is:
$(document).ready(function(){
$.ajax({
url: 'controller_method',
type: 'POST',
data: {
splitfiles :splitfiles,
// key : value pair. You can send as many pair as you want like this
},
success: function(response){ // response from process
// do your stuff here
}
});
});
controller_method
$splitfiles = $_REQUEST['splitfiles'];
// do your stuff here
Note: Don't forget to add the jquery library in your code.
First send that jQuery variable into any hidden input of the view, and then get that input value into controller through GET or POST method.
i try to send a parameter with url to server with ajax in laravel 5.2 but when the length of url become more than 5000 char i face the error that Http not found in route
here is my ajax code :
$.ajax({
url: '/uploadQuestionMod5/',
type: 'GET',
data: {_token: CSRF_TOKEN , jcategory2:jcategory2 , jquestionText:jquestionText , jkind:jkind},
dataType: 'JSON',
success: function (data) {
}
});
and my controller is :
$jcategory2 = $request['jcategory2'];
$jquestionText = $request['jquestionText'];
$jkind = $request['jkind'];
$category2 = json_decode($jcategory2);
$questionText = json_decode($jquestionText);
$kind = json_decode($jkind);
$now = date("Y-m-d H:i:s");
$insertquestion = DB::table('questionsInfo')->insert(
['userId' => $userId ,'categoryId' => $category2 ,'questionKind' => $kind ,'questionText' => $questionText , 'questionFileUrl' => null ,'date' => $now]
);
i try to find the limit of url size in get method please help me thank you :)
Quick and Easy Solution try would be using AJAX POST not GET method.
Make your AJAX post and change your route (/uploadQuestionMod5/) in route file (/App/Http/routes.php) as
Route::match(['get', 'post'],'/uploadQuestionMod5', [
'uses'=>'YourController#method'
]);
Note: this route will accept both get and post ajax request.
If you only do post ajax then your route looks like:
Route::post('/uploadQuestionMod5', 'YourController#method');
This route will accept post request comming from ajax call or any toher source (Client)
Update: Token Mismatch Error means following
1. You have missed to submit CSRF tokens fields via AJAX post.
2. Tokens might have changed but you did not have refreshed your page, just making ajax request again and again.
It seems you are submitting your CSRF_TOKEN correctly, so refresh the page and try again to make ajax call.
It's been 2 days now and still I can't get this problem to work.
So basically I am trying to call a php function through jquery ajax
but nothing is working, I am not sure what is the problem is...
here are my codes
the ajax
$(document).ready(function() {
$("#idCheck1").click(function(){
$.ajax({
url:'../../../../Controller/PostsController.php',
data: {action: 'update_checkbox'},
success:function(result){
// $("#dsa").html(result);
}
});
});
});
the view
<?php echo $this->Form->create("Posts", array("action" => "update_checkbox", "id" => "checkingBox")) ?>
<td>
<?php
echo $this->Form->input('Post.' . $i . '.id', array("type" => "hidden", "label" => false, "value" => $sum['posts']['id']))
?>
<?php
echo $this->Form->input('Post.' . $i . '.done', array("type" => "checkbox", "label" => false, "value" => "1", "id" => "idCheck1"))
?>
</td>
</tr>
<?php
$i++;
}
?>
</table>
<?php echo $this->Form->end(); ?>
the controller
public function update_checkbox() {
// debug($this->data);
$var = $this->Post->saveCheckBox($this->data);
$this->set("result", $var);
}
the model
public function saveCheckBox($checkbox) {
debug($checkbox);
$this->saveAll($checkbox['Post']);
}
The url
url:'../../../../Controller/PostsController.php'
looks wrong. Since this is an AJAX request that goes through the browser you can't use relative paths that try to go upwards in the folder hierarchy, as browsers url's don't work that way. You should be making that request so that it is passed through a web server, i.e. the url should look like one of the following:
url:'http://localhost/Controller/PostsController.php'
or
url:'/Controller/PostsController.php'
The first option is an absolute url, but this also makes the code a bit less flexible (suppose you change the domain from localhost to something else). The second option is a relative URL, but one that is relative to the domain root of your web server (i.e. in the example it would still resolve to localhost/Controller...).
In both cases based on what you've posted, your PHP file should live in a Controller/ folder in the document root of your site. The structure of your code however suggests that you are using a framework of some kind (e.g. Zend, Symfony or CodeIgniter)? If that is the case it would be helpful if you post information on what framework you're using as well as that might change the answer.
UPDATE
In the case of cakePHP, you should access the controller through the front controller, meaning the URL should look like this:
url:'/posts'
UPDATE 2
For the jquery side, a complete ajax request example could look like this:
$(".idCheck").click(
function(){
var idVal = $(this).val();
$.ajax({
url:'/posts/update_checkbox',
data: {id: idVal },
type: 'POST',
success:function(result){
$("#dsa").html(result);
}
});
});
Note that the URL already contains the update_checkbox action (i.e. the complete url to the action you want to execute), and the data object contains the value of the clicked element that you want to send to the server. If you want to send a complete form you could also use $('#myformselector').serialize() to convert all inputs in the form to a object suitable for the data property of the ajax request.