http://jsfiddle.net/EWH8E/
I have some pages that include hidden content that is revealed when a checkbox is 'ticked' and hidden again when 'unticked'. Everything works perfectly in Chrome and FF, but I either get the content always showing or hidden but the checkbox doesn't work in IE.
I am using Ie8, but have tried in 9 also and the same happens. ANy suggestions as to how to get it to work? I included the following in the HTML head section to counter the use of the article element.
<!--[if lt IE 9]>
<script src="http://html5shim.googlecode.com/svn/trunk/html5.js"></script>
<![endif]-->
Now here is the PHP code
echo "<div class=\"resultsContainer\">";
echo "
Recent Results
<article class=\"small\">
<table class=\"results\">";
$query2=$database->query("SELECT team_name, team_score, opposition_score,
opposition_name from results_a ORDER BY updated DESC LIMIT 0, 5");
$i=0;
while ($row2=$query2->fetch(PDO::FETCH_NUM)) {
echo ($i %2 == 0)? "<tr class=\"stripe\">" : "<tr class=\"nostripe\">";
printf ("<td>%s<td class=\"small\">%s<td class=\"small\">%s<td>%s</tr>",
$row2[0],$row2[1], $row2[2], $row2[3]);
$i++;
}
echo "</table>";
echo "</article>";
echo "</div>";
And the CSS
.resultsContainer article {
background:white ;
overflow:hidden ;
height: 0px ;
position: relative ;
z-index:10}
.resultsContainer input:checked ~ article.small {
height:100% ;
width: 100% }
.results {text-align: center ;
table-layout:fixed ;
margin-left: 0 ;
margin-right: 0 ;
padding-top:0.7em ;
width: 65% ;
color:#0431B4 }
The :before selector is not supported in IE versions earlier than 9.
Your best bet for browser support is to use javascript instead.
All you have to do is bind an event listener to the checkbox. So when you click it, you can either directly change the width and the height or just use toggleClass().
$( "YOUR CHECKBOX ID OR CLASS" ).change(function() {
$( "ID OR CLASS OF ITEMS YOU WANT TO DISPLAY" ).toggleClass( "ACTIVE CLASS NAME" );
});
Or if you just set those elements to display: none; then you can do
$( "YOUR CHECKBOX ID OR CLASS" ).change(function() {
$( "ID OR CLASS OF ITEMS YOU WANT TO DISPLAY" ).toggle();
});
Although these answers seem similar, they are very different. Be sure to know the difference.
Related
I'm currently developing a simple web page that enables the user to: upload an image and a corresponding caption to a DB, let the user view the images and delete them.
I have already accomplished the first two with the following code:
<?php
#include_once("connection.php");
$db = new mysqli("192.168.2.2", "root", "", "proyectoti");
if ($db->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}
echo "Información de servidor: ";
echo $db->host_info . "\n";
// Initialize message variable
$msg = "";
// If upload button is clicked ...
if (isset($_POST['upload'])) {
// Get image name
$image = addslashes(file_get_contents($_FILES['image']['tmp_name'])); #$_FILES['image']['name'];
// Get text
$image_text = mysqli_real_escape_string($db, $_POST['image_text']);
$sql = "INSERT INTO images (image, image_text) VALUES ('{$image}', '{$image_text}')";
// execute query
mysqli_query($db, $sql);
}
$result = mysqli_query($db, "SELECT * FROM images");
?>
<!DOCTYPE html>
<html>
<head>
<title>Proyecto TI | Sube imágenes</title>
<style type="text/css">
#content{
width: 50%;
margin: 20px auto;
border: 1px solid #cbcbcb;
}
form{
width: 50%;
margin: 20px auto;
}
form div{
margin-top: 5px;
}
#img_div{
width: 80%;
padding: 5px;
margin: 15px auto;
border: 1px solid #cbcbcb;
}
#img_div:after{
content: "";
display: block;
clear: both;
}
img{
float: left;
margin: 5px;
width: 300px;
height: 140px;
}
</style>
</head>
<body>
<h1>Proyecto TI | <a> Interfaz </a></h1>
<div id="content">
<?php
while ($row = mysqli_fetch_array($result)) {
echo "<div id='img_div'>";
#echo "<img src='images/".$row['image']."' >";
echo '<img src="data:image/jpeg;base64,'.base64_encode( $row['image'] ).'"/>';
echo "<p>".$row['image_text']."</p>";
echo "</div>";
}
?>
<form method="POST" action="index.php" enctype="multipart/form-data">
<input type="hidden" name="size" value="1000000">
<div>
<input type="file" name="image">
</div>
<div>
<textarea
id="text"
cols="40"
rows="4"
name="image_text"
placeholder="Di algo de esta imagen ^^"></textarea>
</div>
<div>
<button type="submit" name="upload">Publicar</button>
</div>
</form>
</div>
</body>
</html>
It looks like this:
Now, the only part I'm missing is being able to delete an image (basically I only echo each image), how would you suggest for me to accomplish this, to make each item clickable and let's say, pop up a dialog or button to perform an action (delete from DB).
