Array Loop with Mysql Insert - php

Question

I have an array called $columns :
array(3) {
[0]=>
string(8) "Food"
[1]=>
string(6) "Calories"
[2]=>
string(3) "Carbs"
}
array(3) {
[0]=>
string(8) "Food"
[1]=>
string(6) "Calories"
}
Another called values
array(5) {
[0]=>
string(4) "'Fish'"
[1]=>
string(7) "'100'"
[2]=>
string(13) "'0'"
}
array(6) {
[0]=>
string(4) "'Tatoe'"
[1]=>
string(7) "'100'"
}
I have columns in my database that represent all possible columns that an array has.The arrays could have 5,6 more or less columns depending on the item.
I have this code that is suppose to generate the sql statement in this sense :
INSERT INTO MEALS (the columns in that array) VALUES (the values in the value array)
Here is the code :
for($i = 0; $i < count($column); $i++)
{
echo("INSERT INTO 'MEALS` ($column[$i]) VALUES ($values[$i])\n");
}
The problem is for each "MEAL":
n(per column) number of sql queries will be generated.
as such :
INSERT INTO `MEALS` (Food) VALUES ('Fish')
INSERT INTO `MEALS` (Calory) VALUES ('100')
INSERT INTO `MEALS` (Carbs) VALUES ('0')
Instead of it all being on the same query.
INSERT INTO MEALS (Food,Calory,Carbs) VALUES ('Fish','100','0')
So if i insert in the database, 3 rows will be created.
I know i am missing the logic, any help is appreciated

Answer 1

Why aren't you genererating the two parts of your query (1 variable for columns in insert and 1 variable for values) inside your array loop?
Once your loop is done, simply concatenate your strings :
$query = "INSERT INTO 'MEALS' (" . $var_column_list . ") VALUES (" . $var_values_list . ")";

Answer 2

$query = "insert into table(".join($colomn,','). ") values (\"".join($values,'","')."\")";
Try using variant of above according to your need

Answer 3

Try This....
$colums = implode(',', $array_of_colums);
$values = implode(',', $array_of_values);
$query = "INSERT INTO `tableName` (".$colums.") VALUES(".$values.") ";