I really don't know much about PHP or CSS/HTML, any help would be much appreciated, Thank you!
Within this loop:
<?php
while ($row = mysqli_fetch_array($result)) {
echo "<div id='img_div'>";
#echo "<img src='images/".$row['image']."' >";
echo '<img src="data:image/jpeg;base64,'.base64_encode( $row['image'] ).'"/>';
echo "<p>".$row['image_text']."</p>";
echo "</div>";
}
?>
Personally I would add an element to click on - like an 'x' or whatever - with a unique data attribute:
https://www.abeautifulsite.net/working-with-html5-data-attributes
You have to add the unique id of the image obviously, so you can let SQL know which row to delete... Like this:
echo "<div class='delete-image' data-id='" . $row['id'] . "'>x</div>';
Then I would link this class to an AJAX call to make an asynchronous request to the server and delete the image without reloading the page. It's not very hard.
An easier solution would be to create a new form in the loop, so you create multiple forms per image, add a hidden field with the image id in the form and make a submit button with the valeu 'delete' or simply 'x'.
The same way you created the check:
if (isset($_POST['upload'])) { ... }
You can create something like this:
if (isset($_POST['delete-image'])) { ... }
You will be carrying the image id value like a normal form input. And you can do whatever you want with it.
I would HIGHLY suggest you to look into how to work with jquery and ajax calls though.
Opening a dialogue and ask the user before he deletes an item will require that you either go another page for deletion or use javascript for this.
In both cases, you should somehow set an identifier for your image in your html-code.
I would suggest you give every image an id
'<img ... id="'.$yourImageId.'">'
or a data-attribute
'<img ... data-identifier="'.$yourImageId.'" >'
with that identifier.
First variant:
...
echo '<a href="/path/to/delete/view/page.php?image=yourImageId">'
echo '<img ... id="'.$yourImageId.'"/>'
echo '</a>'
...
and on this delete-view-page, you just have a form that triggers your delete-code
<form action="/path/to/delete/view/page.php" method="POST">
<input type="hidden" name="id" value="<?php echo $yourImageId ?>">
</form>
<!-- after this, react with $_POST['id'] --> to the id sent to the server side and delete the image in your database -->
The other way is not server side rendered.
You should give your Elements some class like "my-clickable-image".After that, you have a script on your page, that looks something like the following
<script>
/* get your images with querySelectorAll, the . stands for class and after that your name */
var clickables = document.querySelectorAll(".my-clickable-image");
clickables.foreach(function(image){
// say that for each image, when clicked the generated function is called image.addEventListener('click',generateShowDialogueFunc(image.getAttr("id")));
});
// generate a function(!) that reacts to an image being clicked
function generateShowDialogueFunc(imageIdentifier){
// return a function that adds a Pop Up to the page
// the Pop Up has approximately the code of the first options second page
// except that now, it must create and remove elements in javascript
return function createPopUp(){
removePopUp();
var popup = document.createElement("div");
popup.setAttribute("id","deletePopUp");
var deleteForm = document.createElement("form");
deleteForm.setAttr("action","/path/to/file/that/deletes/given/query.php?id="+imageIdentifier);
var deleteContents = '<p> Do you want to delete this image? </p>'
+ '<button type="submit"> yes </button>'
+ '<button onclick="removePopUp()"> no </button>'
deleteForm.innerHTML = deleteContents;
document.body.appendChild()
}
}
// remove the Pop Up that can be used to delete an image from the page
function removePopUp(){
var existingPopUp = document.getElementById("deletePopUp");
if(existingPopUp) document.body.removeChild(existingPopUp);
}
</script>
<!-- just add some styling to make the popup show on top of the page -->
<style>
#deletePopUp{
width: 50vw;
height: 50vh;
position: absolute;
z-index: 1;
padding: 1em;
}
</style>
In this case, you just call the server to delete the image, not to show the delete form.
I would suggest the second one but stack overflow is not made for opinion based answers.
Regarding simple security:
It looks like your users could give titles or texts to images.
try what happens if a user gives a title like <bold>some title</title>
and guess what would happen if the title is <script>window.location.href="google.com"</script>
(XSS * hint hint *)
Regarding code structure:
If you want to do something like web development more often, think about separating your database accessing code, and your logic code from your php page template code, this is called 3 tier architecture and standard for bigger projects but i guess this is really just a first, short prototype or test.
I want to get rid off small dots that appear when I use max-width (see // for details).
Here's my php that shows a messeage saved in session:
<?php
echo "<table id='delpos'>";
echo "<td id='del'>" . $_SESSION["del"] ."</td> ";
echo "</table>";
?>
And css that doesn't show background-color (until session exists) by using max-width + max-height :
<style>
#del {
background-color:red ;
color:white;
max-width:20px;
max-height:6px;
overflow:hidden; // tried using this to hide the small "red" dots...
}
#delpos {
margin-top:60px;
margin-left:30px;
position:absolute;
}
</style>
Please help:)
I have done some research to find a way to use a link to expand/collapse some content. I can't see any problems with my code, but the link does nothing.
HTML code ;
echo "<div>";
echo "[Results]";
echo "[Results]";
echo "<table class=\"results\">";
Followed by php to populate table, then close the table and div.
CSS
.results, .show {display:none}
.hide:focus + .show{display:inline}
.hide:focus {display:none}
.hide:focus ~ .results {display:block ;
width: 20em;
margin-left: auto ;
margin-right:auto}
I am brand new to php and a beginner with jQuery. I have a php page that is populated with data from a mySQL table. What I am trying to achieve is for the h3 that contains "View Job" to have a unique id assigned to it, as well as the div that prints out the job description. Then, I would like to reference these with jQuery so that if someone clicks View Job, only the description for that job will show. I hope this makes sense.
I tried this with classes and of course all the job descriptions revealed themselves when any View Job was clicked.
I tried the solution here, but this ended up with 36 "View Job" links on my page, and I need to assign the unique ID to the h3 and div as they are created.
I am open to suggestions for another way to achieve what I'm looking for - basically to hide/collapse each description as the user clicks on View Job for each job.
here is my code:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<style type="text/css">
.job-post{border-bottom: 1px solid red; padding: 0; margin: 10px 0;}
h3, p{padding: 0; margin:0;}
.view-job{cursor: pointer;}
</style>
<script type="text/javascript">
$(document).ready(function() {
$("div#job-details").css("display" , "none");
$("h3#view-job").click(function() {
$("div#job-details").css("display" , "block");
});
});
</script>
<?php
// Connects to your Database
mysql_connect("xx", "xx", "xx") or die(mysql_error());
mysql_select_db("lcwebsignups") or die(mysql_error());
$data = mysql_query("SELECT * FROM openjobs")
or die(mysql_error());
?>
<div id="job-container">
<?php
Print "";
while($info = mysql_fetch_array( $data ))
{
Print "<div class='job-post'>";
Print "<h3>Position / Location:</h3> <p>".$info['jobtitle'] . ", ".$info['joblocation'] . "</p>";
Print "<h3 id='view-job'>View Job:</h3> <div id='job-details'>".$info['jobdesc'] . " </div>";
Print "</div>";
}
?>
</div><!--//END job-container-->
Assign the classNames instead of id's
Then use the this context to select your div which will only search for the one in the context and not all the divs
$("h3.view-job").on('click',function() {
$(this).next("div.job-details").css("display" , "block");
});
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<style type="text/css">
.job-details{display:none;}
.job-post{border-bottom: 1px solid red; padding: 0; margin: 10px 0;}
h3, p{padding: 0; margin:0;}
.view-job{cursor: pointer;}
</style>
<script type="text/javascript">
$(document).ready(function() {
// Please hide this class on CSS
// $("div.job-details").css("display" , "none");
$("h3.view-job").click(function() {
// you ned to use this keyword
// it is very important when you use javascript or jquery
// this keyword only pick element on which you click
$(this).parent().find(".job-details").show();
});
});
</script>
<?php
// Connects to your Database
mysql_connect("xx", "xx", "xx") or die(mysql_error());
mysql_select_db("lcwebsignups") or die(mysql_error());
$data = mysql_query("SELECT * FROM openjobs")
or die(mysql_error());
?>
<div id="job-container">
<?php
// First of all Please use echo instead of Print
echo "";
while($info = mysql_fetch_array( $data ))
{
echo "<div class='job-post'>";
echo "<h3>Position / Location:</h3> <p>".$info['jobtitle'] . ", ".$info['joblocation'] . "</p>";
// you can't use id multiple time in a same page so instead of id use Class
// if you want to use id then you have to generate uniq id
// check below I generate id --> I don't know your database field that's why I used jobId
echo "<h3 class='view-job' id='job".$info['jobId']."'>View Job:</h3> <div class='job-details'>".$info['jobdesc'] . " </div>";
echo "</div>";
}
?>
</div><!--//END job-container-->
This should do what you want (tested okay). Just replace your mysql login info and the example should work.
I completed your job-details div (it was missing the data from php), but what you were really looking for is the jQuery code.
When an <h3> tag whose id begins with the characters view-job is clicked, the jQuery click event handler will:
re-hide all divs whose id starts with the chars job-details
display the next div in the DOM tree
CODE:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<style type="text/css">
.job-post{border-bottom: 1px solid red; padding: 0; margin: 10px 0;}
h3, p{padding: 0; margin:0;}
.view-job{cursor: pointer;}
</style>
<script type="text/javascript">
$(document).ready(function() {
$("div[id^='job-details']").css("display" , "none");
$('h3[id^="view-job"]').click(function() {
$("div[id^='job-details']").hide(500);
$(this).next('div').show(500);
});
});
</script>
<?php
// Connects to your Database
mysql_connect("xx", "xx", "xx") or die(mysql_error());
mysql_select_db("lcwebsignups") or die(mysql_error());
$data = mysql_query("SELECT * FROM openjobs") or die(mysql_error());
$data = mysql_query("SELECT * FROM openjobs") or die(mysql_error());
?>
<div id="job-container">
<?php
echo "<br>";
while($info = mysql_fetch_assoc( $data )) {
echo "<div class='job-post'>";
echo "<h3>Position / Location:</h3> <p>".$info['jobtitle'] . ", ".$info['joblocation'] . "</p>";
echo "<h3>View Job:</h3> <div id='job-details'>".$info['jobdetails']."</div>";
echo "</div>";
}
?>
</div><!--//END job-container-->
can someone tell me how to create a nice small tooltip like ajax pop-up ?
the situation is like this,
I am pulling the $row->title from the db, and then I presented it as a link like this
<?php foreach($task->result() as $row): ?>
<tr>
<td><a href=#><?php echo $row->title; ?></a></td>
</tr>
<?php endforeach; ?>
when a random user clicks that link, I want it to produce a small pop-up or tooltip like stuff that contains the title's description $row->description , and when user moves mouse from it,it closes. i know its possible, but i just don't know how to do it.
You need jQuery. Add stylesheet into <head></head> and javascript to any place in your page.
Sample style:
<style type="text/css">
.description {
visible: hidden;
position: absolute;
left: 0px;
top: 0px;
/* View */
font-family: Arial,Tahoma,Verdana;
font-size: 8pt;
color: #bbb;
background-color: #444;
padding: 5px 7px;
border: 1px solid #222;
}
</style>
Javascript:
<script type="text/javascript" src="path/to/jquery.js"></script>
<script type="text/javascript">
$(document).ready(function() {
// Add listener to links
$(".some_class").click(function(e) {
var description = $('<div class="description">'+ $(this).attr("description") +'</div>');
$(this).append(description);
description.css("left", e.pageX-4);
description.css("top", e.pageY-4);
description.animate({ opacity: 'toggle' }, 400, 'linear');
// Remove description, if user moved the mouse cursor out description
description.mouseout(function() {
$(this).remove();
});
return false;
});
});
</script>
Change your code:
<?php foreach($task->result() as $row): ?>
<tr>
<td><?php echo $row->title; ?></td>
</tr>
<?php endforeach; ?>
But the better way is to check out some good jQuery plugin..
Check out this jQuery plugin: http://www.w3avenue.com/2010/01/11/coda-bubble-jquery-plugin/
something like the following?
AJAX to get the description and when you're received the response create the description 'box'
var tipel = document.createElement('div');
tipel.innerHTML = descr;`
add it to the page
var bodyel = document.getElementsByTagName('body').item(0);
bodyel.appendChild(tipel);`
and position it like:
tipel.style.position = "absolute";
tipel.style.top = newfntogetabsolutecoord_top(document.getElementById("mytitleelement"));
tipel.style.left = newfntogetabsolutecoord_left(document.getElementById("mytitleelement"));`
getting absolute coords of an element can be tricky, look for a fn online.
for closing the tip, a suggestion would be placing tipel just under the mouse pointer (you already know it's over the link "mytitleelement", just shift the tip a little in the lines above), and then add an onmouseout event function to tipel that:
tipel.style.display = "none"; //hides or
tipel.parentNode.removeChild(tipel); //removes it from the page
(you might get away with using this instead of tipel in those 2 lines)